Sir, you are too kind at matyaga kang magturo at mag explain. Kaya naman binigyan ka ni LORD nang angking talino para sa ganuon ay mai share mo sa mga tulad naming gustong matuto sa pag design.Naway Bless pa kayo ni LORD. Sana gumawa ka nang design of Steel Connection sa rafter using bolted.
We need more kinds of this tutorials!! Especially these times!! More power to you Sir!! 2nd replay ko na. :D Design of columns, beams and slab naman sana next :)
Thank you for this video Sir. Maganda po ang explanation and pinapakita talaga kung saang bahagi ng NSCP 2015 hinugot ang mga ginamit na formulas and concepts. Maganda ito irecommend sa mga students, sa mga nag rereview for licensure exam, and sa mga engr. na gustong ma refresh ang design. Also, thank you for being responsive sa mga questions sa comment section. More power po!
salamat sa appreciation mam. kindly share my channel to your friends and let them subscribe and watch my video lectures. more to come pa po. main goal ko makumpleto ko structural engineering courses then saka ako jajump sa softwares application and also to allied engineering courses.
Maraming salamat po sir tolentino. Its been an honor to me to be praised by the origibal and one true only master of caltech. Pillar as we call it. Salamat po sir dahil moat of my knowledge and confidence is nanggaling po sa inyo bilang studyante nyo po before and bilang mentor and coach during quizbee that lead us victories in those respective quiz competitions :)
Thank you po sir sa lecture, napakalinaw at detailed po. May tanong lang po ako sir, don po sa pagkuha nang As, ginamit ko po kasi sa formula ng Mu ay Mu=∅bd²Rn, then same naman po tayo nakuha sa value ng As na 5543.2797mm², ang tanong ko po ay kapag kinompare po yung rho minimum (p=1.4/bd) sa nasolve ko po na rho, mas malaki po value nung sa rho minimum kaya yon po gagamitin diba po? tas pag ginamit po yun magiiba po non ang As, As=8200mm² na po. Sana po malinawan po ako, hindi kopo kasi alam kung tama po ba idea ko. Thanks po sir!
Very informative video, by the way sir question lang. In what case nagkakaroon ng top reinforcement ang isolated footing? My other way of calculation ba na magdagdag ng top reinforcement to reduce yung size ng footing?
Thank you sa Lecture Sir. Matanong ko lang about sa Stability Check kung ano ang mga Load Combinations na gagamitin? Namomoblema kasi ako sa uplift kapag ginamit ko yung Load Comb na 0.6D + E/1.4 (NSCP 2015 Eqn 203-15).
Sir , Galing po ng pag explain at detailed talaga yung mga facts nyo, tanong ko lang sir, ano po ang pinag kaiba ng NSCP 2010 sa NSCP 2015 ? mostly yung ibang vid 2010 nscp sa kanila
It is written in the front part of nscp 2015 regarding the changes before jumping on chapter 1. There is a list of changes there fro 2010 to 2015. See for your self and have some fun reading it :)
Sir, pano po pag may transverse/horizontal loading, di ba po magiging moment sya? Pero ano po yung perpendicular distance po? To top of footing po ba or bottom? Salamat in advance po.
kindlyr efer to the discussion the difference between qnet and qa :) as a short answer allowable soil pressure is the maximum limit condition to carry load while net stress is the discrepancy of soil pressure considering the constraints of soil, concrete structure under foundation and pore water pressure.
yes boss. square footing pa lang. follow ko na din ang wall footing, rectangular footing and combined for shallow type. also magdiscuss din ako ng may moment na load sa column para maanalyze ang transfer of moment from column to footing via bearing area and shear area
sir may question ako sa pagkuha sa number of bars. what if sir we get the value of Rn then get the value of p(roh) and compare it to pmin(rohmin) then we can obtain the value of As then the number of bars? would it be possible? thank you sir!! and Godbless!!
ah. an old school style of calculations. usually if yopu will use rn (flexure coefficient) usually may table na tinitingnan yan. yan ang gamit ng Rn is may table na sinisipat then poof... may deisgn values agad :) pero if calculation piece lang din naman ang pagbabatayan then Rn is just derived from the original formulation so much better if iexercise yung direct calcs para nakikita yung mga changes sa sense ng values. note that the rho (reinf ratio) is intended for a least value of constraint to check whether possible flexural failure may happen but superceeded by the moment capacity of the section to resist load :) note that moment is a function of curvature or what we call ductility condition or simply rho :) whatever method you are going to use make sure you know its limitations and proper uses so that at the end of the calculations all values are usable :) cheers.
