Leah you are saving me once again. You were my #1 source in undergrad for organic chemistry 2 and literally helped me get an A in that course. I am now studying for my MCAT and for a biochem class coming up this coming semester. I knew I could come to you for clarifications. Thank you so much for everything!
Hii miss, thank you for the video, it's really really helpful!! :) I'm very grateful that I can find your channel.. Miss, if I may ask.., in the end of your video, you gave an example if the reaction go with an acid (H3O+). The H2O atacks the C carbonil, and the one H make a new bond with N. But the result, the C carbonil only change into R - COOH form, my question is why doesn't it make R - COOH2 form..? I'm confused because the molecule that attacks C carbonil is H2O which it has two H, then why in the result, there is only one H (R-COOH), not two H?? I really hope, I can get your answer, I'm waiting for it :) Thank you..
That's an excellent question! I didn't draw the full mechanism here, but another water molecule in solution would have to deprotonate the attacking water to regenerate the acid catalyst.
Sorry, I’m not sure I understand your question. By 2 proteins, do you mean a dipeptide containing 2 amino acids? And if it hydrolyzes to produce identical amino acids, they should not be different.
I'm sorry, but I don't offer tutoring over social media. For help with questions like this and more, I recommend joining the MCAT Study Hall. For more details, visit join.mcatstudyhall.com/ or contact me through my website leah4sci.com/contact/
I'm sorry, but I don't offer tutoring through RU-vid comments. For help with questions like this and more, I recommend joining the MCAT Study Hall. For more details visit join.mcatstudyhall.com/ or contact me through my website leah4sci.com/contact/
No disrespect but a protonation on an amide would almost certainly not Happen on the nitrogen but rather on the oxygen. This is because the nitrogen gives away its lone elec pair for the delocalization in the amide and it is therefore not available for basic reactions
Plus when the nitrogen is protonated the favourable delocalization can't Happen (obviously) thus having an energy loss. Clayden describes this particular phenomenon even with MO Diagramms