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Complex Numbers (How to find the nth root) : ExamSolutions Maths Video Tutorials 

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Tutorial on finding the nth root when dealing with complex numbers.
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3 окт 2024

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Комментарии : 69   
@kennys3095
@kennys3095 11 лет назад
For 1st Quad arg = Theta ------2nd Quad arg = Pi - Theta ------3rd Quad arg = Theta - Pi ------4th Quad arg = -(Theta) We have to consider different arguements for diff quads. In this case our theta was in 3rd quadrant so we used theta - pi which resulted in -5pi/6 .
@saadafm
@saadafm 3 года назад
you beautiful human
@factgirl147
@factgirl147 2 года назад
You helped me out.... thank buddy
@viviannesogomo5182
@viviannesogomo5182 Год назад
thankyouuu
@ebhojayejuliet9728
@ebhojayejuliet9728 7 месяцев назад
Thanks so much this write up was more useful than the video
@lwazilubisi3810
@lwazilubisi3810 5 месяцев назад
Thanks a lot! I've been wondering why he did that cause the Arg was already between -pi & pi at first, Again Thanks!
@ExamSolutions_Maths
@ExamSolutions_Maths 11 лет назад
Just start with k=0, then k=1 and so on. You don't really need to do k=-1 etc as k=1, k=2, k=3 etc will start to repeat the roots eventually.
@sakiiimouse
@sakiiimouse 11 лет назад
thank you so much, you've made me actually understand complex numbers, and they're no longer complex to me
@pignbird4007
@pignbird4007 8 месяцев назад
life saver!
@trkingdavid4943
@trkingdavid4943 4 года назад
i like how you interpret question
@jacktaylor2877
@jacktaylor2877 2 года назад
how is the angle (5pi / 6) if both terms on complex # are negative? Should it not be in the 3rd quadrant ?
@ExamSolutions_Maths
@ExamSolutions_Maths 11 лет назад
For this type, yes.
@ankitsinha4933
@ankitsinha4933 10 лет назад
great method of teaching... awsm clearity of complex concepts !!! thnx
@ExamSolutions_Maths
@ExamSolutions_Maths 10 лет назад
You're welcome.
@dreamlanddon
@dreamlanddon 7 лет назад
thank you so much teacher... your lecture helped me at exact 1 hour before my calculus exam...
@zanacs7393
@zanacs7393 4 года назад
@@tuneese2561 rah
@FadiAlHazim
@FadiAlHazim Год назад
This is one of the best videos ever! keep the good work and please never stop making those, i feel that am really learning with you!
@sjdjfksl
@sjdjfksl 3 года назад
Is there a range for theta because in exam questions they always add pi if the initial theta value is negative
@ExamSolutions_Maths
@ExamSolutions_Maths 11 лет назад
Cool
@Elkycreates
@Elkycreates 10 лет назад
Brilliant!
@mdjahin99
@mdjahin99 6 лет назад
Thanks a ton Sir!
@ExamSolutions_Maths
@ExamSolutions_Maths 6 лет назад
You are always welcome.
@jacksonferris-choi1739
@jacksonferris-choi1739 10 лет назад
in the last line of working where did the power of 1/4 go for the trig part go ?
@siwipenny6870
@siwipenny6870 3 года назад
sorry sir, how to find value of k that we use?
@justaracoonchillinginatoilet69
@justaracoonchillinginatoilet69 5 месяцев назад
Rewatching this again for uni
@thantyarzarhein5459
@thantyarzarhein5459 Год назад
8:52 - reason why not k = 3, it 31pi/24 which exceeds pi radient. Which is why it took -1
@mramtakujasambaaguy6681
@mramtakujasambaaguy6681 5 лет назад
good lecture
@RichieVillan
@RichieVillan 8 лет назад
In my text book they work in polar form, is this method easier?
@franketanhongda7543
@franketanhongda7543 11 лет назад
Why do we need to include the 2kπ?
@mohammadalaminsiam711
@mohammadalaminsiam711 2 года назад
BEST
@ExamSolutions_Maths
@ExamSolutions_Maths 11 лет назад
It should be an integer. Your answers could well be fluky.
@kojolino2401
@kojolino2401 2 года назад
how did u get the 1over 4 for the n?
@ofmice6577
@ofmice6577 Год назад
Because we are finding z to the power of 4
@user-le3oy9gd2f
@user-le3oy9gd2f 9 месяцев назад
9:45 why does theta have to be less than pi?
