Big & Good SURPRISE for JEE Advanced 2024 Aspirants

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Latest news about JEE Advanced 2024 is a big surprise for all aspirants about the design and level of question paper. Every question in test paper of JEE Advanced is designed in such a way to judge the mental aptitude and logical ability of aspirants' mind. In this video Ashish Arora Sir is creating a new OTBT level question in the way questions are designed for JEE Advanced examination and explain how to build enhanced thinking for competing at JEE Advanced 2024.
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2 окт 2024

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Комментарии : 435

@kingroop7070 Год назад

i only got 90percentile in mains but still i was able to solve this question on my own ..feeling confident now .thank you sir

@krishnatrivedi7739 Год назад

Same bro

@sujal_plays_OP Год назад

same 87%ile but got the expression

@rahuldravid8414 Год назад

😂😂😂

@raunakkumar8599 Год назад

Bro ghar me question ban ja rhe the exam me same question nhi ban rhe the 🥲

@chemistry76s Год назад

@JEE

@harshtayal8112 Год назад

Sir I am glad to tell you that because of your mentoring and your tips I've been able to make it to IIT MADRAS in JEE Adv. 2022

@aimiit7012 Год назад

Kese Kiya aapne

@Saurabh.S898 Год назад

To phir se kyu aya time pass karne😂😂😂😂😂😂

@Raj_IIT_KGP Год назад

@@Saurabh.S898vai ye sab juthe ha😂

@user-xg1jv4rw7e Год назад

@@Saurabh.S898 matlab? Kya tum ye khena chahte ho ki iitians ek min bhi waste nhi karte din ka?

@Raj_IIT_KGP Год назад

@@user-xg1jv4rw7e faltu ke thing me to nehi karte

@YouNight69 Год назад

I was able to think most part about it the mistake i made tht i thought it will catcht the ball at other point of circumference i mean I considered theta 180 degree and GOT wrong thank you sir for this amazing perspective!!

@wildnest6740 Год назад

sir it was extremely helpful in getting to know how actually we need to develop otbt thinking. please keep posting these videos.

@pranjalimishra005 Год назад

Sir concept matched...could think till this level ...after mains was feeling like I lacked practice but now thanks to you I gained confidence that i do not need to solve many ques...just focus on the concepts and try to do the same question with multiple approaches which would be more beneficial.

@DoorKaRaahi Год назад

Whats your jee mains score

@gamajiyt8231 Год назад

Sir mene another method se keya h batna ki sahi h ya nahi Method: First let projectile towards the centre axis is X and downwards from top view is Y To mene Range = v²/g jo x coordinate ho gya or y= (2)½ wrv/g ho gya Ab ye point circle per hoga to centre se distance radius ke equal hogi so waha se equation bani Plz sir batna koi concpet missing to nahi h??

@freeassets2375 Год назад

Sir same doubt

@tysonff2627 Год назад

Sir I was able to get the second question exactly...till the last expression...just for that angle I calculated it using the angle between the velocity vectors...

@ManishDesale-i7q Месяц назад

if block A of 2kg is kept on block B of 4kg And block B is on a inclined plane making an angle of 30 degree from the horizontal if coefficient of friction between block A and Block B is u1=0.3 and the coefficient of friction between block B and Plane is u2=0.2, and a external force F along the incline is acting on block B(the external force F is the minimum force along the incline needed to make sure that block A does not slip over Block B). find the direction of friction force acting between block A and block B and also find magnitude of F

@Namchha1 Год назад

Actually, for the boy to catch the ball, both of their x and y coordinates at time t must be identical. However, the boy's velocity in the negative y direction is always decreasing while the ball's vertical component of velocity is constant. This implies that the displacement in the negative y direction of the ball will forever be greater than that of the boy and hence, they can never be at the same position at time t which is not 0. I have mathematically analysed the result ashish sir derived in this video and can confidently say that the derived equation has no solution(v) for all real values of w and r which are constants in our equation.

