Clipper Circuit Explained (with Solved Examples)

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In this video, the diode clipper circuit has been explained. And few examples on the clipper circuit has been discussed.
By watching this video, you will learn the following topics.
0:20 What is Clipper Circuit? Applications of Clipper Circuit
1:14 Types of Clipper Circuit
2:00 Parallel Clipper Circuit
4:06 Parallel Clipper Circuit with Biasing Voltage
10:23 Series Clipper Circuit
11:21 Series Clipper Circuit with Biasing Voltage
13:16 Example 1
15:19 Example 2
What is Clipper Circuit?
The Clipper Circuit prevents the output waveform from exceeding the certain level and at the same time, it does not distort the reaming part of the waveform.
Application of Clipper Circuit
The Clipper Circuits are used in the wave-shaping circuit and the voltage protection circuit.
Types of Clipper Circuit
Depending on which portion of the waveform (Positive or Negative) is clipped, the clipper circuit can be classified as
1) Positive Clipper Circuit
2) Negative Clipper Circuit
Further depending on the placement of the diode the clipper circuit can be classified as
1) Series Clipper Circuit
2) Parallel Clipper Circuit
In this video, both series and parallel clipper circuits (with and without biasing voltage) have been discussed and few examples based on the clipper circuit has been solved.
The link for the other useful videos:
1) Voltage Multiplier Circuits
• Voltage Multiplier Cir...
2) Zener Diode
• What is Zener Diode ? ...
3) Half Wave Rectifier
• Half wave Rectifier Ex...
4) Full Wave Rectifier
• Full wave Rectifier Ex...
This video will be helpful to all the students of science and engineering in understanding the clipper circuit.
Follow me on RU-vid:
/ allaboutelectronics
Follow me on Facebook:
/ allaboutelecronics
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/ all_about.electronics
Music Credit:
www.bensound.com/
#ClipperCircuit
#DiodeClipperCircuit
#DiodeApplications

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Опубликовано:

16 апр 2019

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Комментарии : 295

@ALLABOUTELECTRONICS 5 лет назад

The Timestamps for the Different Topics Covered in the Video. 0:20 What is Clipper Circuit? Applications of Clipper Circuit 1:14 Types of Clipper Circuit 2:00 Parallel Clipper Circuit 4:06 Parallel Clipper Circuit with Biasing Voltage 10:23 Series Clipper Circuit 11:21 Series Clipper Circuit with Biasing Voltage 13:16 Example 1 15:19 Example 2

@ngkean9743 4 года назад

Btw how u know where to put.... The horizontal line V of bias

@aaryan3461 4 года назад

studying this one night before the exam lol

@younothing236 4 года назад

omg same

@abdullahalqusis6899 3 года назад

Same 🤦🏻‍♂️

@DasCODE 3 года назад

😑I am here to complete my assignment

@karunarabha8714 3 года назад

I am here to complete my mini project.. Lol😆

@ranakashif2700 3 года назад

And i am here to prepare shortly only for online class 😁

@420ZEO 4 года назад

perfect video better then my teacher.. thanks alot

@ryanpwm 4 года назад

Well this guy certainly knows about clipping. You can hear it in the audio.

@kunalverma3009 3 года назад

Lmao 😂

@visheshverma8065 2 года назад

i have exam tom and i am laughing everytime he says "it will turn on"

@joetan7023 3 года назад

Informative and very straightforward. Keep up the good work!

@reajis4998 Год назад

@milzex2082 4 года назад

I have been looking for this for so long thanks

@ardra1219 4 года назад

Brilliant way of teaching...hats off

@virajgoyanka5150 3 года назад

Its 8:53AM and My test is at 9:30 AM and I am done with video!! This topic has High weightage..I really studied max topics from ur channel after getting result I will update this comment.!! AMAZING CONTENT!

@atom8509 2 года назад

When will u upadate this comment ?!

@nitishguptarbl 2 года назад

@@atom8509 🤣🤣🤣🤣

@aktiwari3379 Год назад

@@atom8509 😂😂😂

@saitamapreetsingh3057 Год назад

Bhai kitne number aye ?

