The timestamps for the different topics covered in the video: 0:23 Advantages of R-2R ladder DAC 1:58 Calculation of the output impedance of R-2R ladder Network 3:47 Calculation of the Output Voltage of 3 -bit R-2R ladder network 15:35 Solved Example
If you keep the formulas aside, I think its the analog value of least significant bit. Correct me if I am wrong. From my understanding resolution is the least voltage that has to change to achieve the corresponding analog voltage.
@@mayankawasthi6839 in case of DACs resolution is the voltage that the output signal is incremented by, when the digital input changes by 1 unit.... For ex on going 101 to 110 The output analog signal would step up from its previous value (Vi) to Vi + Resolution or 1 LSB.
Bro in the example question you have done a mistake At caluculating o/p voltage the order for binary is in reverse order , please check it ..... it is opposite while you summation for thevenins voltages binary order
The volume bro - it's reminding me of the 'blare' memes (you know, the ones where the screen goes red and the volume goes UP lol) All aside, the explanation works; R-2R type DAC is a nice adaptation
Actually, in the thenivin theorem,while calculating Rth,we will not include the resistor through the thenivin voltage is calculated,in the same here also we should include the resistor 2R,but we are including it and saying 2R//2R, how it's possible?
Sir why you have stopped gi thinking the brief description of the topic that you have taught in that particular video, I think it has helped many students and student too have appreciated it, so pls give the description of the topic in description section
Hi, well thanks for raising this point. I am still providing a description of the covered topic. But some topics are more sort of derivation type. (particularly the last couple of videos on BJT). But yes I will continue to do that. And try to provide a more detailed description in the future.
I'm guessing the the type of current is AC in this circuit right? I have a school project where I have build a 3-bit R-2R circuit with Vref=1V, but I'm not sure what voltage the op amp is supposed to be amplified to (Vcc+/Vcc-)?
Yeaaah we also need ADC types ....ur way of teaching is good n easy whaf i liked more about ur channel is in description u give all the information definition n time stage for specific topics
Sir, at 14:05 the ladder circuit shown with inverting op amp where Vr-2r is applied on inverting terminal. So my query is that why we are not added one resistor R between Vr-2r and inverting terminal of op amp to prove the correctness of the written formula of Vo on the same timestamp. Waiting for your reply sir Further, Thank you for providing us these type of valuable and easy understandable videos 🙏
The thing is, there will be equivalent resistance (Thevenin's equivalent resistance) of the R-2R network at the inverting terminal. The equivalent resistance depends on the data input. Its value will in the multiple of R. I have also shown the same thing at the earlier part of the video using the example. That's why there is no need for additional resistor. I hope, it will clear your doubt. If you still have any doubt then let me know here.
What you are saying is that, there should be additional resistor between ladder network and the opamp right ?? But actually the Thevenin's equivalent circuit will be there at the inverting terminal of the opamp. Which comprise of one voltage source and one resistor ( which is the multiple of R). Just put some values in that equation and you will understand it.
I am confused that how Bo B1 B2 B3 B4 B5 values are taken because if Bo and B1 are grounded then then should not be 2 power 1 because first 0: 2 power zero and next zero 2 power 1 and next one is 2 power 2 and so on...
Sir after using superposition theorm and selecting one input at a time and grounding others can't we then we Kirchhoff's current laws to get vout??? Instead of Thevenin equivalent Thanks
I lost where denominator of Vout is R, maybe that because he said overall impedance is r? but i don't get the overall impedance. anyway I grabbed on gasp of R-2R. thanks very much
I understood it well but got a doubt.. at 6:12 , when the portion of the circuit was redrawn, in that Vref should be drawn with opposite polarity....because in the original circuit the positive terminal is connected to the bottom terminal of the resistor...
No, It is alright. If you closely look once again, in the equivalent circuit, the Vef is connected to 2R. (Also see the left side circuit at the same time). The other terminal of that 2R resistor is connected to the remaining circuit (the node where we want to find the Thevenin's Equivalent circuit and the second 2R resistor), whose second terminal is grounded. If you closely observe it you will get it. I hope it will clear your doubt.
probably a better question is why does the equation for Vo have -Rf/R when Rf is present but doesn't have that when there's a short circuit? Since a short circuit means Rf=0? Or is it just convention to use that equation when the output terminal is shorted with the negative input terminal
for better understanding please go through this video on the op-amp. It will help you. ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-uyOfonR_rEw.html
Unless you are specified the value of Rf (feedback resistor) and R, the resolution of n-bit R-2R DAC is Vref / 2^n . (Because you do not know the internal circuit as well as the value of resistor) But if you have been specifically given the values of R and Rf, (like the solved example at the later part of the video at 16:18), then you can use the equation given in the video. I hope, it will clear your doubt.
no, it is correct. If you see the expression, in the denominator, there is 2^(N- i). Here N is 6. And B2, B3, and B5 are 1. So, it will be 1/(2^(6-2)) + 1/(2^(6-3)) + 1/ (2^(6-5)) That is 1/2^4 + 1/2^3 + 1/2 I hope it will clear your doubt.
It is found using the voltage divider. From 6:00 onward, I have already explained it with the equivalent circuit. Please go through it once again, you will get it.
thank you sir it is very effective video to understand R-2R.I am student oh Çukurova university electric and electronic enginering. can I send our integrated circuit program .please check and give advise
By applying the KCL at the inverting node, you can find the current Rf. Assuming opamp as ideal opamp, no current is flowing into opamp terminal. Therefore, the current through Rf is the summation of all the incoming currents at the inverting terminal. I hope, it will clear your doubt.