@DanielSegripuo
@DanielSegripuo 5 месяцев назад
How did you get the -5pi/6
@LindokuhleMazeka
@LindokuhleMazeka 29 дней назад
I want to know too
@mathsgreek
@mathsgreek 11 лет назад
is it a trick to know with which values of k i must start? thanks really apprieciated ;p
@anuragsuresh5867
@anuragsuresh5867 5 лет назад
oller bin You definitely won’t find this useful now but for other viewers, I’m pretty sure you start from 0 and go to a k value 1 less than the power of z
@paris293
@paris293 4 года назад
Anurag Reggie ooo thank you
@AllanLovezGaming
@AllanLovezGaming 2 года назад
Oller bin how did your exams go?
@brunosilvaneri
@brunosilvaneri 8 лет назад
what do you mean by " 31pi/24 exceeds pie radian"? thanks
@RichieVillan
@RichieVillan 8 лет назад
+Brunin G3 neri Pi radian = 180 degrees. He is just saying that 31/24pi is bigger than 24/24pi. (The angle is bigger than 180 degrees, going anticlockwise from the x axis). As the range of the principle argument is 0 to pi then 31/24pi exceeds the range we want
@VipWeerasooriya
@VipWeerasooriya 2 года назад
Sir, Can we use seven pi upon six instead of - five pi upon six?
@kojolino2401
@kojolino2401 2 года назад
i also had 7 pi on 6 and iwas doubting
@michaelechutem995
@michaelechutem995 Год назад
I was wondering too
@Mexicomonster25
@Mexicomonster25 10 лет назад
do you have a video for drawing shapes with more than 3 vertices on youtube, I don't know how I would go about it!
@ExamSolutions_Maths
@ExamSolutions_Maths 10 лет назад
Sorry, no.
@aashsyed1277
@aashsyed1277 3 года назад
@@ExamSolutions_Maths :(
@adamdesmit776
@adamdesmit776 10 лет назад
Are you god?
@ExamSolutions_Maths
@ExamSolutions_Maths 10 лет назад
Hardly!
@rordongamsey3057
@rordongamsey3057 3 года назад
@@ExamSolutions_Maths lol I love you so much.
@MrMoeqt
@MrMoeqt 8 лет назад
Is this FP1 or FP2/3??
@ExamSolutions_Maths
@ExamSolutions_Maths 8 лет назад
+Moezph. Depends on what board you are doing.
@MrMoeqt
@MrMoeqt 8 лет назад
+ExamSolutions I checked your website, it's edexcel FP2. I'm studying FP1 this year. Great videos sir!
@ExamSolutions_Maths
@ExamSolutions_Maths 8 лет назад
+Moezph. Okay - good luck
@zionsinkala9856
@zionsinkala9856 3 года назад
how come tan inverse of 8/8.root 3 gives you -5pai/6 in the third quad ,am confused you made a mistake
@ExamSolutions_Maths
@ExamSolutions_Maths 3 года назад
Based on the complex number, we landed in the 3rd quadrant. As mentioned in the video, the Arg Z must be between -pi and pi radians, so you need to find the angle from the positive Re axis, to the reference line (red line) by turning in a clockwise direction (giving a negative angle). As we found the acute angle to be pi/6, we got 5pi/6 by doing pi - pi/6.
@fatfrankthepeteacher36
@fatfrankthepeteacher36 3 года назад
@@ExamSolutions_Maths cool story bro
@booyah7394
@booyah7394 3 года назад
So what's the final answer? Sorry if this is a dumb question
@ExamSolutions_Maths
@ExamSolutions_Maths 3 года назад
The solutions are the different values of Z when k =-1,0,1,2
@الاستاذمحمدعقيل
@الاستاذمحمدعقيل 11 месяцев назад
How k = -1 ?
@Anyone10M
@Anyone10M 4 месяца назад
Urdu me
@Anyone10M
@Anyone10M 4 месяца назад
Speaking urdu
@ebhojayejuliet9728
@ebhojayejuliet9728 7 месяцев назад
Your lectures are veey useless sir very hard and u dont 3xplain how you get values you just write them out if we know then we qont be here obviously all the comments is someone confused pls do better
@lumosss
@lumosss 6 лет назад
Complex numbers? More like simple numbers. :)
@abhijeetkumar2099
@abhijeetkumar2099 7 лет назад
speaking for Hindi
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