@43nileshmahajan18 Год назад

@@saitamapreetsingh3057 i don't think he will reply now🙄😂

@sidharthguptax 2 года назад

I watched many videos of yours, they are awesome. I'll recommend these forever.

@siddharthgarg1495 4 года назад

Very good , calm and full of concepts vedio....excellent work

@kshitizkaushik1862 3 года назад

you know you are very underated today i found your channel and yes subscribed it too. helped me a lot

@ShriPhotographyOfficial 5 лет назад

how you edit your videos?

@srujaniam9762 4 года назад

thanks a lot sir definitely solved a lot of doubts and cleared a lot of misconceptions . keep up the work.

@mohitrawat7762 5 лет назад

Thanks sir it help so much

@machiElectronics 5 лет назад

Thanks sir nice and simple

@alpha-yb7en 3 месяца назад

for the first example i dont understand why the zeiner diode turn to an short circuit ( instead of open circuit ) when Vin < 0v ???

@amitghosh1213 4 года назад

one of the best

@avynkarlespino941 3 года назад

Thanks a lot... Your the best.

@wansegamat3064 4 года назад

this video very helping for understanding clippers circuit.. many thanks

@shubhammanna 4 года назад

Does all the clipper clamper circuit have zener diode? Coz i needs input voltage more than diode activation voltage

@ALLABOUTELECTRONICS 4 года назад

You can also use additional voltage source (with diode) to clip or clamp the waveform at the desired level.

@naiemataliep9142 3 года назад

hi, for example 2, i got the reverse version of your graph ie. my pulse was on the negative side, is this fine? I assumed this was because the direction I chose to be my positive and negative cycles were opposite to yours. Does this matter?

@035belekaiserahmadkhan2 2 года назад

bro I am also facing the same problem...so do help me out if u got the reason to it

@sunandachowdhury1455 2 месяца назад

Can someone please explain the last example? I did not get it :((

@vanikians4585 4 года назад

sir last k dono example paralllel k lg rhe the to series k concepts kyu lga h

@acapjumpen 4 года назад

Hi there, thanks for the informative video! Can I check why the Vin need not be larger than (0.7 + 0.5)V? To account for ideal diode voltage + bias voltage. Why is it only accounting for bias voltage (0.5) ?

@indianlad23 5 месяцев назад

If you've found the answer, pls do share with me

@learn8614 3 года назад

But consfused regarding zener voltage problem

@sandeepkumawat4982 4 года назад

why is the condition Vin

@baikannikitha1897 3 года назад

Thanks a lot sir, u r explanation with examples help me a lot

@mahamatdjibrine95 4 года назад

many thanks

@Rahulkumar-yg5wr 4 года назад

You can tell me , why In the parallel clipper ckt, when +ve half cycle is applying in the ckt the ckt work as a short ckt ? What is the working of resister her ?

@ALLABOUTELECTRONICS 4 года назад

The R is the current limiting resistor. And here during the analysis, it has been assumed that the diode is ideal. That means when it conducts it acts as a short circuit. But actually in the output when the diode is conducting, the voltage would be around 0.7V. I hope it will clear your doubt.

@HarshaAbey 4 года назад

thank you

@chethank8716 2 года назад

0.7volt is shown in time axis?

@shan_singh 4 года назад

15:50 Why will it get forward biased????? It should be reverse biased and should act like an open circuit !! Please someone explain!!

@ALLABOUTELECTRONICS 4 года назад

The input is triangular wave and it is gradually increasing to 12V. But during that rise in the voltage, when the input is less than 5V, the voltage at the cathode of the diode will be less than 5V. While at the anode voltage is 5V. So, for that duration when input is less than 5V, the diode will get forward biased (considering ideal diode). And for that time it will conduct. That means when Vin < 5V, Vout = 5V. I hope it will clear your doubt.

@sreeharibalachandran 2 года назад

Thank You :)

@aaryan__bondekar9778 9 месяцев назад

at 4:30 wont R affect the voltage at all? how can we directly compare V and Vin

@ALLABOUTELECTRONICS 9 месяцев назад

It restricts the flow of current through diode. When the diode is conducting, then remaining voltage will drop across this resistor. (e.g Vin - V will drop across the resistor, when diode is conducting.) I hope, it will clear your doubt.

