Bioenno got me... I need your help! 

If you assume FT8 is 50/50 TX/RX you have (.5 *.45A) + (.5 * 2.31A) = 1.38A draw on average. With a 3AHr battery that's a little over 2:10. The extra 27 minutes comes either from the battery being a bit more than 3AHr (likely with a Bioenno) or a slightly lower duty cycle than truly 50/50 (likely because it doesn't transmit for 100% of the transmit cycle) or small inaccuracies in the current measurements.

I started out at 1 volt when I woke up this morning but after that first cup of java I'm running at 12 volts strong straight through lunch, great video Steve tnx bro.

I am very pleased with my Bioenno batteries. I'll continue to spend the extra dollars for the quality.

I'm using 5a 14v lipo commonly used in R/C vehicles. Very convenient with the IC705.

It really depends on what you were trying to test. It seems your test was actually a test of radio run time for the mode you were running. If you really want to test the battery capacity you need to know the full charge voltage, the cutoff voltage and a known load (current draw).

I'm not good with the battery maths but I like the test. I've got 3 Bioennos and have had a great experience with them. Thanks for the video.

I would look at cell resistance vs battery pack resistance. I would think the cells in a pack would be higher. Now 2x longer would be interesting. Now add in TX vs RX that timing vs other tests could be different.

Since both batteries have the same voltage the bigger one must have cells connected in parallel. Therefore, in practice the usable amperage is slightly higher because at the lowest discharge states you have two battery cells working together instead of one. Even though we talk in average wattage when turning on or off any device there's usually peaks or spikes. In my experience those peaks are better absorbed by multiple cells at low charge levels.

I power my Xeigu G90 with the 3amp hour battery. I average 6 hrs between charges. I am going to get a larger battery for POTA. Winter Field day I made 20 contacts in that 6 hrs at the full 20 watt output power of the radio. I love the Bioenno battery.

It’s probably the label, most of the labels Amp Hour ratings are a guarantee of power, the cells they construct it from are probably pretty decent cells.

When you did your original calculations you assumed 65% receive @ .45 amps and 35% transmit @ 2.31 amps. Then you summed them to 2.76 amps and used that figure to divide your 3 amp hour battery. That would assume a you're transmitting and receiving the entire time. You'd have to do 3 ah / [(.45 * .65) + (2.31 * .35) ], or 3 amp hours / 1.101 amps ~= 2 hours 15 ish minutes. At least, that's my best guess as to what went wrong with the estimation. Obviously, the actual power usage overtime may not align with the computed estimates.

Build a battery pack with several 12Ahr Bienno batteries wired in parallel. I'm also building a 150w Solar Panel Array with built in Solar tracker to keep the panels aimed at the sun. These will feed a 10Amp renogy charge controller and feed a 60w triband ham radio, an evolve laptop and a 6 station charger for hand helds. All of it except the 48Ah battery pack will fit in a mid sized pelican case and weight will not exceed 45lbs. Now to procure two carbon fiber tripods....one to mount the self aligning solar array and the other for the triband antenna. 65% of solar panel charge rate would be my break even point vs consumption @ 50% radio duty cycle. So Even at 25% duty cycle, I'd remain net positive battery charge.

I've been using Milwaukee M12 power tool batteries for some time. Now they offer 3A in the small package (1/3 of a banana). It is just 12V, not 13+ but t powers my KX3 at 10W for several hours, although I didn't measure it. As long as my little laptop lasts, FT8.

That "where did the current go in the 817" website shows that the lower the voltage, the lower the current used in both TX and even RX. In other words, the radio is less efficient at higher voltage. However, a battery goes from high to low voltage while still performing, it's not constant. But your estimation set it up as a constant, and that's why it's off. Another reason is that a good battery manufacturer will under-report the specs and if your battery is very new but already broken in, then it's going to have higher capacity than rated . Only bad manufacturers or brands would over state their specs. So this is the second reason.

You need to test at a 0.2C rate for the battery at 25 degrees Celsius. So the 3000mAh should be tested at 600mAX12V which is roughly 7.2W. That's the industry standard. When batteries get warm (30-40 Celsius) they will give about 105% to 110% of rated capacity. Controlling for temperature is hard but it causes funky results when people put cells in slot style charger/testers and don't have a fan running over the top of the cells. The two inside cells will typically test higher because they get warmer than the outside cells even if they are identical cells that should pull near identical capacity.

Thanks!

Why is this surprising? Ft8 has a 50% duty cycle. So it's really like you were keyed down CW for about an hour. The battery voltage drops toward BMS cutoff at a bit below 10v over that duration. While the radio is configured for 6w TX, actual output power drops along with the supply. So while this video shows practical endurance of this pack, the methodology isn't right for measuring actual pack capacity.

I am thinking max power transfer theorem. I don't know this, it's thinking outloud at you. So put another way the other also-ran's have an internal resistance that doesn't match the load (ft81x) But the lifePo4 with the premium choice of cells I suspect it is probably lower internal resistance. I would like a video showing the smallest portablest way to keep them properly charged. Like if say I had two one on the KX2 and the other on a roll-up solar panel and rf quiet solar charge controller. For the man-portable or sota context.

Love Bioenno

I used those batteries to power my game cameras, better than putting 8 AA's in them.

Watts don't matter batteries are not sized to watts, they are sized to amp draw. 3000 Mah is 3 Ah. (3000 ÷ 1000 mah to ah) so from this time of 2 hours, you pulled .66 amps for 2 hours. --- so figure out your amp draw from your watts output. Then you can accurately determine your battery size needs for the time desired.

Becouse... Science! 😮

To test a battery capacity properly u use a constant load say a light and use a battery capacity tester

Were those estimates from the video where you added transmit and receive currents when you should have time averaged them? I.e.; you need: battery_capacity / ( (i_receive * fraction_of_time_receive) + (i_transmit * fraction_of_time_transmit) ) = estimated_operating_time

Not sure what transmitter duty cycle you used in your calculation, but that might be it.

No fire yet??😮

That battery is tiny!... I got nuffin.🤷‍♂️😮

It’s a well known fact that 5 out of 4 people have problems with math.😊

If you need a fan should it not also be powered from the battery too?

How old is your battery and how much use has it had? Did your calculations allow of listening time?

Just wondering if the fan was also blowing on the battery?

It's an 817 or 818? I'm wondering how you get 6W out of the 817.

Oh Oh.....

Charging time matters. The lower the charging current, the more energy is stored. Not without influence is the fact that the battery was kept at the optimal temperature during discharge.

Hello my ham friend i having a better power solutions: USB-C powerbank + USB trigger with direct plug to radio for 12v or 15v i use Powerbank Baseus 30000 mAh 65W PD 3.0. This is best solution for portable use radio. U can always change powerbank in a car or home with regular usc-c charger.

how about 7300 at 10 watts

More impressive FT817 has major draw on receive