Binomial Probability Distribution 

Thanks sir, much appreciated from south Africa here.

This is really good Explained in such the simplest way 🙂🙂

Thanks a lots for very good explanation 😊

WELL DONE!

your lessons are just incredible. thank you so much for sharing with us

Thank you for this wonderful tutorial, well explained 😍

Thanks so much.

This is well explained 🥰🥰 Thank you so much!

In the example 2 sir how did you get the success(p) and failure (q).

Hello good day. Why does in example 1 letter C you included Probability of 0? We are talking about of having a head right?

But a good concept

Thanks 😊 for sharing

In example 1 how did you got the 32 and 64?

Thank you so much sir. This helped me alot

Thanks very much but I have a lot of questions regarding part b of the second example. If I use Pr(x=0) + Pr(x=1) + Pr(x=2) + Pr(x=3) + Pr(x=4), I get an answer which is greater than 1. This arises from the fact that Pr(x=4)=10/9 which is impossible in probability. If I try your method, I still wonder why you did not subtract Pr(x=6). Otherwise the video was very helpful.

Pls how did you get 1/2 in the first example

thanks sir

Please example 1 how did you get the probability to be 1\2

On atmost question.. it is possible to use combination of 2 itself and only? Excluding 0?

Pls the final answer how do we do it

Thank You Sir

Have gotten it

how did you get 1/2??

What do you mean by 6c4 is 15 I'm not getting it clearly

Sir please how did you get the probability of success as p and q as a failure from the given question

Pls how did you get p=1/2 and q=1/2

I have a question for you 🙋‍♂, in colleges and universities, which math courses talks about Continuous Probability Distribution? Which courses talks about this? Which courses? The reason why I wanted to know which courses talks about Continuous Probability Distributions in colleges and universities because I don't know which courses talks about that? Please give me an answer to the question of which courses talks about Continuous Probability Distribution. Please answer my question.

Thanks

Thanks so much

God bless you

Thanks bro

Sir pls how did you get you success (p) and failure (q) in question 2&3 its confusing

How did you get 1/4 and 3/4 in the third question

How did you derive 6 combination 5 to be 6?

How you came out with 1 half and the rest

Moral is good

How did u get failure 0.2

Thanks sir

I don't know how get the 0.2 but u are doing very well

❤❤❤❤❤

recheck Q1

Pls how is 6c4 =15

In the examole 2, 2/3 to the third is 2/27, not 8/27. Reputability check. Unless my calc has got an internal issue.

3:49 how do u get 1/2

How is 6c4 15

Pls how can I get the failure

We have seen what is p as probability of success but we don't know how we seek a number P

Okay of this one p: it rains q: there will be flood

how is in (b) 6*1/(1/32) is equal to 6/64? it is wrong

How did you get P1/2??

the example 2 / b id didn't understand very well why you didnt inclidees even the probabibilty p(x=6) when calculating p(x>,=4 )?

Good but too long solutions ..

Sorry at least 5 it supposed to be 0,1,2,3,4,5

John M Sesay

oh i got it now

recheck Q1