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Carbon 13 NMR 

Allery Chemistry
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Carbon 13 has never been so important. It's certainly important when it comes to NMR! Watch this video to find how to interpret spectra and why TMS is so important to NMR.

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26 июл 2024

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Комментарии : 33   
@msshikable
@msshikable 8 лет назад
The perfume analogy was genius. Would have never thought of it that way! Thank you so much for making these videos!
@AlleryChemistry
@AlleryChemistry 8 лет назад
+Shika Brilliant! I did wonder if it made it easier to understand. Just the way my mind works!
@alimirza6379
@alimirza6379 8 лет назад
you are the most helpful teacher i have ever had!!! thanks a lot
@abrahamadinya
@abrahamadinya Год назад
7 years after it's still so relevant Thanks alot 😅
@AlleryChemistry
@AlleryChemistry Год назад
Nothing has changed in that time believe it or not! 😀
@ayushuprety5676
@ayushuprety5676 6 лет назад
You are great.i respect you very much for all the hard work you put on to make these videos.
@WithFaizanKhan
@WithFaizanKhan 7 лет назад
May God Bless You For Your Efforts
@joshhubbuch8352
@joshhubbuch8352 3 года назад
This is Fantastic, You're one hell of a teacher!
@hillaryantwi9279
@hillaryantwi9279 4 года назад
So helpful. Thank you
@AlleryChemistry
@AlleryChemistry 4 года назад
Glad it was helpful!
@sananabiuni6365
@sananabiuni6365 6 лет назад
Perfect 👌
@mastereruthien2656
@mastereruthien2656 6 лет назад
Very good vids to revise stoned mate guy talks nice and slow and very clear explaing every bit of the white board mate ur a donny, keep it up.
@Dr.Freeze
@Dr.Freeze 3 года назад
😂😂😂
@aki957
@aki957 8 лет назад
thanks
@shivanibhanderi1228
@shivanibhanderi1228 3 года назад
you are the best . thank you!
@rohitkumar-et3np
@rohitkumar-et3np 6 лет назад
thanks..
@mohammedibrahim4900
@mohammedibrahim4900 9 лет назад
Hey Chris, when you say "depends on what the carbon is next to" are you referring to what the carbon is bonded to?
@AlleryChemistry
@AlleryChemistry 9 лет назад
Mohammed Ibrahim Yes as neighbouring atoms will affect the shift on the spectrum.
@mohammedibrahim4900
@mohammedibrahim4900 9 лет назад
Also, when we talk about the shielding effect, can we refer to the electronegativity of the element next to Carbon when describing the amount the shielding we have? Like for example when you said, "Oxygen is deshielding", could you have said, "Oxygen is more electronegative, and thus pulls away the electrons"?
@AlleryChemistry
@AlleryChemistry 9 лет назад
Mohammed Ibrahim Yes that is correct.
@mohammedibrahim4900
@mohammedibrahim4900 9 лет назад
A Level Chemistry Revision Videos Alright, thanks a bunch. Your videos are extremely helpful. :)
@AlleryChemistry
@AlleryChemistry 9 лет назад
Mohammed Ibrahim No problem. Please spread the word, the more people they help, the better. Follow me on twitter if you have it news on up coming videos are published there first. @allerytutors
@drshehryarmohsin.2003
@drshehryarmohsin.2003 Год назад
How many absorptions of carbon 13 would be for 2,2 di methyl propanal
@user-vp1su4iz3u
@user-vp1su4iz3u 3 года назад
at 6:00 you say that the last carbon with the -OH next to it is less shielded so more affected, but the writing on the right says if it's less shielded so therefore less affected? I'm not sure if I'm misunderstanding or if one of them was a mistake
@mwinikamchedzera3569
@mwinikamchedzera3569 2 года назад
WE LOVE YOU CHRIS HARRIS
@SweetChemistry
@SweetChemistry 7 лет назад
good work I used the video image on my channel but did not know you were using it Do you mind?
@ellansa4178
@ellansa4178 4 года назад
my guy
@eGazTheFirstAustralian
@eGazTheFirstAustralian 10 месяцев назад
But what is NMR?
@Sibasish07
@Sibasish07 5 лет назад
Only if proton nmr wasn't enough! 😑😢
@goharkhan2627
@goharkhan2627 8 лет назад
Sir are you phd or smth?
@AlleryChemistry
@AlleryChemistry 8 лет назад
+Gohar Khan Ha, no. No PhD, just an honours degree and a few years of teaching.
@WithFaizanKhan
@WithFaizanKhan 7 лет назад
PHDs Dont Prove Anything.
@Sheena1234ization
@Sheena1234ization 4 года назад
Sort out that £4 mic and echo then these videos would be UNBEATABLE
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