China | Can you solve this ? | Math Olympiad 

Simple pq formula: x1,2 = - (p/2) +/- SQR((p/2)²-q) x1 = 33333, x2 = - 33334

everything is fine, but once the factorization has been obtained, Vieta's theorem can be applied. You can also simply factorize the free term so that they differ by one 1111122222=11111*2*3*16667=33333*33334. And also apply Vieta’s theorem.

Excelente explicación en el idioma de los números y sus reglas. COMO SE DICE EN MI PAÍS: MÁS CLARO ECHALE AGUA👌👌👍👍👍

The sound of the roster in the background makes it even more exotic :)

Excelente "saída" para a equação. Está aí a beleza da matemática. Parabens professor.

Решение хорошее,но очень много лишних преобразований,к тому же сложных.Две скобки (7:02) можно было получить значительно проще.

If you add 3*3+3,you get 12,in the same way if you multiply 33 with 33 and add 33 you get 1122,in the same way if you need to get 1111122222(that is,five 1's and five 2's)your answer must be 33333(five 3's)

Beautiful prob.

Same idea but I had assigned y = 3*11111 along the way. Then x(x+1) = y(y+1), (2x+1)^2=(2y+1)^2, so x=y or x=-(y+1). Nice problem.

I solved by realzing it is X(X+1) which is two consecute numbers. The square root of 1111122222 will be between them andthe answer is the lower of the two numbers.

I solve it💪

Танзанийские мотематеги оказались круче индийских мотематегов!

Why you substitute or used the y nothing to do with the equation

Sem finalidade pratica

استاد عزیز سرعت شما زیاد است وپرش داری

Log2 + x = 1,111,122,222

brother just solve the quadratic the usual way at this point

х1=33333; х2=-33334.

11111

X=33333.

이해안가, 인수분해가 어떻개돠지????

who cares?? not pratical