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Convert number presented in IEEE double precision 64 bits to decimal numbers | Numerical Computation 

The Infinite Math
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10 сен 2024

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Комментарии : 7   
@bryanmeza6139
@bryanmeza6139 3 года назад
Excuse me! How did you get the decimal for the Mantissa? (0.57421875)
@muhammedyasinhanyasar539
@muhammedyasinhanyasar539 Год назад
you need to find the sum of the decimal represented bit value * digit of the bit as radix(2) to the power of. 0010 as integer part is equalent 2 0010 as decimal part equals to 0*2^(-1) + 0*2^(-2) + 1*2^(-3) + 0*2^(-4) equals to 0.125
@ryanr2592
@ryanr2592 3 месяца назад
The key piece of info for calculating the mantissa is that you start with bit[51] and work your way down to bit[0]. bit[51]*2^(-1) + bit[50]*2^(-2) + bit[49]*2^(-3) + .... + bit[0]*2^(-52)
@shadabkhan9163
@shadabkhan9163 2 года назад
hello, Could you calculate the mantissa number completely?
@musaddafmurtaza6440
@musaddafmurtaza6440 Год назад
Hello i can explain you
@sv798
@sv798 Год назад
@@musaddafmurtaza6440 plzz explain
@hazymagnum6436
@hazymagnum6436 Год назад
Remember that the typical conversion from binary to decimal is dependent on the bit's index in the binary number. For example, 0101 can be calculated using the following method: (1 * 2^0) + (0 * 2^1) + (1 * 2^2) + (0 * 2^3) = 5. Similarly, we can use this method to calculate the mantissa of any binary number with a decimal. Using the example from the video, .10010011000...0, we use the following method: (1 * 2^(-1)) + (0 * 2^(-2)) + (0 * 2^(-3)) + (1 * 2^(-4)) + (0 * 2^(-5)) + (0 * 2^(-6)) + (1 * 2^(-7)) + (1 * 2^(-8)) = 0.57421875. We can stop after the 8th bit in the decimal because there are no additional 1's that will contribute to our decimal value.
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