@abhayprajapati2485 Год назад

But I think that when the ball will actually complete its range then automatically x and y coordinates will match to that of the person at the same time

@gourik1929 Год назад

You are correct When we look at in in only dimension (eyes pointing towards +ve x axis)we observe that always the ball will be ahead of the boy along -ve y. So they can never coincide

@prikshitkhyalia8054 Год назад

You are correct. I have not analysed it mathematically but I was able to think the same. I was searching such type of comment and found yours. Thankyou.

@darshan5044 Год назад

Exactly. I was just so confused how it could be even possible without having the boy _throw_ the ball in the +ve y direction. Without a throw in the +ve y direction the ball will always go farther than the boy in the y direction, hence never meeting at the same time and point in space after t=0. Thanks for writing the comment, I do not feel left out.

@ruchitkala5841 Год назад

@@darshan5044 actually ball ke pass Rw velocity hogi na in -ve direction kyunki initially ball bhi ghum rahi thi

@Shubh__05-r8y Год назад

Sir you told in your previous videos that we need to follow finger technique and read questions and their solutions but you said in this video that doing pyqs and solutions will not help so sir can you give a little clarity on that. I am sorry if my doubt is a little silly I'm just not able to understand what's the right way to go about it.

@omprakashnarayan1327 Год назад

Try to extract concepts from pyq and try another ways to do same questions 🙂

@Shubh__05-r8y Год назад

@@omprakashnarayan1327 Yeah I understand that but suppose if I am using finger technique with the 700+ advanced illustration book then am I going right and if not which material am I supposed to refer to for reading with finger technique and learning.

@Kovid_ Год назад

sir i was able to get the idea of that resultant velocity thing but can't get into PM and time of flight part. I'll try my best to evolve my thinking. Thanks for showing us the approach towards jee adv qs. Edit : PM = range of the projectile

@sudarshan1793 Год назад

why resultant velocity is not included in time of flight it seems that tangential velocity only affect range and direction of projectile not time of flight

@Khokalaa Год назад

9:02 sir Person is in touch with table which means he doing circular motion also that's why you added linear velocity due to circular motion but the ball is in air and have only projection velocity not Circular velocity which cause ball to move towards centre only, it means person can catch only ball opposite side of daimeter. WHY YOU ADDED CIRCULAR VELOCITY TO BALL ALSO. I MAY WRONG?PLZ EXPLAIN SIR? How ball also has rw velocity?

@ShivanshuMishra398 Год назад

Yes, sir table is doing circular motion not the ball...why you added linear velocity due to circular motion in ball.?

@ninja_42 Год назад

Ig the disc was already rotating before the boy even threw the ball, so just imagine yourself instead of the boy and it actually does make sense

@Khokalaa Год назад

@@ninja_42 yes, boy do circular motion and have linear velocity with wr but when you throw the ball in air it was not follow you because it has not circular velocity. It has velocity towards centre and can you only catch the ball when you reach the just opposite the daimeter means you travel distance of πr(half circumference ( ball must have range range 2R)

@feelingdreams Год назад

Yes sir plz reply 😢

@Khokalaa Год назад

@@ninja_42 do you understand what I am asking? What is my doubt?😢

@rahulp4830 Год назад

Sir honestly I will tell. I could only think till Vh (net resultant) of Horizontal component Vcosθ and Rω. 😭😭🥺. Couldn't think beyond it.

@physicsgalaxyworld Год назад

try to think more and more on framing new such questions from PYQs... it will help in building your thinking...

@rahulp4830 Год назад

@@physicsgalaxyworld Thank you sir ☺️.

@DalaluddeenHalala Год назад

@@physicsgalaxyworld Sir yesterday I have ordered PYQ analysis by Physics Galaxy

@vijoyprasad9855 Год назад

Here we can also use cosine rule to derive the expression Cos(theta)= (2r^2 -l^2)÷2r^2 L=range Theta=wt w angular velocity t time of flight

@amitupadhyay6707 Год назад

wonderful

@NotDefinitelyNotMe Год назад

Once sir mentioned the word "3D" the question seemed pretty obvious to me and I got the procedure....I lagged behind in taking theta in terms of velocity of projection and the radius

