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China | Can you solve this ? | A Nice Math Olympiad Radical Simplification 

Learncommunolizer
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This is an interesting question that tests a lot of concepts!
Hope you are all well
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• Maths Olympiad
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‪@profreginaldomoraes‬
Questão de Matemática Olímpica || Isso é da China? || Matemática
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Опубликовано:

 

24 июн 2024

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Комментарии : 8   
@ichdu6710
@ichdu6710 3 дня назад
an amazing solution. also an amazing discovery is; you can solve this directly by squaring the given fraction, square the result two times and multiply with the fraction at last
@nkverma1577
@nkverma1577 3 дня назад
No sence
@user-fb1qo8go1b
@user-fb1qo8go1b 3 дня назад
Как всегда интересною. Спасибо! Удачи!
@Rosomaxa-wu2ps
@Rosomaxa-wu2ps 3 дня назад
Wunderbar
@deckexcellentfoundationaca2390
In fact this solution is nonsense. The answer is simply 1. What were you solving
@michaelblankenau6598
@michaelblankenau6598 День назад
In fact the answer is NOT 1 … what were YOU solving ?
@sirikumaradayananda368
@sirikumaradayananda368 2 дня назад
😜
@gabrielebariletti6045
@gabrielebariletti6045 9 часов назад
more easy, and logic too: ((5^(1/2)-1)/2)^9 ; ((5^(1/2)-1))^2 * ((5^(1/2)-1))^2 * ((5^(1/2)-1))^2 * ((5^(1/2)-1))^2 * (5^(1/2)-1) ; ((5^(1/2)-1))^2 = 2(3-5^(1/2)) => (2(3-5^(1/2)))^2 * (2(3-5^(1/2)))^2 * (5^(1/2)-1) ; (2(3-5^(1/2)))^2 = 8(7-3*5^(1/2)) => (8(7-3*5^(1/2)))^2 = 128(47-21*5^(1/2)) ; 2^(7)*(47-21*5^(1/2)) * (5^(1/2)-1)/2) = 2^(7)*4*(17*5^(1/2)-38) => ((5^(1/2)-1)/2)^9 = (2^(9)*(17*5^(1/2)-38)) / 2^(9) => ((5^(1/2)-1)/2)^9 = 17*5^(1/2)-38 = circa 0,013156 C.V.D. as we wanted to show !
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