6 years after this was made, and it was still taught better than my orgo professor did. Thank you so much, you have no idea what a relief it is to finally understand this.
You teach far better than my Organic Chemistry I professor. I am glad you posted this video. You are making the lives of students like me easier. Please post on a regular basis. You'll be helping a lot of students. Thank you and God Bless you for helping me and other students.
You are the best chemistry teacher on RU-vid. You have a God's gift to teach. Please post videos regularly. You can post videos for AP Chemistry or Gen Chemistry 1 and 2.
Hello I'm French speaking, I've been searching this stuff on French vidéos for almost a whole week because I did not get a shit of what was said in class, and finally few hours before my test I find answers to my questions, this...this is a message from God ohhhh thanks
you are God sent (cries in organic chemistry tears). I finally understand thank you, and God bless you. AMEN. This was made 8years ago and it's still very helpful.
Sorry to be off topic but does anyone know a way to log back into an instagram account..? I stupidly forgot the login password. I would love any help you can give me.
@Ian Jadiel thanks so much for your reply. I got to the site thru google and Im trying it out now. Takes quite some time so I will reply here later when my account password hopefully is recovered.
You're absolutely right! The size of a group and length of the bond connecting it to the ring play key roles in determining how stable it is in an axial vs equatorial position. If two bonded groups are the same distance away from the ring, then the larger one will be more stable in the equatorial position than the smaller one.
You can know that the C-Br bond is longer than a C-C bond (at 3:55) by comparing the sizes of carbon vs bromine atoms. On the periodic table, C is in the 2nd period (row) while Br is in the 4th period. That is, Br has two extra shells of electrons compared to carbon, and it holds its outermost valence electrons much further away than carbon does. Since atoms form bonds with their valence electrons, Br forms longer bonds (valence electrons further from the nucleus) than C does (valence electrons closer to the nucleus).
It can be drawn axially. After a ring flip, it will switch to an equatorial position anyways. So no matter how you draw it (axially/equatorially) in real life you will find it in both positions since both chair conformations rapidly interconvert at r.t.
Are you perhaps thinking of bond strength? You're right that there is a trend that longer bonds tend to be weaker (which may be what you're referring to here as less stable?). This could lead us to predict, for example, that it would be easier to break the C-Br bond than the C-CH3 bond (other factors are also at play here in addition to bond length). However, at 4:20 we weren't comparing bond strengths, we were comparing the relative stability of the two possible conformations of the cyclohexane. Both cyclohexanes have the same bonds, so we can't use bond strength to compare their relative stabilities.
