It won't starts from 2^0*R, 2^1*R, 2^2*R.... It starts from 2^1R, 2^2R......2^n*R. If you observe the equation of DAC Analog value =K* Digital value. Vo= Vfl(2^-1*d1+2^-2*d2....2^-n*dn).
No you multiple inputs can be given depending on the number of bits if 110 in binary then from msb make two input connected to -Vr and lsb 0 the 3rd input to ground to make 0 the current will be flowing from 1 1 input. Total current will be the sum of 1 1 input current. Now the total current is input to op amp which converts current to voltage. Thank you hope this will help many techies😊
Resistor required in n binary weightage type resistor is not nr or 2r or 4 r ...it is 2 power n-1 R like as for 4 bit binary weighted converter n=4 so 2 power n-1 = 2 power 3 =8 resistor ...
Hello Krishna, Reference voltage can be either positive or negative.... if ref voltage is negative we will get a positive output else output will be negative...
is required to operate a solenoid valve using a microcontroller-based system. The solenoid valve has two opening positions A and B, the valve opens at position A at a voltage of 0.4125V (scaled) and at position B at a voltage of 2.0625V (scaled). Design a binary weighted DAC that can be used to perform this task. You cannot use a reference voltage higher than 5V. Solution???
Hello Munesh, digital value is actually binary weighted - consider 111 ie decimal 7- 1 × 2^2 + 1 × 2^1 + 1× 2^0, so amount of currents through these resistors are also binary scaled - let current through MSB resistor is 4mA, current through next resistor is 2mA and current through LSB resistor is half of current flow through resistor of the previous bit....