@GaneshKumatole7 Год назад

TQ SIR ..., MAINE ATTEMPT KARTE WAKTH CURCULAR KA DYAAN NA DENE KU MISTAKE KARDI THI .... SO , MADE THE BOY TO COVER SEMI-CIRCLE IN SAME TIME AS THE PROJECTILE WOULD LAND COVERING THE RANGE OF 2R ... LATER , ANALYSED MY MISTAKE... , ACHA LAGA BY VISUALIZING... !! TQ SIR , ♥️💪🔥

@ringtone34 Год назад

Thanks you so much sir motivation through this question this question clicked me conceptually and iam able to solve instead of low performance in mains

@yogeshwarsingh7975 Год назад

thank you sir i actually solved the question on my own and feel great about myself for it!!

@BREAD-kc4zp Год назад

Was able to solve both the questions, feeling 💪💪💪

@debadityanath5558 Год назад

I reached upto equating time, missed: Calculating the value of θ using Resultant horizontal velocity: Lesson: Always draw neat and to the scale diagram taaki resultant nikalna naturally aajaye yaad

@m.a.y.u.k.h Год назад

I actually equated the PM distance ,means the (root R^2w^2+v^2/2 )*v/root 2 *g =PM .PM is calculated from traingle law PM/sin wT =R/sin (180-wT)/2 ,Where T is v/root 2 *g

@Rohit_03 Год назад

I thought entirely right...for one moment i calculated l as vh^2/g then realised upward speed is vsin45 but horizontal isnt vcos45 anymore so projection angle I think changed then went again to basics range=xspeed*timeofflight

@abhisheksriramula3612 Год назад

Sir I was able to solve the question correctly, just a silly mistake, even I had taken it as cos instead of sign. But I was able to solve it completely thank you sir!

@sharpmind2869 Год назад

Sir, your question is wrong ❌❌❌❌as there will be no solution. Because the ball has wr velocity in downward direction at the same time boy has wr velocity but on circular path so at any given time the downward displacement of ball will be greater than boy, so he would never be able to catch the ball. A correction can be made if he throws the ball by aiming at a point which is above the center O as then the downward velocity would decrease and the boy can catch the ball.

@tycoon3228 Год назад

Sir I did half of the question then I thought that the question is wrong... actually I misunderstood that boy will remain on P

@soham683 Год назад

Yes sir l am able to grasp the concept of this question.

@bijaykryadav7906 4 месяца назад

Sir please bring more such kind of question solving videos this was really very helpfull

@chaitanyatelagani550 Год назад

Keep calm and cool

@atulboi222 Год назад

Sir I got the answer , it took 8 minutes of thinking 😫

@NishithDubey Год назад

Sir centrifugal force bhi to lag rahi h?????

@apurbanandi9175 Год назад

Thank you Sir!

@amanshukla118 Год назад

Feeling good sir i catched the thought for the problem when you gave the time all Because of you sir

@potu6534 Год назад

Har baar ashish sir ko dekh ke ek happiness ki feeling aati hai 😊

@sudarshan1793 Год назад

why resultant velocity is not included in time of flight it seems that tangential velocity only affect range and direction of projectile not time of flight🤔🤔🤔🤔🤔🤔🤔

@kaizen1728 3 месяца назад

Sir can't we just simply use concept of relative motion Like at t=0 and t=final the displacement of ball wrt boy should be 0 For ball by vector laws components along x axis we have Rw of ball and -Rw of boy which cancels out In y axis we have vcos45 and deacceleration of -w²r since boy is moving with centripetal acceleration which will be parted to ball in his frame in -y axis In z axis we have vsin45 and g We don't care about the z axis but in y axis the displacement should be 0 so by 2nd equation of motion we can find time of 0 displacement which is √2v/w²r By this time we can calculate theta and other things

@sakhamurithanmai4442 9 месяцев назад

sir, i got the full question.feeling confident now...

