holy cow I spent days trying to understand this using every resource I could find and still didn't understand it but came across your video and I NOW UNDERSTAND IT THANK YOU!!!!!
Sir can u please do one video for Experimental procedure for measuring the rate of reaction which involves a gas being evolved . If u r busy then it's fine.
Abu Bardewa I can't do it for tomorrow, I'm afraid! In a situation like that, you would want to use a gas syringe, and measure gas at intervals. From that you could work out a rate of reaction.
You are just God sent. Thank you so much. May God bless you. You actually make chemistry interesting and fun, without you I would have probably failed.
I've been so scared of this topic up until now, it's literally been giving me nightmares since my teacher taught it us and all of a sudden i understand and i don't quite know how to react
*delightful, absolutely delightful. I finally understand this bs :)* Edit: Btw i wrote that b4 watching the vid - that’s how certain i was, and your’s truly wasn’t disappointed in the slightest 😇 😊 😂
It's worth to know that fluorine reacts distinctively with alkanes: CH4 + 2F2 = C + 4HF, while iodine doesn't react at all. But, it's some kind of rule that chlorine and bromine shows similar properties, when fluorine and iodine differs significantly from these two halogens.
You are my savior THANK YOU SO MUCH FOR THIS VIDEO Also I have a question, I do AQA chemistry but in my notes from my teacher she's written, "Why is Cl. + Cl. = Cl2 NOT a termination step?" Could you explain why it wouldn't be a termination step please?
Thanks very much! Yeah, the aim is to get the alcohols topic covered this Sunday along with equilibria. The alcohols topic will include the classes as well as the oxidation of the alcohols and tests for products.
Thanks, I think I finally have the Free radical Substitution mechanism in my head now. Just a question, you said that the dot (for free radical) had to be next to the carbon, on my course guide, the Dot is on the right next to the H atom like this CH3', is that wrong? (i couldn't find a dot in the middle so i had to use an apostrophe)
Boro Jen xX Sorry I'm late to the party on this, it was put into spam! The dot certainly should be next to the carbon as it is from the covalent bond that was there!
In my textbook it says that the ozone is created via O2 + hv ---> O. O. then O2 + O. ----> O3. But I don't understand how a free radical just adds to the O2 to make it O3. I guess i'm probably being stupid by attempting to keep to the octet rule from gcse, but i'm just curious.
Hi, in my cgp book it says CFCs are halogenoalkane molecules where all of the hydrogen bonds have been replaced by chlorine and fluorine atoms. In other words, they have no Hydrogen atoms in them. But your example of CHClF2 has a H atom. Sorry I am just confused, did you do it by mistake or is my book wrong?
Ok so you said that in chlorofluorocarbons the C-F bond can't be broken because it is too strong and hence the C-Cl bond is broken by the UV light So I have two questions: When the C-Cl bond is broken by UV light is it still homolytic fission? I'm assuming the Cl gets one electron and the carbon compound gets the other. If we had a bromocarbon compound in the atmosphere, is it possible to break the Br-C bond since that bond would be weaker than the C-Cl bond?
Thank you so much for your videos!!!!!!! Only problem now.... I can't find a set of Physics videos as good as your Chemistry ones! Anyone have any ideas?
You said that when we are dealing with molecules we must put the dot (free radical dot) on the starting point of the molecule. But, the reaction at 15.50 you gave the free radical dot on the ending side. Is it that you have put that out in mistake,or this is a special case.please le t me know! Thank you!
+Au Rora The Cl2 is there from being initially added! I would assume it is Cl2 that hasn't been broken into radicals or some that has formed from 2 chlorine radicals reacting.
Thanks! The reason that the C-H bond doesn't break is that the energy required to break it is too high. If you look on a table of bond dissociation enthalpies, you'll see that the C-H bond has a value of around 413 kJ/mol which compared to around 330 kJ/mol for the C-Cl bond, is higher. Does that make sense?
Hi! Once again a really good video. I do have a quick quetion though. When you look at the ozonethe Cl free radical rips a oxygen off O3, why is it still a free redical then? Isnt the whole point of it ripping a oxygen off to stop it being a free radical. Maybe i got this all wrong but can you explain please. Thanks!
What he is asking is Cl radical reacts with ozone to give ClO radical... Isnt the point of a radical reacting so it no longer remain a radical?? (first equation of the degradation of ozone)
Becky Donaldson I'm not sure - possibly! I know I made a mistake with saying that there are hydrogens in CFCs, but you do get HCFCs and as far as I am aware, these still contribute to the degradation of the ozone layer...
Hi and thanks! What do you want from the alkanes, alkenes and alcohols? I've already done electrophilic addition which comes into the alkenes chapter (it also kind of includes elimination, I guess). I'm yet to do a general alcohols one and a general alkenes one, but they're on the cards for the future! There's not really a lot on the alkanes in general terms besides fractional distillation. Is that what you mean?
Have you taken down the videos on DNA and NMR spectroscopy, I find your other videos extremely helpful and would love to know if you have any on the final topics in paper 2.
Sir, at 15:03, why is the single unpaired electron attached to the oxygen and not the cl? i thought the "dot" should always be on the left when dealing with compounds?
Rangahatimuhmon It isn't as simple as saying that the dot should go on the left. When dealing with a radical such as the methyl radical, the dot would go next to the C, which would be the left, because this is where the unpaired electron is found. In the case of the ClO radical, the unpaired electron is found on the oxygen, hence the dot being drawn there. If you look at the bonding in the ClO radical, you'll see that the oxygen has that unpaired electron. Does that help at all?
I thought that CFCs contained no hydrogen as CFCs are halogenoalkanes where all of the hydrogen atoms have been replaced by chlorine and/or fluorine atoms?
When dealing with a radical such as the methyl radical, the dot would go next to the C, which would be the left, because this is where the unpaired electron is found. In the case of the ClO radical, the unpaired electron is found on the oxygen, hence the dot being drawn there. If you look at the bonding in the ClO radical, you'll see that the oxygen has that unpaired electron. Does that help at all?
Hello Antonio, I have covered a video answering an exam style question on this topic which you may find useful: ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-D9Vj4saGofE.html
Yes, ultraviolet light (UV) is the essential condition in order to produce the free radical in the initiation stage. Feel free to check my channel out and subscribe as I cover a level chemistry exam questions. Here is my video on this topic: ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-D9Vj4saGofE.html
John Paterson I would love to do that! BUT, I have no idea how to. Plus, I think to make an app for the App Store you need to make it on a Mac. And I am not getting a Mac. Can you make apps?!
Alias DMG No, you don't need to. With an alkane, you're normally OK to write it as I have done as there's not really any confusion that could come from it. However, if you were looking at ethanol and you wrote it as C2H6O, that would be wrong as you haven't shown that it has an OH group present.
