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dictionary comprehension in python | Lec-15

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In this video, I have talked about the fundamentals of programming and Python. If you complete this, you will be well-versed in using list for different use case.
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data = {"DERF":0,"POENKN":10,"DD":7,"MAINDATA":[{"IDD":"d3454355","BDD":"5678hfjhjh","LINKID":4,"HeaderFields":[{"FieldTypeName":"H1","Value":"false"},{"FieldTypeName":"H2","Value":"148877564"},{"FieldTypeName":"H3","Value":"20230930"},{"FieldTypeName":"H4","Value":"20231130"},{"FieldTypeName":"H5","Value":"2441.56"},{"FieldTypeName":"H6","Value":"0.00"},{"FieldTypeName":"H7","Value":"2411.56"},{"FieldTypeName":"H8","Value":"EUR"},{"FieldTypeName":"H9","Value":"00115190035"},{"FieldTypeName":"H10","Value":""},{"FieldTypeName":"H11","Value":"4500575382"},{"FieldTypeName":"H12","Value":"0.00"},{"FieldTypeName":"H13","Value":""},{"FieldTypeName":"H14","Value":""},{"FieldTypeName":"H15","Value":"F0"},{"FieldTypeName":"H16","Value":"87"},{"FieldTypeName":"H17","Value":"0.00"},{"FieldTypeName":"H18","Value":""},{"FieldTypeName":"H19","Value":""},{"FieldTypeName":"H20","Value":"No"}],"CodingLines":[],"Tables":[{"N1":"233553","N2":"3555","N3":"ASDDDD","N4":"334324","N5":"900.00","N6":"1.29","N7":"387.00","N8":"","N9":"0.00","N10":"","N11":"","N12":"","N13":"","N14":""},{"N1":"765765","N2":"67657657","N3":"ADFDFF)","N4":"667657","N5":"1000.00","N6":"1.94","N7":"1940.00","N8":"","N9":"0.00","N10":"","N11":"","N12":"","N13":"","N14":""},{"N1":"67657","N2":"76576576576","N3":"SFDFFDFSDF","N4":"7667676","N5":"1000.00","N6":"0.11456","N7":"114.56","N8":"","N9":"0.00","N10":"","N11":"","N12":"","N13":"","N14":""}],"INININ":"148877564","SDRER":"null"},{"IDD":"frret5","BDD":"5trtry4566","LINKID":4,"HeaderFields":[{"FieldTypeName":"H1","Value":"false"},{"FieldTypeName":"H2","Value":"ICI2300397"},{"FieldTypeName":"H3","Value":"20231219"},{"FieldTypeName":"H4","Value":"20240331"},{"FieldTypeName":"H5","Value":"76.44"},{"FieldTypeName":"H6","Value":"0.00"},{"FieldTypeName":"H7","Value":"76.44"},{"FieldTypeName":"H8","Value":"INR"},{"FieldTypeName":"H9","Value":"56676765"},{"FieldTypeName":"H10","Value":""},{"FieldTypeName":"H11","Value":"0.00"},{"FieldTypeName":"H12","Value":""},{"FieldTypeName":"H13","Value":""},{"FieldTypeName":"H14","Value":"F1"},{"FieldTypeName":"H15","Value":"87"},{"FieldTypeName":"H16","Value":"0.00"},{"FieldTypeName":"H17","Value":""},{"FieldTypeName":"H18","Value":""}],"CodingLines":[{"CODE1":0.0,"CODE2":76.44,"CODE3":"5645654","CODE4":"","CodingFields":[{"FieldName":"COL1","Value":"223DD666"},{"FieldName":"COL2","Value":"3454545"},{"FieldName":"COL3","Value":""},{"FieldName":"COL5","Value":""},{"FieldName":"COL5","Value":""}]}],"Tables":[],"INININ":"DER3434","SDRER":"null"}],"Final":"JKHJKLH0909908"}
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29 авг 2024

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Комментарии : 32

@BeingSam7 9 дней назад

count = 0 for i in range(len(data.get('MAINDATA'))): for dict1 in data.get('MAINDATA')[i].get('HeaderFields'): if 'FieldTypeName' in dict1: count+=1 print(count) output - 38 Manish isme kitna optimize kar sakte hai plz batana..

