Oh my god , I really don’t know how to thank you, you are an amazing teacher!!! It’s unbelievable how you make everything understandable! Thank you so very much from the bottom of my heart ❤️ you can’t imagine how much you helped me.
At time stamp 11:01 you said the 6th carbon reacts with the 2nd carbon to form a 5-membered ring instead of saying a six-membered ring that is written on the whiteboard. Just wanted to mention that so nobody gets confused :)
Dear Sir your handwriting is so neat! but could you please explain why the anomrs e in a ratio ogf 66:33:1 and not equally shared like 49:49:2? Thank you.
If you put them both into a "chair" conformation, the Beta-D-glucose would have all -OH groups equatorial, and the alpha-D-glucose would have axial -OH groups. Therefore, the Beta form is more stable because of sterics.
