A bit of background on this puzzle: it was originally a practice round for a Speed Setting Championship on Discord, where I was encouraged to try out unfamiliar constraints. The puzzle you're seeing here is quite different from this practice round. I liked the break-in pattern with the 19 cages, and then the interactions with the 15/4 cages, so I decided to work on a polished version of the puzzle.
@@ZeAgentboo Please correct me if I'm wrong but the 1 in box 8 is unresolved in the solution as it should be doubled and accompanied by a 6 to sum to 8. If Simon's solution is the intended solution then I suppose just changing the cage to a 9 would suffice as a fix. Otherwise, I reached a point with all the boxes fulfilled but multiple sudoku solutions
I love yelling at Simon from the future. It makes me feel smart that I see something he doesn’t when, in reality, I don’t even know where to start any of the puzzles he does on the channel. 😂
right there with you but I could not restrain myself about that 10 clue in box 5. He hovered the pointer over it, said maybe he should check all the clues, then checked every single clue except that 10 in box 5. I was pulling my hair out.
Often it's so funny. I feel very proud when I see some very obvious thing Simon is overlooking for half an hour. At the same time I don't even know how to break in while Simon spots the difficult things with his eyes closed LOL.
13:38 These are the moments why it's funny to have done these puzzles and still watch the video afterwards. Simon ponders the puzzle and says: Yes, ahh... No, well yes actually, or is it? Yes, it is. Having done the same logical steps I was able to understand fully what he was thinking about even though what he said was completely unspecific.
I always love when Simon reminds us that we're his favorite people should he get the chance to reveal the triangular number of the square of the second prime.
1:06:45 "I DON'T KNOW WHAT I HIT THERE" You hit the left mouse button twice, too close together. Doesn't matter that you did separate actions (selecting two cells) before clicking the second time. The operating system (with its double click speed setting) detected a double click and sent that information to the browser which the software interpreted as "select all green cells".
It probably didn't help that Simon had it wrong for most of the video. He shortcut some logic by thinking that a doubled index cell didn't change what it indexed to. He's going to have to figure it out eventually, because the solution relies on it. But I haven't got to that part of the video yet.
35:34 Simon pointing out the relationship between r1c3 and r9c1 at this point had me thinking "The enemy of my enemy is my friend." I then went off on a tangent thinking about a recent workplace dispute between two co-workers recently. Sudoku is life people. Every so often I get the feeling that the numbers are alive and they are speaking to us.
Had not the greatest day today, to stay polite, but knowing there'll be a cracking the cryptic video to watch before bedtime kept me sane during the day - already feeling better after just a few minutes into the video, thanks Simon ♥
62:33 The 14/15 cages interactions with the 19 cages was a thing of beauty and the joy never stopped. Intriguing rule I hadn't seen before, but enjoyed and would love to see again.
I absolutely love how Simon solving this sudoku's, it's so lovely how he could see hardest itterations, but sometimes miss easier ones or when he jumps from clue to clue sometimes he forgets to return to half resolved ones and miss some digits.
55:58 “I’ve still got two clues that I haven’t investigated…” I’d revise that count… (The 10 clue in box 5 I think gets ignored here because it has a digit in it, but is still unfinished and indeed forced in a very useful way)
Nice puzzle Agent, and Simon's solve was fun to watch.. I didn't have any issues with the Remote Sums clues, until I had to think about the doublers which might as well be kryptonite. I keep thinking modifers will just click in my mind sooner or later... I enjoyed figuring out all the twists and turns in this one nonetheless!
Simon not realizing that he'd not finished that 10 clue was driving me bonkers... but made me feel better about my own mistake where I indexed the doubled 1 clue to make a 6 one square away instead of the proper 2.
hi Simon, I just want to say when you start playing that guitar I get such a joyous feeling. Your videos are one of my favourite parts of the day and the best surprise when there’s a guitar segment.
16:45 even if there had been overlap, the overlap position wouldnt be at an equal distance from the 19-cells. And since the cells sums to the same sum, the overlapping cell would therefore need two different sums for the overlap to work.
_"...but we could put [there] a _*_doubled_*_ 1"_ (Simon @9:54) Correct terminology 😏👍 _"One of the numbers must be 10 or greater and therefore it is _*_a doubler"_* (Simon @11:37) Incorrect this time 😜 Digits are *doubled* (modified). Cells are *doublers* (modifiers). I loved Jay Dyer's videos about his unforgettable sudoku hunt, themed on different kinds of modifiers, where this was made crystal clear.
@16:44 very nice use of colours to show there is _"no overlap between the four doublers"_ 👏👏👏 Of course, since no *orange* cell is in the same *row* or *column* as another *19 cage,* by symmetry the same must be true for each of the other three sets. Hence, it is not strictly necessary to colour the other three sets. However, it is nice to see them all. More importantly, it makes crystal clear that the *14 cage* needs a doubler. 😏👍👍👍
@25:07 Even more beautiful is using pencilmarks to show the only possible doubled digit that each coloured cell may contain. It makes Agent's logic machinery crystal clear. 👏👏👏👏👏👏
Fantastic puzzle, which it felt immensely satisfying to finally conquer. It took me a very long time to realize the implications of the high doublers for the middle box.