@VivekKhare-z1m Месяц назад

count = 0 for word in data["MAINDATA"]: for headerFile in word["HeaderFields"]: if "FieldTypeName" in headerFile: count += 1 print(count) Ans : count = 38

@laxmanprajapati3945 14 дней назад

lis=[] for key in data['MAINDATA']: for eles in key['HeaderFields']: lis.append(eles['FieldTypeName']) print(len(lis)) answer: 38

@mdtasauvar Месяц назад

for item in data.get('MAINDATA'): # print (item) for next_item in item.get('HeaderFields'): print (next_item) for key in next_item.keys(): if key =='FieldTypeName': count +=1 print (count)

@anuragdasgupta6203 3 месяца назад

count = 0 for i in data.get("MAINDATA"): for j in i.get("HeaderFields"): if "FieldTypeName" in j: count += 1 print(count)

@divyaborse5866 3 месяца назад

counter =0 for key,value in data.items(): if key =='MAINDATA': #print(key,value) for val in value: for key,value in val.items(): #print(key,value) if key == 'HeaderFields': #print(value) for i in value: for k,v in i.items(): if k =='FieldTypeName': counter+=1 print(counter)

@himanshushorts7143 3 месяца назад

count = 0 for i in data: if type(data[i]) is list: for j in data[i]: if j['HeaderFields'] is not None: for k in j['HeaderFields']: if 'FieldTypeName' in k.keys(): count += 1 print(count)

@raghavjuyalcomedyclub184 3 месяца назад

Hey Manish, in one of my interview [cred or angel one] they asked me How to check if key is present in response data or not if key can be at any level in nested response how to solve this using dictionary ? I tried but failed due to nested response and they was no limit on level an they want optimal solution

@iAmLeeFr 4 месяца назад

38 count=0 for list1 in data["MAINDATA"]: list2 = list1.get("HeaderFields") for inner_dict in list2: if "FieldTypeName" in inner_dict : count+=1 print(count)

@nupoornawathey100 4 месяца назад

key_maindata=data.get("MAINDATA") counter=0 for key in key_maindata: for inner_key in key["HeaderFields"]: if len(inner_key) > 0 and "FieldTypeName" in inner_key: counter+=1 print("FieldTypeName appears in json data ", counter, " these many times") ## solution: 38

@rishabhsp 4 месяца назад

count= 0 for i in data.get("MAINDATA"): for j in i.get("HeaderFields"): if 'FieldTypeName' in j.keys(): count = count + 1 print(count)

@user-iy1rx8cy1i 4 месяца назад

suggest some content or documentation related how to build project architecture, do's & don'ts , good habits in python environment

@manish_kumar_1 4 месяца назад

You can checkout databricks blogpost

@manish_kumar_1 4 месяца назад

You can checkout databricks blogpost

@hariharanraman4181 4 месяца назад

counter_name=0 for char in data["MAINDATA"]: for HeaderFields in char["HeaderFields"]: if "FieldTypeName" in HeaderFields: counter_name=counter_name+1 print(counter_name)

@safiadawood5637 4 месяца назад

count=0 for k in data["MAINDATA"]: for fitem in k["HeaderFields"]: if "FieldTypeName" in fitem.keys(): count+=1

@rishabhsp 4 месяца назад

lis = [] for j in range(len(data["MAINDATA"])): for i in range(len(data["MAINDATA"][j]["HeaderFields"])): lis.append(data["MAINDATA"][j]["HeaderFields"][i]["FieldTypeName"]) print(len(lis))

@ajitpadhi 4 месяца назад

Namaskar ❤

@coolguychemistry1976 4 месяца назад

the answer I got for the count of 'FieldTypeName' is 38 . Following is the code: count =0 for i in data.get("MAINDATA"): for j in i.get("HeaderFields"): if "FieldTypeName" in j.keys(): count += 1 print(count)

@ankitdhurbey7093 4 месяца назад

Data is not available in description, please update.

@manish_kumar_1 4 месяца назад

sorry forgot to add. check now

@anantkashyap1746 4 месяца назад

Please give data in description

@manish_kumar_1 4 месяца назад

Added in the description. please check

@nupoornawathey100 4 месяца назад

can you share sample json for assignment please ? it's not there in description.

@manish_kumar_1 4 месяца назад

sorry forgot to add. check now

@nupoornawathey100 4 месяца назад

@@manish_kumar_1 key_maindata=data.get("MAINDATA") counter=0 for key in key_maindata: for inner_key in key["HeaderFields"]: if "FieldTypeName" in inner_key: counter+=1 print("FieldTypeName key appears in json data ", counter, " these many times") # FieldTypeName count = 38

@nupoornawathey100 4 месяца назад

@@manish_kumar_1 key_maindata=data.get("MAINDATA") counter=0 for key in key_maindata: for inner_key in key["HeaderFields"]: if len(inner_key) > 0 and "FieldTypeName" in inner_key: counter+=1 print("FieldTypeName appears in json data ", counter, " these many times")

@nupoornawathey100 4 месяца назад

@satyamkumarjha4185 Месяц назад

count = 0 for i in range(len(data["MAINDATA"])): for j in range(len(data["MAINDATA"][i]["HeaderFields"])): for k in (data["MAINDATA"][i]["HeaderFields"][j]): if k =="FieldTypeName": count = count+1 else: count logger.info(count)