@balakaladabk8450 Год назад

12:43 series clipper with biasing , the signal not get clipped , it get smaller form .why?

@ALLABOUTELECTRONICS Год назад

The series clipper circuit clips the certain portion of the waveform (in time domain), much like a rectifier. Similar to the rectifier circuit, here the diode will conduct when the voltage across the anode of the diode is more than cathode. And during the ON time of the diode, the output voltage is Vin - V (assuming ideal diode for a moment). That is why you are seeing the reduced voltage during the conduction of the diode. I hope, it will clear your doubt.

@PradeepKumar-bc1ez 5 месяцев назад

Good explanation

@snigdhadhar32 2 года назад

Loved it

@recazamgarh3110 2 года назад

Nice explanation

@learn8614 3 года назад

Thanks a lot

@swarnadeepbiswas9303 3 года назад

Nice presentation

@imugandhar Год назад

Seeing this video on November 10 th the day before my semester examination

@rajneeshpatwa9365 3 года назад

thanks bro

@dalenassar9152 2 года назад

Can typical zener diodes handle higher ac frequency sine inputs in the 100kHz range? THANKS FOR THE GREAT VIDEOS A+++

@abdulbaseerabbasi3443 2 года назад

I may have learned something But I have learned "during this time" a lot more

@ramanand6836 3 года назад

thankyou sir for such a nice explanation

@mohitrawat7762 5 лет назад

Sir in circuit 6:47 what graph when we reverse V attach to diode

@ALLABOUTELECTRONICS 5 лет назад

The Vout = -V, when Vin > (-V) And Vo = Vin, when Vin < -V

@hemantbagani1248 4 года назад

Completely satisfactory

@ngkean9743 4 года назад

about the last one....how does it V less than 5 V diode able to conduct?

@ALLABOUTELECTRONICS 4 года назад

When the input is less than 5V, then the cathode of the diode is at less than 5V, while the anode is at 5V, so the diode will conduct.

@huyhq_official1601 2 года назад

Thanks soooo muchhh

@AmarSingh-rq7rj 3 года назад

Great explanations

@mhusain6185 2 года назад

very nice

@Rahulmohan-mv6nq 3 года назад

nice simple

@ayushmishra1973 3 года назад

3:40 sir no effects on positive half cycle will be seen for non ideal diode?

@ALLABOUTELECTRONICS 3 года назад

No, there won't be any effect during the positive half cycle. Because if you see, during the positive half cycle, the diode remains in the reverse bias condition. I hope it will clear your doubt.

@ayushmishra1973 3 года назад

@@ALLABOUTELECTRONICS Thank a lot sir

@enthusiastic_7 3 года назад

In example 2 when the Vin less than 5V the Vout is 5V ..I have some doubt in that part .Is there is no effect for Vin in Vout when the Vin less than 5V .I think Vout =5V -Vin when Vin is less than 5V..? Pliz clarify this part..

@ALLABOUTELECTRONICS 3 года назад

The input signal plays role in turning on or off the diode. (Here it has been assumed that the diode is ideal diode). Depending on the conduction of the diode, the output will change. Vout is the output across the one terminal of the diode and reference node. You can simply find that voltage by applying the KVL. You can also simulate the same circuit and check the result by yourself.

@cheerladinnemouli2864 4 года назад

Good lecture sir keep on upload the videos

@nerdyboy2443 7 месяцев назад

Sir, if it is possible for you then please playlist for all the topics. It is hard to search all topics separately. But if you arrange them in a playlist then it would get easy for us access your content.

@ALLABOUTELECTRONICS 7 месяцев назад

It is already added in diode and diode circuit playlist. You can check it on the playlist page.

@ramanababugorli3077 Год назад

Draw circuit diagram of positive clipper with VR = 3V and Vi=5Sinwt can you drawn this sir

@indianlad23 6 месяцев назад

I am too looking answers for question like this. Where do I get them?

@eee_bangla 5 лет назад

Please make a video on communication for radio frequency...