@Newstimes1301 Год назад

🙂🙂🙂 confidence level badhta ja rha

@physicsgalaxyworld Год назад

Block Strategy Revision for JEE Advanced 2023 - ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-WoGmb5b4kQU.html Best Practice Book of 700+ Advance Illustration for physical situations on Physics Problems. Check at - amzn.to/3qyIK8H Best Chapterwise PYQ Book of JEE Advanced with detailed comprehensive solutions. Check at : amzn.to/3ZXotZs Download academic resources for JEE Mains & Advanced 2023 from PG Telegram - t.me/physicsgalaxyworld For best online courses on JEE & NEET, download Physics Galaxy mobile app. Download link : bit.ly/PhysicsGalaxyApp

@shivamkumarprasad9724 Год назад

Sir, one doubt, should i do my coaching material before or after the Advanced Illustration and PYQs, or should i leave it and focus only on Adv Illustration and PYQs? Please help Sir.....🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻

@Mr_flash_videos Год назад

Sir can we do it with shm

@Mr_flash_videos Год назад

By taking two projection in x, y axis

@ujjwalsingh3814 Год назад

But sir isme to solution galat ho gaya na. Agar boy ko ball catch karni he to uske liye ball ko wapas land bhi to karna padega. Matlab ball ki to resultant veloicity ki range he usko exact circumference pe khatam bhi to hona padega. aisa bhi to ho sakta he ki ball circumference tak pahuchne se pehle he land kar jae. To sir mai finally keh raha tha ki isme ek aur eqaution banegi jo Resultant velocity ko uski projectile ki direction me karegi => 2 * tan⁻¹(v/✓2Rw) = theta

@dhruvbajaj3164 Год назад

Please also guide something about chemistry and maths also. It would be a huge help.

@physicsgalaxyworld Год назад

Follow block strategy video for fusion revision for jee advanced 2023

@dhrudeepdesai1779 Год назад

This video tells that , still work is needed for advance...........

@OptimusCubing1 Год назад

please make block strategy for JEE 2024

@WhiteR9se Год назад

i was able to grab the theory of the question but now i am curious as this is an interesting question. now i am this train of thought : if we throw the ball towards the centre with enough velocity and the moment we throw the ball, the horizontal disc starts to accelerate, would it be possible to catch the ball diametrically. i solved theta for 180 degrees in this equation and as far as my math took me, it was not possible( for constant omega).

@YouNight69 Год назад

same bro I took theta 180 degree (got wrong) then reconsidered to some small theta !!

@snehapeter4686 Год назад

Hmm i guess you can if the ball was thrown just before disc started rotating and then disc had enough linear velocity for boy to reach and catch on time.. But if it was thrown exactly whe disc started rotating, you migh get what you want if the ball is thrown with rw in the opposite direction of rotation, making a required angle in that direction to cancel out velocity component due to rotating disc

@ritankarmondal0411 Год назад

@@YouNight69 Same bro! And I got v = g pi/ root(2) w 😅

@WhiteR9se Год назад

@@snehapeter4686 hmm i get what you are trying to say. If you throw the ball to catch it diametrically while the disc is rotating. the trajectory of the ball might me similar to how the sun rotates the earth wrt us. not a perfectly vertical parabola, a slighty titlted one.

@rohit_____ Год назад

Love you sir you stand for us every time

@SathwikDonthu-es9ji Год назад

Pogi rocking every lecture 🤣😂

@careerwhere4508 Год назад

Thanks u so much sir for this types of important concepts.

@Sraghav0 Год назад

Sir when you will start jee advance 2023 series? Please tell

@pawan_chavan_123 Год назад

What was Done by Pogi ? 6:22

@ma.hinder_ Год назад

Pogi ko uski salary time p nhi mili isliye usne apna Kam nhi kiya

@ankita5078 Год назад

Jiska naam hi pogi hai usse kya expect Kiya tha 😂

@ma.hinder_ Год назад

@@ankita5078 pogi k pass job to h karne ko. Tere pass to kuch karne ko bhi nhi h 😂😂 Don't hate pogi😠

@ankita5078 Год назад

@@ma.hinder_ 😔 sorry pogi. Kitna cute naam hai apka I luv you pogi ❤️ from my soul.... Chal be pogi asli I'd se aa😂😂

@ma.hinder_ Год назад

@@ankita5078 pogi guine h , agar naraz ho gya to jee main m fail kar dega 😂

@ironman9706 Год назад

Sir plzz give info about pys advance batch 😅😅😅....we are waiting eagerly and need it

