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The correct answers are 3.23A for I1 and 3.54A for I2. Because you want proof of these answers. 7*3.23 - 3*3.54 = 11.99V and -3*3.23 + 5*3.54 = 8.01V. Your answers give for the second equation -3*4.38 +5*6.23 = 18.01V. This should be 8V and not 18V. You filled in the wrong voltage for the second equation. You also use a rather strange form of Cramers rule for I2.
for some reasons, the current rises from negative to zero instead of falling from 1.5 mA to Zero, which isnt the typical charging function of the Current in a Capacitor... its the discharge function. i dont get why the Current function is delayed like that. what did i forget?
Other calculations have wanted an efficiency rating as on a motor's tag. This suggest I can use the resistance and perhaps derive the reactance and use those numbers to size a cap.
It would be helpful if you refer to the spec sheet for transistors. how do you know what I(sat) is? spec sheet for a 2n2222 doesn't show I(sat). Otherwise it is a very good tutorial. makes me remember what I for got.
I have a simple question, and it may depend on its application. But what if we supply(Vin) to the negative(-) input instead while the positive(+) terminal is tied to Vout. I believe this configuration is also Vout = Vin ? It's more common to supply the positive input... why is it ?
Sir, I did not learn a bit. I have in fact learned A LOT. Thank you so much for this explanation. My finals are in a few days, and you have accelerated my learning.
I love how you explain your answer for this problem. I hope you can create more example problems concerning different theorems (Branch current, maxwell, kcl/kvl, nodal analysis, superposition, thevenin and norton's).
Wouldn’t ZL be at -90 degrees and ZC at 90 degrees, according to the ELI and ICE acronyms saying that the current of inductors lags the voltage and that the current of capacitors peaks before the voltage (on a phasor diagram)?
THANK YOU for demonstrating a single power supply schmitt trigger, I had to look around quite a bit to find your video. everyone with an op amp in their hand tunnel-visions thinking you MUST have a dual power supply if you're using an op amp.
Awesome video. I would note that you can get an easier and quicker answer to solving the circuit by doing KVL in each loop and solving for currents 1 and 2, Since these elements are assumed to be behave linearly. By getting currents 1 and 2, you can solve the corresponding voltages across the resistors. I solved it this way and i got the same answers. Knowing this, i am just confused as to what came first and how to connect these ideas. Does KVL incorporate superposition through the currents ? OR is it better to think about these ideas separately?
FYI “watch your p’s and q’s “ comes from the days of typesetting. In those days you set the mirror image of text you were setting using separate little metal characters. It was easy to confuse or flip a letter upside down. So the p, q, d and b always required extra attention as they were all easily mistaken. (Crap I’m old!)
You know, i've been beating my head against this problem for years. I work on batteries for a living and so was always assuming the voltage stays constant throughout the entire discharge