@LearnandEarn-dl4ok 8 месяцев назад

At 14:08, Should the sign of zener diode not be be opposite? I think you have made a mistake declaring the sign of the zener diode. Please check it and tell me if your example 1 is correct or not

@ALLABOUTELECTRONICS 8 месяцев назад

When the Zener diode operates in the breakdown region, then the voltage across it is equal to the Zener voltage. The polarity is correct. For more info, please check this video on Zener Diode: ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-MZPeRlst8rQ.htmlsi=f3Nb-aHyhqGYlhw_

@vanikians4585 4 года назад

sir you hàve taken àll diodes ideal in series circuit?

@ALLABOUTELECTRONICS 4 года назад

Yes.

@aryanmishra399 4 года назад

11:33 It shouldn't be (Vin)-V>0.7? Please explain Sir!!

@ALLABOUTELECTRONICS 4 года назад

Here the diode is assumed as an ideal diode. If it's not, then yes, Vin - V should be greater than 0.7V.

@Ramu-mv8co 3 года назад

Guys, in parallel clipper circuit in reverse bias the voltage is not zero..... Whereas in series clipper circuit in reverse bias the voltage is not zero na .....why? Like this can anyone explain me

@jackyunlucky8432 3 года назад

Thank you , appreciate it

@Rukaya_99 2 года назад

Apply a triangular input signal using function generator to a biased series positive clipper and draw the output waveforms. ممكن حله

@aaliya9652 4 года назад

At 7:53 when V in

@ALLABOUTELECTRONICS 4 года назад

When Vin is between V1 and -V2 both diodes are reversed biased. If you see, the diode D1 will conduct, when the voltage at the anode is greater than V1. Similarly, diode D2 will conduct when the voltage at the cathode is less than -V2. That means when the input voltage is in between V1 and -V2, both diodes will be reversed biased. I hope it will clear your doubt.

@Kiran..153 2 года назад

Who all are the night before internals 😂😂😂😅

@tezuphysics8960 4 года назад

It is great

@kg3217 4 года назад

Sir, at 10:22 how will the zeners work the same way?

@ALLABOUTELECTRONICS 4 года назад

During positive half cycle one zener will work as normal diode while the second one will work as zener diode. So, it will clip the waveform at vz+ 0.7 v. Similarly on the negative side, the voltage will be clipped at (-Vz + 0.7)V. By selecting the proper value of Vz, the circuit can be used for the clipping the waveform at the desired level.

@kg3217 4 года назад

@@ALLABOUTELECTRONICS thanks Sir/Mam, i understood that by browsing other sources as well, but thanks for your reply, it solidified my understanding.👍

@user-cw6ri8pp3y 2 года назад

If diode is silicon diode..out voltage how

@owen7185 3 года назад

excellent lecture

@kkrnagula8234 3 года назад

Hlo sir Does the diode in all types of clippers acts like a switch?

@ALLABOUTELECTRONICS 3 года назад

As its name suggest, it clips the input signal. When diode conducts, the voltage drop across diode is 0.7V. And in this way, it restricts the input voltage.

@kkrnagula8234 3 года назад

@@ALLABOUTELECTRONICS sir I didn't get it

@microchipdotpk Год назад

hello sir, can we also use a Zener diode as a threshold voltage reference to conduct the diode?

@ALLABOUTELECTRONICS Год назад

You mean to say, using Zener diode as a reference voltage, you want to conduct another diode, right ? If so, then yes you can do that. But it depends, how you cannect them in circuit ?

@arpan6246 5 лет назад

I m here after learning that this is in AIIMS mbbs entrance syllabus

@aaliya9652 4 года назад

Now it won't , cuz it's combined with neet

@pranathia4266 9 месяцев назад

Studying this one night before an interview 😂

@anjaanmusafir9977 3 года назад

Mein bas itna kahunga Charan kahaan hai aapkeeeee ........

@abhimanyubishnoi8727 4 года назад

Eg 2 is contradictory to what u explain earlier.when Vi5V then Vout=Vin-5V. Please explain this.

@ALLABOUTELECTRONICS 4 года назад

In example 2, when Vin

@abhimanyubishnoi8727 4 года назад

Now I’ll understand. Thank u 😊

@THEQueeferSutherland 4 года назад

I'm getting used to THE.... cadenceoftheseprentations.