@spacex8583 Год назад

Sir i am prapring with my fill energy sir par advance ka form fee hi 2900 hai so price dekh k sir but mere 87.5 bane they pahle attempt me 2 month ke gap me major familiar issue me padh nhi paye drop ka v soch rhe bcz sir form feee v dal de and result v na bane ( my syllabus in physic 85 % and chem 30 and in math 40 cokplete hai and phy chem wale chapter ke accha grip hai unme sir kya kru Mai

@Foundational_physics Год назад

It is extraordinary respected sir

@thefallenangel2403 Год назад

Thank you sir, really a nice concept..... although I didn't solve on notebook and pen, I could figure out the steps of solving....just didn't form the equations.

@AyushSharma-qe3uv Год назад

V=root(2Rg-2(R^2)(w^2)) If we take: Rsin(wt)=Rwt Rcos(wt)=R-tvcos(45°) Square and add to get condition on v using t=2vsing(45°)/g

@siddhantgupta555 Год назад

PLS tell my mistake i tried to resolve in components and made inequality on the basis of that, and got 2 cases for 1st half and 2nd half .

@akash494 Год назад

2nd dropper JEE advanced nahi de sakte to ab kya karu samja nahi ati hai...mains mai 98 percentile hai......need your guidance sir.😢

@lucifer8257 Год назад

Aur koi coaching liya tha ya self study ?

@surajinamdar3847 Год назад

98 aye hai toh kisi nit mein chale jao ... no option and dont expect any messiah comes and helps for jee advanced 3rd attempt... kyunki aajkal log 75% criteria ki peeche pade hai and no one is thinking about 3rd attempt... so stop hoping and accept the bitter truth... sorry if u felt that I am harsh

@xeesoxee2 Год назад

Bhaii IIIT lele cse agar paise chahiye, agar thora college lifee me saxxx suxxx krni hai toh NIT 🗿

@lucifer8257 Год назад

@@xeesoxee2 ye 2nd drop me placement me difficulty hoti hain kya ?

@xeesoxee2 Год назад

@@lucifer8257 ghanta kuch nahi

@syntax.errxrr Год назад

Sir i have not yet studied rotation 🥲 So i cant take good part in your decision 🥲🥲

@harshchad Год назад

Thank you sir

@ashwanththinks9139 Год назад

I was able to thing about equating time of both motions but i was not doing projectile motion vector analysis!

@arkadeepdas6726 8 месяцев назад

Sir, can we solve the second question in the following way? As triangle PMO is isosceles, angle OPM = 90 - theta/2 So, tan (90 - theta/2) = Rw√2 / v Where theta = w × time of flight of ball. Solving this, I got : tan (wv/g√2) = v/Rw√2

@krishnatrivedi7739 Год назад

Can anyone tell that advanced illustration uploaded on channel and 700+ jee advanced illustration book, are both having the same questions amd illustrations?

@blazing-ansh5128 Год назад

Sir visualization ek dam perfect tha mera same yahi kiya tha magar expression tak nhi pauch paya

@Thearpitsoni Год назад

Dream: IIT DELHI I'll crack the exam

@Ayush-mg6xw Год назад

Im coming toooo

@YourLovelyAnmera Год назад

All the best to you both 😊, me vi IIT roorkee gaunga .

@ma.hinder_ Год назад

Thanks for all your efforts sir. I will definately get into iit this year ❤️

@sujal_plays_OP Год назад

how? you studied from where

@Abnik62 5 месяцев назад

Kaha ho bhai

@ma.hinder_ 5 месяцев назад

@@Abnik62 lpu🤣

@amolsingh975 Год назад

Hy sir, Sir mane is question mai ball ki xy plane mai velocity ke do components leiya or point p ka net displacement liya in time T or fir ball ke displacement se equate karke mera expression for v is (2w2R2 +2Rg)’0.5 aagya plz tell is it right

@avigorai1644 Год назад

10:45 meko wo trigo wala nhi sooja to cosine law laga diya, usse bhi solve krke yahi ayega ,,

@Anonymous-jm5fi Год назад

I was literally thinking the veryyy same thing like how in the earth it is possible to... I was writing this👈 but suddenly a thought came to my mind It's about frame... The thing that we are missing, you must try to look it from a distant position and you'll nottice that the ball will have RW velocity too... It's easy if uknow some part of inertial and non inertial frame...

