READ!!! In Step 1, the fraction part of the binary number should be .101, and not .11. I forgot to write the zero. Its correct in the rest of the problem
should elaborate on how 0.625 becomes 101 in binary. just multiplying by 2, see if its over 1 or not, and then repeat with any remainder 0.625x2= 1 r0.25 0.25x2= 0 r0.5 0.5x2= 1 r0 =101 0.754? 754x2 = 1 r58 58x2 = 1 r16 16x2 = 0 r32 32x2 =0 r64 64x2 = 1 r28 28x2 = 0 r56 56x2 = 1 r12 12x2 = 0 r24 24x2 = 0 r48 48x2 = 0 r96 96x2 = 1 r92 and ive had enough of this. 1100 1010 will suffice for 8 bits of "mantissa". the rest of it would be a lot easier if people still had to learn log tables at school, what "mantissa" is. this is what maths at school should be. its pretty easy. to think most graduates these days can barely even count to ten let alone multiply or divide...