Hi engr, I have a query with regards on finding the qna. Hindi ba dapat qnu/FS siya instead of qu? kasi if iplug in yung values from the solution instead of dividing the summation of weight values ay namultiply siya by the FS.
Hi. If you are asking for dimension assessment its qult first since how can you get qnult if you dont have the size of footing to deduct as an effect of stress to be transferred on the footing itself :) also as set forth in section 413.3.1.1. Cheers
Also by logic, is it right qna is greater than qult whereas qult is the factored stress? Note that qult is the magnified value of stress and qna is the net condition lower than qult due to deductions of stresses transfered from generated stresses above.
@@nioroskyengineeringonline8968 I'm just wondering that the paired equations for q_ult would be q_all and if net would be qn_ult and qn_all. Then basing with NSCP it is not how it should be paired. Anyway, just confirming things. Thanks
@@engineersspace2024 @norielepaulcruz3242 q ult is the reference since we are approximating bearing resistance based from forces that understand service state conditions. Note that it is set as a min condition for approximating sizes of footing then note for final checking the qna was taken to assess proper stress where stress of soil was deducted to q ult since size is determined as shown in 1:29:33 for final checking.
good day. as mentioned in the video lecture, the discussion for Bo done here are only for footings which is centered and whose critical area is not exceeding the footing bearing area. Otherwise there should be a consideration of shear center based on the location of the column at the bearing area of footing to be discussed in my future video lecture. cheers
Hi. It was already discussed in the video lecture roght after this topic. Design of rectangular footing :) kindly find it on my playlists by visiting my yt channel. "Patience and diligence is a virtue" :)
Thanks napanuod ko una hanggang dulo. Dun po ba sa reduction factored phi(φ) is equivalent to 0.75. (32:33) yan po ba ang updated na nscp? 0.85 pa po kase gamit namin sa college. Thanks in advance for the answer.
Please see the separate discussion on that matter. It can be found on my RCD playlist on reduction factoe. I think 0.85 can be fpund on nscp 2000 which is already obsolete :) nscp 2015 na po gamit natin. Cheers.
@@butikegtv3590 none. Reason is the as most likely will fall under lower than Asmin or maybe higher than Asmin but wont exhibit higher than potential Asmax since the footing is cobsidered as a slab element where sectional is small as well as effective depth. We learn before taht rho is As/bd so if the d is small then As is large. So in terms of Asmax since d is very small then rho is very large. You will notice it anyway. That is why code does bot provide Asmax condition for footing.
Hi most likely the values for the values for DL and LL will be calculated from the force members transferred from the column to the footing and tie beams. There will be a separate video lecture for that :)
@@leobanco597 yes you can have the valuea from any design software that is capable to calculate forces like staad, etabs, sap, etc. Or even an excel design program can do also the same job by programming it appropriately. The most precised calculation is through finite element analysis since it uses boundary conditions.
@@leobanco597 yes you can have the valuea from any design software that is capable to calculate forces like staad, etabs, sap, etc. Or even an excel design program can do also the same job by programming it appropriately. The most precised calculation is through finite element analysis since it uses boundary conditions.
Sir question lang regarding sa computation ng effective depth. as you have said in the video, ang effective depth is in between main and shrinkage bar. so d = T - cc - db. pag naman sa slab po sir. kasi ang ginagwa ko sa slab is D1= T - Cc - db/2 (bottom bar first lay) D2 = T - Cc - db - db/2 (bottom bar 2nd lay) since as you have mentioned ang footing ay slab din. therefore ganun din dapat ginagawa ko sa slab? then mo mali po yung ginagawa ko sa slab?
hehehe as explained in the video lecture, slab treatment of effective d is different in footing although a footing is just like a flat slab :) cheers. note that slab is continuously connected in a frame that is why the slab rebars act independently and effective depth d is found on the last layer nearest to the tension fiber of concrete and usually they are alternate in position since compression and tensions changes in position (positive and negative moment relations). Meanwhile, Footing has only one type of concavity if isolated type. so it was found out that the layer in between the main and temp is the location of the effective depth (does not change position with regards to compression and tension, see my discussion how footing bends when subjected for flexure).
i think this is the right for you to study deeply on different types of slab, slab as a shell element and slab as a plate element, slab as a membrane element, and slab as a layered element :)
@@nioroskyengineeringonline8968 well explained sir. going back to college, i remember that slab has tension and compression. for left and right support, the tension is within the top of slab since negative moment occur on the support, while on midspan the tension fiber is at the bottom of slab since positive moment occur at the midspan. my next question is, how do i calculate the compression bars for the slab? is it necessary to use temp shrinkage or just the Asmin?