@Khokalaa Год назад

How ball has rw velocity? Plz explain?🥲

@Anonymous-jm5fi Год назад

@@Khokalaa Fuck U I hate increasing my comp. But okayyyyyy!! Imagine if you're traveling in train it will appear to you that you are at rest but you'll be seeing trees speeding or in simple words the world outside will see you as they are in rest with respect to earth and you in motion with respect to earth... Similarly if the projectile is at P and P rotating then P will also have the very same angular velocity... If you're saying that only person has that RW velocity and not the projectile then they won't be moving together and the projectile will be left behind...

@se7enseas324 Год назад

sirrrr but previously you had told that we should follow d PYQ analysis book by finger reading method but in this video you are telling that just doing that is not usefull please tell properly which method to follow thank you

@pritigupta4293 Год назад

Sir please listen!! I'm going to take drop this year and I'm confused to purchase which book of physics galaxy So please help me to figure out!!

@ugufggfhhkuw736 Год назад

Take all 5 volume books and follow it chapterwise, I'm doing same

@darrydimola3300 Год назад

sir in this question angular momentum conservation nahi lagega kya b/c first boy at center and come to peripheri of disk please guide me 12.00

@Games_Era44 Год назад

Can we do this in this way Along line OP R-RCos(wRt)=Vt/root2 And then Rearrange for V??? Anyone Please Tell🙏

@magicalwithmusic Год назад

Not able to understand sir .....

@arikithroychowdhury5038 Год назад

Sir I am able to find the exact expression for velocity, it can be done by using pythagoras theorem, darwing perpendicular from M on OP

@diskritis2076 Год назад

Question is based on a flawed logic that i realised while reading, I will attach another person's comment to convey: Actually, for the boy to catch the ball, both of their x and y coordinates at time t must be identical. However, the boy's velocity in the negative y direction is always decreasing while the ball's vertical component of velocity is constant. This implies that the displacement in the negative y direction of the ball will forever be greater than that of the boy and hence, they can never be at the same position at time t which is not 0. I have mathematically analysed the result ashish sir derived in this video and can confidently say that the derived equation has no solution(v) for all real values of w and r which are constants in our equation.

@bhaskarruwali4905 Год назад

I was able to imagine how boy will be able to catch the ball,but wasn't able to think formula

@amitamit1628 Год назад

I thought even deeper and conserved angular momentum when the boy reaches on the circumference and found new omega and solved the question.... Lol

@parvinderkumar6712 Год назад

Sir my approach is different i am equating displacement in x and z direction and qeta equal to wt and finding t from z direction dispalacement AM I CORRECT

@try-to-be-expert1 Год назад

done by own ( thank you sir )

@adityadeshmukh7759 Год назад

sir need your help in chemistry and maths pls sir your experience required a lot.....I think you would guide us ......thanku

@Josuke217 Год назад

0:11 no Mathongo was harmed

@omprakashnarayan1327 Год назад

2:00 ☠️

@yahiko-thedevapath5049 Год назад

Bruh you know in the morning I saw a video and saved it to watch later...but then thank you 💀☠️

@azamshaikh6011 Год назад

Jee advanced series sir please

@heetshah9046 Год назад

Sir, my doubt is that in rotating disk the velocity on ball due to rotation will act in opposite direction due to inertia......wright or wrong??

@Akanksha6643 Год назад

Inequality se kese solve kare. Like range cannot exceed 2R. Distance travelled by rw velocity cannot exceed R etc.