@dudeontheinternet123 4 года назад

lmfaoooooooo

@Eren-vz5vb Год назад

2:47 why Vo is not 0 here?? There is resistance but no voltage drop

@ALLABOUTELECTRONICS Год назад

Since diode acts as open circuit, so there is no current through the diode. ( Considering ideal diode). And since, diode is open, so circuit will not get completed and hence no current through the circuit. So even though there is a resistor in series with voltage source, but there will not be any voltage drop across it. And hence, Vo = Vin during that negative half cycle. I hope it will clear your doubt.

@nitishguptarbl 2 года назад

Excellent man 🙏🙏

@nivetha.s9892 2 года назад

Why clippers are used in tv receivers

@kianlaguna5555 4 года назад

Hi, can I ask what is the output response of a clipper circuit. Hope I can get a respone thank you

@ALLABOUTELECTRONICS 4 года назад

Do you mean the transfer function, or the in general output of the clipper circuit.

@kianlaguna5555 4 года назад

@@ALLABOUTELECTRONICSthan you for the response. What I mean is, how to get the output respone or voltage of a clipper circuit

@mukeshvarma9214 4 года назад

🔥🔥🔥🔥🔥

@kanchanmeena9150 2 года назад

Great explanation sir

@Suryatechniacademy98 5 лет назад

Could you please explain breafly

@billyandmandy286 4 года назад

is it me or his vioce sounds different the whole time

@learnsimpleworksmarter4527 2 года назад

Sir can you please draw a clipper circuit to clip the the output at +2 V

@muhammadirfan7940 3 года назад

How to find the Current across resistor In 9:19 circuit

@ALLABOUTELECTRONICS 3 года назад

The current through resistor R is (Vin - Vo )/ R. At 9:19, Vo = -V2. So, accordingly, you can calculate the current.

@muhammadirfan7940 3 года назад

@@ALLABOUTELECTRONICS Thank you soo much for your reply

@dr.sudharsanaraopotturu1380 2 года назад

Your video contents are good sir, but beginners will have many questions and doubts while watching your videos. Instead of explaining simply what is given in the textbook like a robot, explain more clearly by adding why this is clipping at this voltage etc. Explain in detail sir.

@nethmisathsarani1679 4 года назад

In eg 2, when Vin

@ALLABOUTELECTRONICS 4 года назад

If you see, the anode of the diode is connected to the 5V. And through the resistor, the cathode is connected to the input voltage. When Vin < 5V, then the anode (which is a5 5V) will be more positive than the cathode (Forward Biased) and hence the diode will conduct for that time. I hope it will clear your doubt. If you still have any doubt let me know here.

@nethmisathsarani1679 4 года назад

ALL ABOUT ELECTRONICS got it, thanks😃

@anaromana8183 11 месяцев назад

Example 4.23 time. I saw your explanation here. Is ANODE conected to AC input source and CATHODE to the V=5 v DC source. But i still dont understand why DC source allow current to flow in reverse? For DC source, current doesent exit from positive borne and enter back in source in negative borne? But ofcourse it will be opposite to the diode direction. So i dont understand. Or we have a special rule here.

@AjitKumar-ug5he 2 года назад

Watching this at night before exam and I got to know that much thing which I couldn't during whole semester..

@amajadali187 Год назад

today i m just watching this video , tommarow will my end sem exam ......

@musfidurrahman8406 10 месяцев назад

Could not Example 2 😢

@mayurshah9131 5 лет назад

Excellent 👌👌

@golu4625 4 года назад

Positive side of graph is why first taken in side of forward side why it is not taken in reverse side

@siamhasan288 3 года назад

love how the audio in this video is also clipping

@ivandagiant Год назад

lmao fr

@makewithmegma 2 года назад

💕👍

@mohammedsrivastava5917 3 года назад

6:00 why output should be constant after V ? I mean as the current through the diode increases the voltage should also increase following it's I-V characteristic curve

@ALLABOUTELECTRONICS 3 года назад

During the entire discussion, the diode is considered as the ideal diode. Yes, what you are saying is true in the case of the actual diode, where the diode also has forward resistance. I hope it will clear your doubt.

@mohammedsrivastava5917 3 года назад

@@ALLABOUTELECTRONICS got it...thank you very much sir...