Charging a capacitor 

I came to your most recent video just to tell you you are the man. Intelligent, attractive, charismatic, and just straight up contributing to the collective enlightenment of other humans through science. This man deserves maximum vindication for his efforts!

Thanks, Prof. Matt Anderson. You are really a professor You must be my teacher one day.

Semma🔥Explanation! Feeling bad because I don't have(can't find) a Physics Teacher in my school and college days

In discharge: V2/Vc = e^(-t/rc) In charging: V2/Vc = 1- e^(-t/rc) If I had a big schematic to design, these were fast, conditioned response. I did it for money at a lot of companies, designing power supplies and battery chargers from 1977 to 2008.

Thank you sir this one helped for exams

For some reason this guy reminds me of Christopher Reeve/Benedict Cumberbach, anyone else?

When the capacitor is charged through the resistor there will be an energy loss in the resistor. That loss is exactly half the energy in the capacitor when fully charged. It seems surprising that the loss does not depend on the resistors resistance. So what happens when the resistance is zero? An infinite current, a singularity? In real life we would get an oscillation because there always is a self-induction and energy would be radiated. It means that in a world where we assume there is no inductance while we have capacitors our theory must be incomplete.

So nice

Who else thinks he looks a bit like Tom Cruise???

Very helpful sir

am i the only one freaked out by him writing backwards, like so we can read it, not him??

WOW !

OMG it is because of teacher like this that I ran.

Does the capacitor pushes the amps that the load needs or more then it requires?

Seems like I am the first viewer 🎉 Thanks sir for these awesome videos

Professor, if there is no flux accross the capacitors, so how does it 'conduct' electricity through it ?

By what i mean a load max is 3 amps does it only pushes 3 amps or does the capacitor pushes more than 3 amps

👍👍

What happens when you charge a capacitor that has charge on it lesser than the potential of the battery?