@priyaranjanrout777 Год назад

Sir I did it 🙏🙏🙏❤️❤️❤️

@shivamprakash4324 Год назад

Sir i solved the whole question by myself thanks sirr feeling confident now

@jiteshmishra6633 Год назад

Sir maine angles ka use Kiya sirf or mera xota soln aaya Velocity vector ka angle v/√2 se @ mana or tan @ nikala Phir circle ke centre pr angle π -2@ substend hua jab ball catch hui or same time me boy ne π-2@ angle ko cover kia So π-2@=wt => t=√2v/g tan@=√2Rw/v 2(π/2 -2@)=√2vw/g 2arccot√2Rw/v=√2vw/g Finally v= √2 Rw tan(w v/√2g)

@jiteshmishra6633 Год назад

Sir equating angles are more convenient then equating distances

@namanthakkar8972 Год назад

Solved on my own, Derive the same expression in the reference frame of boy.

@ujjwalsingh3814 Год назад

But @Physics Galaxy sir isme to solution galat ho gaya na. Agar boy ko ball catch karni he to uske liye ball ko wapas land bhi to karna padega. Matlab ball ki to resultant veloicity ki range he usko exact circumference pe khatam bhi to hona padega. aisa bhi to ho sakta he ki ball circumference tak pahuchne se pehle he land kar jae. To sir mai finally keh raha tha ki isme ek aur eqaution banegi jo Resultant velocity ko uski projectile ki direction me karegi => 2 * tan⁻¹(v/✓2Rw) = theta

@rockrozindia2893 Год назад

Sir socha sahi ta but ek Galti he hui ti me range KO max manke R tak likha ta

@Darkboy49 Год назад

I was only reached upto time period and theta relation

@anonymous-zr2cb Год назад

Sir.. video pause kar ke solve Kiya toha toh uss ka diagram exactly same banaya tha par expression develop karne mein issue hua aur voh nahi ho saka.. aap kuch suggestion denge kya please, isko improve karne ke liye?

@Deepak_Malik_ Год назад

2nd question was similar to one part of inpho 2021 question

@shivasharma1984 Год назад

Sir thinking to aise hi kiya but expression tk nhi pahunch paye...iska kya soln hoga

@physicsgalaxyworld Год назад

try to think more and more on framing new such questions from PYQs... it will help in building your thinking...

@shivasharma1984 Год назад

@@physicsgalaxyworld thankyou sir

@crackcompetition4751 Год назад

I reached till the last expression but was not able to calculate thetha

@anshoswal5450 Год назад

Sir bannn gayaa qsss🥺🥺

@TarunKumar-rr8gw Год назад

Sir agar kisi ka jee adv ke liye just qualify ho raha ho aur uski thinking iss level par ho toh kya us se adv crack ho sakta hai ??? 😐😐

@AJAYKUMAR-oi9ft Год назад

Good evening sir. I have solve this question using the Non-inertial frame of reference. Kindly check my solution and also I think there is a mistake done by you during providing solution to the question on RU-vid ( I may be wrong ). I am attaching the pic of my solution.

@AJAYKUMAR-oi9ft Год назад

Unable to attach the solution pic through RU-vid chat box. Kindly suggest that how can I send my solution through other means.

@AJAYKUMAR-oi9ft Год назад

Sir please say that how can I send my solution pic to you. I can't send it through RU-vid chat box. This is important to send because I have solved it and spent a lot of time for it. I have also found out a mistake which has been done by you. So kindly provide any link or number whatever possible.

@dibyenduguru3408 Год назад

Sir why acceleration due to centrifugal force is not considered in the 2nd case??

@avigorai1644 Год назад

I feel lucky to have a mentor like you, At the same time i feel jealous that it is available on youtube and it is increasing competition day by day.

@raghavsharma4823 Год назад

Can this be done by keeping the disc in rest and applying the velocity and relative acceleration. As in this case we will get velocity only along y and x axis and acceleration in -x axis ( the centripetal acceleration in reverse direction applied to the ball). In this way it will simply become standard projectile question but with horizontal component of acceleration too.

@channayyameti2685 Год назад

Thank you sir You are the only trust for us!!❤

@prachiyadav1602 Год назад

I am sorry to say…. But boy can never catch the ball…..How?? Drop a perpendicular from M on OP. Call the foot of perpendicular N. Now, the boy travels the “arc” PM with a speed wR. And the ball travels the length MN with same speed wR ( ball’s speed in vertical direction is wR) in the same time. Think yourself, can arc PM ever equal MN?