BJT - Switch Circuit

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This video discusses switches in general, shows how both an NPN and PNP bipolar junction transistor (BJT) can be used as an electronically controlled switch. The video then describes how to check that a switch is biased correctly (i.e., operating with the proper current and voltage characteristics) and finally shows how to design a simple BJT switch circuit

Опубликовано:

15 сен 2024

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Комментарии : 36

@jimedgar6789 Год назад

Excellent work! The 5 to 10 (Ib) I never knew. Perfect explanation. BAM! Take that BJT !

@03333628261 11 лет назад

You are the MAN! Bro you've solved my great problem, love your way of explaination!

@12torotoro 12 лет назад

The best explanation I seen thank you.

@EddieFox 11 лет назад

I'm designing a bridge motor circuit with 12volt supply and 1Amp motor. I used your formula with the gain characteristics of my O/P transistors etc. to work out base bias component values. This was amazingly helpful. Thank you

@Shakira4816 11 лет назад

The best video for BJT switch circuit!! Thanks!!

@xALIGx 13 лет назад

great explanation!

@enochrichbert3076 10 лет назад

Seriously usefull for learning basic design....Great

@thesotongball 11 лет назад

Thank you very much! Greetings from Singapore! :D

@jonnyschmidt5876 10 лет назад

Great vid, very clear and made it easy :)

@A99YearOld 11 лет назад

You are awesome, thank you!

@metaknightxd3 4 года назад

Finally clicked thank u

@mrdouble 9 лет назад

Thanks a lot. Nice explanation

@astorina 4 года назад

top video , thx from brussels

@ElectronXLab 4 года назад

Thanks Antonio!

@mohfa1806 8 лет назад

Hello david ...thank for the videos , they are really amazing....i have a question please : why we cant use the BJT as a switch in its active mode ? , since in the active mode we can also know exactly the value of IC also...am i missing something :).....thx

@ElectronXLab 8 лет назад

+Mohamad Fakhoury you could set your switch up so that it is in the active region when turned on. One problem is that then the operating point is dependent on beta. If beta changes from what you designed your circuit for, then Ic (which is your load current) will change too. If you make sure that your transistor is in hard saturation, changes in beta will not cause Ic to change.

@mohfa1806 8 лет назад

Thank you for your fast reply . Just to understand fully your answer : do you mean that beta changes within the same transistor ? . Thx

@ElectronXLab 8 лет назад

+Mohamad Fakhoury Yes, beta is temperature dependent, so can change for the same transistor.

@mohfa1806 8 лет назад

its all clear now.....thank you very much

@marxl19 5 лет назад

when the transistor is working in active region.then the transistor will waste a lot of energy too

@mohamedasaad2837 5 лет назад

David could you explain how to design H-bridge circuit ?, it is little bit hard in calculation (Designing) espacially when i tried to calculate the IC and VCE and what make it hard as i think that i am also not famlier with calculating circuit which not common emitter neither common collector

@alperenalperen2458 10 лет назад

Decent explanation

@mazyarsalehi7699 6 лет назад

Thanks for your very useful videos. May i ask why did you choose the IB five times greater than IC over beta?!

@josymarpereira4904 7 лет назад

Is it when Vin is 0v that is in cutoff or when Vout is 0v?

@michaelcostello6991 4 года назад

So the saturation current of 400 mA is determined by the motor rating (10V and 400mA). The transistor itself might be capable of conducting more than 400mA ?

@stefanopassiglia 6 месяцев назад

It depends on the transistor. The design here is that you need to use a transistor capable of 400mA or more.

@michaelcostello6991 6 месяцев назад

@@stefanopassiglia Thanks

@demersjeff 12 лет назад

Nice video Dave! P.s who's Brenda?!?!

@divya7520 7 лет назад

Hi , what do mean by Vce here ? (collector to emitter voltage difference ? but both collector and emitter will be of same n type . ) whether there will be any potential difference ? I don't understand Vce ..

@stefanopassiglia 6 месяцев назад

Yes collector to emitter voltage. See the other videos to understand