6 years later and let me tell you,,, You saved me through my exams. I was so confused with all the lines but this video right here changed my story. Thank you.
Wow these lectures are so good. Thank you so much for contributing to the free and open body of knowledge for our species! You've really helped me get a strong grasp on this material.
at 23:45 what if the concentration is below 18.3% at a temperature of 150 would the calculations of W(alpha) and W(beta) be the same or would it be different?
Hi, I just don't understand this problem at 2:10. Let's say I had 2% Ag, so at 600 - 1100 T(c) I have only alpha - Cu. What happened to my 2% silver as I increased the temperature? How did the system turn completely into Cu / Alpha? Thank you.
α, β and L are used to represent the different phases of the system. α, and β represent solid solutions of Sn into Pb and Pb into Sn, respectively. With that in mind, I don't think it's right to say that the α+β phases are present in the liquid phase. Moreover, in the liquid phase, there are both Sn and Pb, but as liquids, and not as α, β solids. Therefore, within the L+α region we have a liquid phase (L) and an solid phase (α), and both of them are solutions of Sn and Pb.
