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hey after we are done from the while loop and we start checking if the reverse is equal to our main number, why we didn't compare the num directly with the rev? why you assigned n to num the compare n to rev? I tried it and it gave me a wrong answer
Hey, this tutorial is very helpful. But, how would we change the code if we want to use a negative number? Ex: if num = -121, then rev should equal 121-, and should output not palindrome.
Thanks Ronak. There's a scientific reason to not go with dark theme with doing video recording. That's because the text on dark theme is not as clear as text on white theme especially at lower resolutions. You can try to verify this. Personally I love dark theme myself. It's just not optimum for video recordings 😊
Write a menu based C++ program to do the following operations using dedicated user defined function for each operation. a) square of a number b) factorial of a number c) whether prime or not d) whether even or not e) whether palindrome or not Plz solve this 🙏🙏
Wow buddy, that you so much for such a wonderful response. I'm so happy to hear your positive feedback and to know that this video was informational for you. Do share the videos with your friends and contacts and keep sharing the knowledge buddy 😇
Sir, you could please make a video regarding palindorm in C++ using stack... and one issue with this code is that for the first time the result is correct but when I used do while loop for asking the user whether they want to repeat this process or not, for the second time the result is incorrect for the same palindrom number.
+Aryan Madhav Verma thank you so much buddy for such a positive feedback buddy. I'm sure you'll do great in your exam 😎✌😇 all the best and do share the videos with your friends so that it'll help them as well 😎
It should workout fine buddy. There's no alternative that I have tried but you can google palindrome program for C++ and you will get it. Also try downloading this Dev C++ IDE and try it there. I should work. Lastly you basically know the logic and algorithm of how it works right. So maybe you can try out some other possible combinations to see if it works. ✌
Hello, in the last iteration num=1 correct. so lets try and dryrun the part inside the loop. in the first line we have : digit = num%10. % sign is mod sign which will give us the remainder and not the quotient. so 1mod10 = 1 so digit = 1 now on the next like we have rev = (rev*10)+digit. rev was already 12 so multiplying it by 10 we get 120 and adding the digit variable which is 1 we will get rev=121 last statement is num = num/10 now / is for division so we get the quotient. num is 1. so 1/10 = 0. so the new num =0 so when the loop again tries to execute we have num=0 hence the loop execution stops as the while loop executes only till the num is not equal to 0. which means the moment num=0 the loop will stop iterating. thats why I didnt emphasize much on the last step
While solving for 202 in second iteration I got 10 and at the 3rd iteration I got 20, by 1 and 3 iteration by adding it will be 202 I guess but what about that 10?? at the second iteration
Computer doesn't understand like human because as we know that the reverse number of 121 will be 121 But computer' result wil outcome By some mathmatics calculations....
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Aisa Program type krne k kya faida jo read hi nai kiya ja sake. Bhai sahab apne jo program type kiya hai logon ko usko read krne me Microscope ka use krana prega.
