I congratulate you from the core of my heart. Your dynamic eloquence and the way of teaching is very fine and attractive. Surkhuru hota hain insan thokrein khane ka baad, Rang laati hain heena, patthar pe ghis jane ka baad. Aap ka aana dil bahlana , sahi se tricks shikhana, dil aagaya re dil aagaya. Ye dil mange more.
Thankyou sir I am form Odisha 🙏🙏🙏 and I wants more blessings from you....🙏🙏🙏🙏🙏🙏🙏🙏 Sir you are the most popular mathematics teacher and reasoning teacher....sir I am so proud , bucoz I have a excellent reasoning teacher 🙏🙏🙏🙏 please blessings me your voice is magical
I have been following most of your videos and I find them very interesting and educative. Wish such knowledge and videos were available during my younger days. I am now retired and yet I love to acquire knowledge. Do you have any published books which I can buy for studying and for practice? Please let me know. Today's generation is really lucky. So many career options and so many options and methods to study. Anyways my best wishes to the present generation of boys and girls and hope they take full advantage of the facilities available to them.
Sir, you are amazing. I am an NTSE aspirant, currently in grade IX. This was the only chapter of MAT which I was facing problem with and after watching your video I can say that I have mastered every topic all the concepts of Mental Ability both verbal and non verbal
Really helped a lot and i use to watch all ur video it really helps to understand logic very easily and feeling very happy.... Your class made my interest towards studies much better sir....
I was never able to solve any questions related to calendars.. I'm glad I came across your video. You have taught the concept in very easy manner. Thank you so much Sir.❤🙏
Thank you so much sir.... 🙏🙏🙏🙏🙏Jo chiz aaj tak samaj nei payithi.... Aaap 15 minutes me samjha diye...... Jitna v thank you kahun kaam padjayega..... God aapka bhala karen aur aap aise hume padhate rahiye.. 🙏🙏🙏Love from Odisha❤ Jay jagannaath 🙏
It is a good session for me and also for all subscribers. I have a little doubt on calendar. Can you clear that ? How to find out the year code,what will be year mentioned in question? I am so happy to get some lessons from you,that helps me. I request you to make a video on calendar. A date is given, question asked in which year the same date will be repeated.
Thank you Imran sir you are helping to study for Sainik school entrence exam because the maths subject is very tough for me but you have do it. Very easy Thank you very much sir ones again.........
Sir... Please create one more video about calender and teach us more examples... Fr example like 1 jan 2010, 28 may 2006, or 1 jan 2008...bcoz I'm not able to find out this questions answers...
Respected sir, kindly take remaining types related with calender. Viz; (1) 1Jan 2019- Mon 1Jan 2020- ? (2) 15 Mar 2018- Mon 10 Oct 2018- ? (3) 10 Jan 2013- Thursday 10 Jan 2018- ? Etc.
Sir... Please create one more video about calender and teach us more examples... Fr example like 1 jan 2010, 28 may 2006, or 1 jan 2008...bcoz I'm not able to find out this questions answers...
Thank you soooooooo much for your teaching way .it's too easy to find such dates with in very few seconds .once again thank you very much keep going on....
God bless you. you are really doing very nice work to encourage students to face examination without fear. Tricks showing for shortcuts though are wonderful but easy and very helpful. Continue अच्छे काम का अच्छा फल मिलता है l
We can make solution more easy by finding remainder of date, year quotient (by dividing by 7) while applying formula in place of adding and then dividing by 7
Every thing need to be remembered in your video. There is no logic, but it is pure math. Let us see,, how.... As u know, day of week is Mon 1, tue 2. ....... Sun 0 Leap year , if divisible by 4, but century year divisible by 400 is leap year with complete logic .. 1 simple year= 365 day/7.. Remainder 1. Leap year ..366/7.. 2 okay. 100 yr= 100 + (100/4=24, not 25 as 100 is not leap year) That is 100+24= 124/7=5 day remainder 200 yr= 5×2/7= 3 DAY 300 years=5×3/7=1day 400 years .. 0 day REMAINDER AND SO ON.. As 400YR=5×4+ 1 (being leap century yr)/7= 0 remainder So 800, 1600, 2000 yr gives 0 day.. 1900year=1600+300=0+1=1 is remainder Jan 31/7= 3 , feb 28/7=0 leap feb 29/7=1, mar 31/7=3, ...so on Dec 31/7=3 Now 15 Aug 1947 Completed year 1946, in year1947, Jan3+feb0+mar3+april 2+may 3+jun 2+jul 3+aug 15= 31/7 remainder 3 To find day, from above 3 is for aug 15, 1 for 1900, 46 ordinary year, 11 leap year Add 3+1+46+11=61/7 remainder 5 mean friday. Hope it is clear. No need of remember any thing ..