There was never going to be any overlap 16:54 If two of the 19 cages would share a doubler, they values in these cages has to be the same as well, otherwise the won’t both add up to 19. But these values wouldn’t be the same, since the distances between the shared doubler and both of the cages aren’t.
i am alittle sad he did not notice round 36:40 that it did not matter where the double 5 goes the last 2 19 clues allways end up the same way that feels alot more beautiful then what he ended up doing
I didn’t completely understand why the 19 clues all have different digits due to non overlapping. Could someone please explain, so I get the logic behind that? Thanks in advance! Cheers 17:37
All of the numbers in the 19 clues must be odd. This is because of two reasons. 1: The doubled number must be in the target cell, not in the clue cell. This is because if the clue cell number was doubled, the distance to the target cell would also be doubled, which would put it outside of the grid. 2: Since the target number is doubled, it will always be even. Therefore the only way the sum of the clue cell number and the target number could be odd is if the clue cell number is odd. So given that, if you go through and highlight all of the numbers that could be target cells for each of the 19 clues, you'll find that there is no overlap. There are no cells that are an odd number of cells away from two or more of the 19 cells. Therefore, all 4 of them must point to different target cells.
Anyone else shouting Look at the 10, Look at the 10 at around 56 minutes as Simon insists on going through the other clues first? Then as he checks all the clues to see if he has done what he can with them, and completely misses the 10 clue!!
welp, I'm giving up after 71 minutes. I thought I broke it when I got to the 15 cage and watched the video to be taught that I can use the same double digit for two different clues, I broke the solve somewhere in the middle and looked to see how much I had to undo (the 4 cage in the lower left), and I was told my solution was incorrect at the end. Looks like I put a 6 in r1c1 forgetting that the 4 in r1c9 actually had a value of 8.
The doubler acts as a doubler for everything. So although the value written is a 4 it still acts as an 8 so it needs a 2 8 cells away which it gets in R1C1
@@coreycadile2585 Simon kept mixing that up all the time as well though. Sometimes in direct succession, eg. when he checked the possibilities for R1C9 after determining that it was a doubled 2, 3 or 4 he looked for the 6 only 2 steps away (missing the doubling), then immediately after for a 4 at 6 steps away (as it should be with a doubled 3).
Uh oh ... I landed on a deadly pairing at the end of this solve ... looks like there are actually two solutions to this sudoku. Anyone else encounter this?
Yes I’m only 20 minutes in, but how is the center digit absolutely a 4, with a doubled 5 when it’s possible to be a 2 with a doubled 6??? They both make 14
Also, the 4 cells he immediately said had to be a 1357 with a doubled digit doesn’t make sense because the cell itself could be the doubled digit with the 1357 existing outside of the cage.
What frustrates me so much is sometimes it feels like he guesses or assumes something to be true because he either hasn’t seen or at least hasn’t mentioned alternatives. So he continues on with the assumption and yet it’s always gets solved! How could I ever learn to solve such a puzzle?? I won’t be able to make guesses or assumptions like this.
@@orionSquared I feel like you didn't really listen to the video or you misunderstood the rules. Nothing about this is a guess, but I've seen a lot of people miss that the doubled digits also need to have double their distance, so you're not alone. The 1357 is correct, because if you double the cell itself it points to something outside the grid: Even if you were to point to something as high as 9, it would still need to be 10 (or double-5) away. The 4 is correct because each doubled digit only exists once in the puzzle. As you can see by the early coloring in the video the possible positions of the doubled 6 (which is required for the 7) of the 1357 quadruple and the doubled 6 of the middle cell could not overlap, which means the middle cell cannot take a doubled 6 as well.
@@BrinaaSM Ah, I did misunderstand that. I did not realize that I had to double the length away from the doubled cell. So the cells HAD to be an odd number, because if it were a doubled even, it'd have to be 4 or less (because the max distance is 8) and then the odd digit would have to be an 11 at least, which obvi won't work. Gotcha, so it does have to be a 1357 quadruple. Which means it has to have a doubled 6, so the middle cell DOES have to be a 4 with a doubled 5. Ok, I get it now. I did remember that there could only be 1 unique digit per doubled cell, but it was the 1357 that was throwing me off, because I was convinced it didn't HAVE to be a 1357, but could be any doubled even digit with an odd number in the corresponding cell. But it can't. Thank you, that was really helpful. I appreciate it. :)
There's that "in a moment or twos time," (instead of "in a moment"). Whose "time" is it? It's "twos time." Simon, just go back to saying "in a moment or two." That's all lol 😆
