I didn't search too much but I really like to know this teacher's name. He's awesome. He knows how to make you understand not only the basics but he's making you think everything around you using simple examples. Great job sir.
He teaches at Mt Druitt TAFE. I won't tell you his name as It's not up to me give that info out. But he is good at what he does. I did a diploma course under him in 2013.
This is the best shear force and bending moment explanation on you tube. thank you very much. Could you please upload SF & BM analysis using ANSYS. I would really appreciate it.
Its good to see that Carl Barron has another job outside of comedy. Well done Carl and who knew you had so much to offer in engineering. Loved your last special by the way.
Wow, I've watched a few of his videos now and this man is a great teacher. I wish he had full courses available on here, I think they'd be some of the best ones on RU-vid.
I have been struggling for 2 months watched so many examples and still couldnt understand, my professor told me I should go back and repeat modules "very encouraging" when you have to do multi jobs to pay tuition, just because he couldnt explain to me. Thank you for helping me understand,you have no idea how simple you made this look.
Fair play...Ive just completed a HND in Civil Engineering and with all the things you have to take in its very easy to forget some things, I never entirely got it the first time round in University...but this is an easy to follow and well explained example. You have put some good effort in to the production of a simple and not overloaded with snippits of information(experience). As when a student is making notes or trying to visualize what is happening, often it is hard to keep up with the visualisation of what is happening compared to how fast the lecturer is speaking. Well done on this video. Cannot wait to check out the rest. Thanks.
you're the best teacher on the internet I've come across. thank you for clearing my concepts better than my college teachers. The way you practically demonstrate the concepts is a treat !
Sir , thank u very much for making the subject such clear and easy. When a section is under tension stress we consider the forces postive though it act in opposite directions , so both bending arrows were postive too as u wrote the first time. The case is different when we compare the signs of the external forces and the internal forces. Of couse their sum will be zero
This was incredible. I’m not an engineer but in woodworking and a timber framing I keep encountering these concepts but had no idea what they even meant. Trying to size a tenon or a beam will be a lot easier now thanks to your explanation.
Brilliant instructor, very knowledgeable. A fantastic resource for both Instructors and students. I do the same job but in England. If possible I would like to contact him to discuss the syllabus and compare it with the HND in the UK.
for the first time i understood shear force and bending diagram so easily it was just awesome this should be the way of teaching thanks sir for presenting this and hope we can get more like this
excellent class on bending moment .........this is the best class on you tube . I understand very well........THANK YOU VERY MUCH SIR...................................
Please show all the work done by Aneroid barometer and efficiency So what if we use steel plate 3 mm thick for making aneroid barometer cell cylinder. Having surface area one kilometers square kilometers ?
if you are saying the moments about "a" near 14:00 why are you saying that clockwise is positive when that particular direction is the negative direction in all other torque problems. counterclockwise is the positive direction which should have meant that 12x1 takes the positive value....
Amazing. The equipment you used to explain I really liked it. I make Civil Engineering lessons too and you inspired me so much sir. I will try to use this equipment. Kinda hard to find it readymade in market. But I will make myself Great sir. You're an inspiration
Why is the bending moment negative though? If I’m using the right hand rule I would get a positive value (thumb sticking towards me), so I shouldn’t the bending moment be positive?
I had some teacher which were just pathetic when it comes to express their ideas ..of course they have knowledge but their presentation was awful ,even they could not speak good english,and they dont care to improve their skills which is absurd..
Hello Sir, thank you so much for the video. It is easy to follow and understand. Just a question. A lot of my teachers keep telling to cut the beam to a distance. Do we always have to do this? It just makes it more confusing to me. Regards
You can also determine de equations of sheer (integration of sheer load), B.M. (integratin of sheer) and axial and plot. Should put always the unities in wich you abtain the results and even during calculus so people understand. Just saying...
@21:09 if we draw SFD with Fixed support of cantilever on LHS, the SFD is resulting in opposite shear force values (Positive shear force towards free end). Can u please explain?
If the bending moment for the sagging beam is 18kNm - what is the significance of that to a structural engineer ? For example, if the BM was 25kNm what is the affect? Does it mean the beam is stronger/weaker in comparison ?
Hi Helen: Bending moment is the intensity of applied load on a beam, so the engineer must design the beam to withstand the applied bending moment (by making it large enough). Regards Tim
It tells you how large the product of section modulus and allowable stress of the material must be, in order to safely withstand that particular bending moment. Section modulus is a property of the geometry of the beam cross section, that relates bending moment to maximum bending stress within it. It also governs the total deflection of the beam, as you account for the accumulation of bending moment along its length. As an example, suppose the beam were made out of Aluminum 6063-T5, with an allowable stress of 100 MPa. Allowable stress = stress at failure (yielding in this case) divided by required safety factor. Given a bending moment of 25 kN-m, this means the section modulus must be at least 0.00025 m^3, because section modulus * allowable stress must meet or exceed bending moment. If the beam were a solid square extrusion, this would mean a beam that is 12 cm wide by 12 cm tall.
at around the 20 minute mark there's the triangle in the parabola. How do you calculate a triangle when you know its change over a distance? or bluntly, how did they calculate 0.25
Wish my lecturer at uni explained it like this. Instead his idea of explaining convention involved starting off by saying Australian BM convention is opposite to the USA convention. And everything in the prescribed textbook has to be inverted. Combine this with errors in the textbook and very limited worked examples most of the class was lost.
What does the 18kNm max bending moment imply in real life. ? If I have such number, what do I do to counter it ... Please explain how it applies in real life.
