he is correct it is suppose to be 10^13 because its to MeV which means you need t multiply the 10^-19 by 10^6 to change the eV into MeV you made a mistake identifying MeV and eV
never learnt about that last point on helium being unusually stable, really helpful making notes on these videos in the week running up to the exam, thanks!
Three nucleons contribitung binding force but only one nucleon contributing em repulsive force. That ratio does not exist in any other isotopes. Tritium maybe 2:0.
I really like your channel, your videos are my go to choice for consolidation after lessons, and I actively look for your thumbnails in the search results. They seem thoughtfully planned out, and they’re pleasant to watch and understand. You neatly cover the course content without expending unnecessary time, and you remain professional throughout (if we overlook the “BIG D” reference hehe). I’m sure I speak for everyone when I say that your channel is more than just a hobby or side business, but an outpost for aspiring physicists.
I get you, but its the energy that's being used to literally bind the nucleus together. In order to seperate it, think of the energy putting into it as though you're "paying the nucleus" the energy back that likes to have from being bound together, so that each nucleon is satisfied after.
I am doing a research project at school on how nuclear reactors work, and this video helped so much to explain binding energy, mass defect and how this all relates to fission. Thank you so much!!!
Ok. This is the part I'm constantly confused about. If total BE increased, then wouldn't that mean that mass is gained rather than lost (mass-energy equivalence)? Or is there something I'm misunderstanding?
Binding energy is a bit of a misnomer - it's a 'negative' energy; the energy needed to get out of the potential 'well'. If you roll down a hill, we can say that your climbing energy has increased, because it's now going to take more to get to the top again. Same idea.
@@ScienceShortsI prefer to call it binding force, because it is the force that hds the protons and neutrons togethet in thenucleis. Otherwise known as the residual strong force, which I consider to be a misnomer.
at 7:40 can someone explain why the binding energy goes up after uranium decays? - for anyone who needs this is how i understand it during fission energy is released from the system during the decay and to separate the atoms into its base nucleons, that energy will need to be put back in on top of what u already need. as binding energy is the energy used to separate them, it increases the mass decreases due to equation -> binding E = calculated mass - actual mass so an increase in binding E would be caused by a decrease in actual mass - as mass and energy are interchangeable
I thought that when we convert U to MeV we multiply by (933.75) which rounds to (934) .. atleast that's in the CIE syllabus. We calculate by using E=mc^2 . So E=(1.66x10^-27)(3x10^8)^2 . while U is the atomic mass unit. Then we Get the answer as 1.494x10^-19 (J). Then we divide by (1.6x10^-19) to get (933.75x10^6 eV) which is (933.75) MeV which rounds to (934) MeV
Physics isnt helping itself as a field of study when it does things like defining binging energy as the energy required to sepparate. It serves no purpose to define it that way round and just makes the subject harder to learn.
Thank you for your amazing videos, they are very helpful! I am confused about the steps in the process of mass defect. Because of the electrostatic repulsion between protons in the nucleus of an atom, there is a strong nuclear force which holds the nucleons in place. Firstly, where does this strong nuclear force come from? Is it generated by the neutrons? And why does the strong nuclear force cause a loss of the mass of protons and neutrons? How is the energy released related to this force? Does the strong nuclear force hold the protons and neutrons only, or their quarks as well? Also, how is binding energy related to all of this? Thanks again
.we are doing a mock paper 2 and I'm much confident on it now thanks for ur amazing videos.dont know what I would have done without them.i got a question : is the binding energy the energy needed to overcome the strong nuclear force between the nucleons from 0.5 fm to 4 fm (because it is attractive )and the rest of the energy is provided by the electrostatic force between protons to pull them apart?
Also sir... How does the difference in binding energies of the nuclei in a fission reaction give us the energy given out? Eg Binding energy of Uranium- 1739MeV splits into Rb and Cs Binding energy of Rb and Cs= 1957.6MeV How is it that 1957.6-1739 gives us the energy released during fission?
Thank you for this well done video! I’m not sure if it was covered but how do you calculate the potential energy between two points with a known mass number? Could you point me to a resource as well? Thank you!!
Why does the neutrons and protons come together by using energy up but when it comes to seperating we have to put energy in ? Cant they use even more energy up to seperate and the mass decreases even further
It's confusing when they write it like that, no doubt. By writing the unit like this, this is essentially saying that this is the mass in MeV. To make it clear: mc2 = 931.5MeV, so that means m=931.5MeV/c2
7:39, am I right in saying that the total binding energy increases because the total energy in the system has decreased so now it takes more energy to separate the constituent parts? If not then I’m a bit confused on why the total binding energy increases Edit: just seen the fusion bit now as well and my point above wouldn’t work for it so I’m confused on how total binding energy increases for both fission and fusion
brutha ik it prolly doesnt matter anymore an i hope it all worked out for u - the way i understand it is that during fission energy is released from the system during the decay and to separate the atoms into its base nucleons that energy will need to be put back in on top of what u already need and as binding energy is the energy used to separate them, it increases
+Tania Remember that binding energy is almost like 'negative' energy - it's the energy needed to 'unbind' the nucleus. Therefore, if energy is released, that must mean that the particles are now in a power energy state, meaning that it will now take more energy to break them apart. So that means binding energy has is increased :)
Binding energy is the energy need to separate or 'unbind' the nucleus. The release of energy in fission creates more stable nuclei, so the total binding energy increases (as the new nuclei are 'harder to unbind'). Hope this helps
@@ScienceShorts what about deuterium or tritium? A proton and neutron, and a proton and 2 neutrons respectively they should all be in significant contact. Is it because each particle has its own individual attractive and repulsive forces hence you want to maximise particles at the point they are all touching? In that case would deuterium and tritium be right below the helium nucleus in the graph?
You adding electrons in the beginning might confuse a few students, especially as we only really care about the nucleus mass and not the entire atom's mass.
It's an application of the relativistic energy equation (basically an equation which tells you the *total* energy something has), subtracting the kinetic energy. This leaves you with rest energy.
