Bandwidth - AOL gain slew rate

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Learn more about the TI Precision Labs - Op Amp Evaluation Module used in the hands-on lab modules
www.ti.com/tool/ti-plabs-amp-evm
This is the fourth of five videos in the TI Precision Labs - Op Amps
curriculum that addresses operational amplifier bandwidth. In this training,
we’ll cover 5 bandwidth related topics:
1) A deeper look at how the slope of the Aol curve affects gain bandwidth.
2) How an op amps input capacitance can limit the bandwidth.
3) How to calculate the practical gain verses frequency for amplifier
circuits.
4) How to limit the bandwidth of a circuit on purpose using a feedback
capacitor .
5) How slew rate can affect the response over frequency.
Download the TINA-TI Spice Models for our video exercises
www.ti.com/lit/zip/SBOMBR7
Download and install TINA-TI, the preferred simulator used exclusively with TI Precision Labs - Op Amps
www.ti.com/tool/tina-ti
Download the Analog Engineer's Pocket Reference e-book
www.ti.com/amplifier-circuit/...

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Опубликовано:

13 июл 2024

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Комментарии : 3

@shuvodas2 Год назад

14:14 Why the output achieves 5V peak when 10V peak input is fed? In previous page, the max peak output was calculated to be 3.183V. So, output peak should not be around 3.183V?

@mansionese 9 месяцев назад

Understand the previous page first bruh. the output only made 5Vpk *_(traingle wave)_* is because the OpAmp don't have enough Slew Rate (power bandwidth) to make 10Vpk sinewave. Simply put; the opamp can't deal that input signal, so the output become greatly distorted.

@arx_wtf 8 месяцев назад

I have the same question, and my guess is this: the calculated value of 3.183Vp is "max output voltage without slew-rate induced distortion" (see the graph), not the maximum output voltage the opamp will produce. It was supposed to produce 10Vp of output voltage, which is more than the 3.183Vp distortion-free maximum, thus it produced distorted waveform with 5Vp (a number which is not calculated anywhere).