Compounding of steam Turbines 

Your logical but simple explanations are really helpful, Sir. Thank you!

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Thanks for the video. Genuinely,had Never seen a lecture on this topic of such kind. The diagrams of nozzles,rotor and blades used is the uniqueness of lecture. Thanks for the effort.

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sir you teach so well! the concept has been made so clear focusing on each and every detail. thank you so much.

Better than all others i have seen,nice explanation

well explained, Good lecture, Thanks for sharing.

Subscribed!! Very well explained with reasoning and with example values. Took care of some details too for better clarity.

Extremely helpful and clear explanation. Keep it up.

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Great teacher with good knowledge

Best way to teach turbine compounding

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Excellent sir

Best explanation of compounding

JUST I CAN SAY SUPERB.

stunning lecture

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Very well said😁

Bro, why in velocity compounding first blade does not absorb all energy?

Excellent explanation 👍

Hi Mr.Amit , excellent explanation 👏

Thank you.soooooo much sirrr🤗🤗

Supper!!!

The axial gas turbine compressor take its roots in the axial steam turbine

sir, in case of velocity compounding, velocity of steam has reached to its maximum in first stage itself, but since rotor speed is not equal to the speed of rotor intended(optimum pressure) for harnessing maximum energy(since rotor is kept lower intentionally) . so there is loss of energy in first stage, which could have been absorbed. but in subsequent stages the harnessing may be improved due to matching of lowering velocity of steam to that of corresponding optimum rotor speed required. is it correct understanding?

well explain sir but more better if add with derivation part , mathematically

in first stage, steam loses. its entire pressure and velocity shoots to suppose 1200m/s and. therefore. corresponding. optimum velocity is 1127m/s, but the speed of rotor is kept lower, so there is loss in energy absorption as there could be absorbed more, let suppose absorbing. potential. is 25J but have absorbed only 20J. is it not a loss in velocity compounding, however it may be small.

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Uopt = C1COSa1/2 .is coming to 563.8, not 1127. it's coming 1127, if you don't divide it by 2.

I think you made an error in the math. U = 1200 * Cos(20 degrees) / 2 = 1127.6 / 2 = 563.8. You forgot to divide by 2.

Please change starting sound

English would be nice

Sometimes you are speaking too fast...so try to speak with normal speaking speed

English please