@@iangalicia8264 check if it passes the min condition based onthe grade of rebar. Not that in slab as a diaphragm suffers two types of bending, while in the foundation suffers only type of bending as discussed in one of my video lecture here in isolated footing. It will be different when mat ot combined footing. Soon to upload my video lecture reg on that.
sir sa 1:25:43 kung sakali pong mas mataas yung ld ko sa ldmax, ang advisable lang po talagang i-adjust ay yung base at cc? Hanggang ilan po yung pwede kong iadjust sa cc po? Tapos sir pano po kung mas mataas pa din yung ld ko kahit na nag-adjust na po ako? Salamat po sir.
Hi as mentioned it means yung dimension ng Footing mo is kulang assuming 75mm na ginamit mong concrete cover due to exposure to earth. So puede pa magbago yung footing dimension since lalaki siya dahil kulang/inadequate yung development length nya as set forth by code provision then revisit the checking of OWS, TWS, flexure, and Bearing connection of Column and Footing :)
yes both directions need icheck hanggat maaari pero may mga conditions reg analysis to minimize the checks but ordinarily dapat both sides sana specially pag may moments sa column on both directions
hi. i already explained in the concept that the calculation of the effective depth of the steel bars found on footing is the space between top and bottom bars while on beam and column and as well as slab is at the rebar center. This is due to the action of the flexure found on the footing and found at that the perforation happening is in between the layer of the two directions of the bars ssince the spaace is limited and also the action seems orthodirectional. As a proof the cracks found on foundation failure assuming flecure alone is always found on that particular layer as proven by laboratorical experimentation. this is also stresses by one of the committe member of ACI which is committe number 318 in the personality of Macgregor, one of the authors of the RCD books that is good to read with. Notice that most of the reference books alwaays refer the concept to Macgregor since he was an expert of this design principle :) cheers
also this one. happy viewing :) ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-J6yGNI7qRyk.html you can validate my discussion by reading reference books authored by Macgregor and the likes, not review books since it has too many errors, sad to say.
hi. maraming constraints yung pagselect ng thickness and depth. as for my actual design projects, nagrerely muna ako sa soil bore hole log reports para madetermine ko yung desirable depth and thickness ng footing. if walang soil investigation report or just purely theoretical yung gagawin mong calculations as per classroom puposes lang, You can Try at D = B as mentioned in Terzaghi's condition where D = depth of footing, B = least dimension ng rectangular or diameter ng circular footing. Using Soil bearing checks then makakakuha ka ng D and B, then for the thickness ng footing you can use the One Way Shear or Two Way Shear.
Other way naman is gumagamit ng presumptions ng multiple of 55 sa depth of footing if backho ang gagamiting panghukay since ang nababawas sa isang kahig ng backhoe is most near to 75mm (3inches). then inaassume na wala munang lupa sa taas ng footing, nagkakaoverestimation ng kaunti.
In practice, nagseset kami agad between 1.0 to 2.0 meters since usually duun ang desirable depth basta hindi dangerous sa settlement or other factors that might give failures sa foundation especially liquefaction effect (uneven settlement). Then chinecheck namin using allowable soil bearing pressure and cocompute na kami ng thicknes required using one way or two way.
@@angelicapenaflorida1903 salamat. you can also add me up sa facebook account ko. just search my name and i also entertain question through facebook messenger. Nioro Guevarra Furiscal. ALso please subscribe to my YT Channel :) Thanks and regards
Hi isa yan sa mga next topic. As discussed centroidal pa lang yung loadings and wala pang moment as a load. There will be a separate discussion on that since it will apply concepts on strength of material like shear centre.
@@nioroskyengineeringonline8968 sir, for the fence lang poh. dbah load itself lang ang meron? need p din bang malaman ang SBC nya kahit for fence lang ??
@@zandralyninfante7028 all structural members should conform to the code. Please refer to our design code otherwise you dont want that fence to overturn and kill people whose walking beside it. Safety first before everything else.
Sorry boss, pero ang hirap sundan. I think mahina talaga ako kasi paulitulit ka na magsalita di ko pa din magets sa dami ng redundancy mong pinagsasabi.
