I am doing Math Higher Level in IB, and I am doing it online (there is no teacher in my school who can teach math) And if it wasn't for this video, I dn't know if I would ever understand the topics I have to study. Alone. Thank you!
One of the most thoroughly and well explained videos I have come across. The constant use of different examples really helped make things clear. Thank you for this
excellent video n explanation. just started my certification course in buisness analytics using sas . so had to study these concepts again after almost 14 years . very well explained . keep it up sir
I salute you sir, fantastic video! Doing probability and statistics this year so I really need videos like these with worked examples. Thank you for sharing your knowledge, South Africa sends its gratitude.
OMG! Thank you so much. I'm taking statistics online and my professor does not explain as well as you. It's 2:52 am. I was crying because I didn't understand the binomial distribution and tomorrow I have a quiz. Now, I'm ready to pass the quiz. Thank you sooooo much😘❤
I really appreciated how precisely, clearly, honestly you explained Binomial Distribution and poisson distribution. Indeed you are a good teacher. I really like to get the whole lessons of Statistics. But how, Dr? And thank you very much indeed.
I'm struggling with a particular question..That being; average BOD content being 2.25mg/litre. If a 5 litre sample of water is taken, what is the probability of finding BOD contents of;1mgless then 3mgmore than 6mgAt least 2mg BOD is measured if only 1.5 litre of water is sampledDo I do 2.25 x 5 to get the total average? Or do I just use 2.25 as my lambda?
Excellent explanation Dr Craig McBride. Can you host more sessions like these and explain all the Random Variable led Distribution. Would be great if you can solve some of the questions of Prof Ross' book on Probability...
I have several videos on both of those topics. Just search for "chi" and the t-test videos are all titled by the type of test IE: two dependent means etc. Here is a link to a spreadsheet list of all of my current videos to help you find what you want. docs.google.com/spreadsheet/ccc?key=0ArSlKTsH9KkCdGxnRVpaMFJBUWNjZ0QzNzdwd1gyLWc&usp=sharing
@@DrCraigMcBridePhD if this is so , provided 530 hurricanes over 100 years time period, so how is this possible that there is no upper limit of occurrence in a single a year because total has to be 530. And also 530 hurricanes are distributed over 100 years, so it should be done uniformly right? Please make it clear sir! I am bit confused ! Thanks in advance
@@sayanjitb 530 over 100 years are the numbers that were OBSERVED in the PAST. We use data from the past to allow us to make educated GUESSES at what MIGHT happen in the future. SO, we had an average of 5.3 per year, but that doesn't mean there was an equal spread. There is no max. You could have 100 in a year or you could end up having 500 in one year! Those likelihoods are VERY small, but there is no max with probability distributions. Unless you are told that a distribution has a uniform spread, there is nothing that forces it to be so.
In a binomial experiment with n=300 p=0.5 Find p>0.6 I cannot seem to find the answer will you please assist me? If I say 1-px=0.0and 0.1 and 0.2,and 0,4 and 0,5, and 0.6 then it should give me the answer but I get an error when I put it in my calculator I assume it is because they are asking for p> a fraction instead of a numerical number such as 1, 2. 3 exc, If there is someone in chat or RU-vidr that'll be able to help me I would greatly appreciate it
You can't find the probability of a decimal with a binomial. You can only find probabilities related to whole numbers, so either it is a misprint, or you are misunderstanding the question. You could find P(X>6) given n=300 and p = 0.5 but your question does not fit a binomial.
DO you mean 0.15? Because I don't think there is a 1.5 anywhere in this video. 0.15 is the probability of a failure because we are given P(success) = 0.85 and thus the compliment is 0.15
.85 is the 85% probability that an adult knows Twitter given in the question. Since we are testing for exactly 3 adults knowing Twitter, our probability of a success "p" is 0.85
when you did the minimum and maximum values for a 95% confidence interval, how come u used the standard deviation instead of the standard error? shouldn't it be 11.4 +/- 1.96 (standard error), where standard error =standard deviation ÷ √n
Great question! That is because we were using the RANGE RULE OF THUMB for that example. We know that from the EMPIRICAL RULE that roughly 95% of the data lies within TWO SD's of the mean, so if we do +- 2SD from the mean, we get roughly a 95% CI. If we were to COMPUTE a PRECISE value, then YES we would in fact use the SE as you mention. The RROT is really just a close approximation to use if you didn't have technology or a way to compute the actual CI.
