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tuple in python | Lec-16

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In this video, I have talked about the fundamentals of programming and Python. If you complete this, you will be well-versed in using tuples for different use cases.
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29 авг 2024

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Комментарии : 23

@bolisettisaisatwik2198 4 месяца назад

Quick Notes: o Tuple is a data storage or a data structure or data type object in Python. A tuple can be updated by adding new values into it but cannot reassign an existing value by indexing method. The main features of tuples are: o Tuple: tuple = (1, 2, True, abcD) o Tuple gives an ordered output irrespective of input order. o Tuple is immutable object. o .count(2): gives the count of number of occurrences of 2 in the list or tuple. o Tuple.count(2)  1 o index(2): will give the First occurrence of the index number of the argument or number passed. o Tuple.index(2)  1

@user-sf7xi7zw6f 3 месяца назад

t1 = (10, 2, 3, 5) t2 = (3, 6, 4, 3) lst = [] for i in range(len(t1)): j = t1[i]**t2[i] lst.append(j) print(tuple(lst))

@SudiptaTripathy 2 месяца назад

tuple1=(10,2,3,5) tuple2=(3,6,4,3) final_res=() for i in range(len(tuple1)): new_var=tuple1[i]**tuple2[i] tuple3=tuple([new_var]) final_res=final_res+tuple3 print(final_res)

@muktanandzarapkar5841 3 месяца назад

import math t1 = (10, 2, 3, 5) t2 = (3, 6, 4, 3) t3=() for i in range(len(t1)): t3 = t3 + (pow(t1[i],t2[i]),) print(t3)

@tajveertyagi3084 3 месяца назад

input_tuple = ([5, 6], [6, 7, 8, 9], [3]) result=() for sublist in input_tuple: for element in sublist: result=result+(element,) print(result)

@safiadawood5637 4 месяца назад

Q1: test_tuple = ( [5,6], [6,7,8,9], [3]) result = () for lst in test_tuple: result = result + tuple(lst) print(result) Q2: tuple1 = (10,2,3,5) tuple2 = (3,6,4,3) output = () for i in range(len(tuple1)): output = output + (tuple1[i] ** tuple2[i],) print(output)

@divyaborse5866 3 месяца назад

question 1: test_tuple =([5,6],[3]) res_tuple = () list1 = [] for i in test_tuple: print(i) for j in i: list1.append(j) print(tuple(list1)) Question 2: t1 =(10,2,3,5) t2 = (3,6,4,3) final_res = () for i in range(0,len(t1)): #res.append(t1[i] ** t2[i]) result = t1[i] ** t2[i] res = (result,) final_res = final_res + res print(final_res)

@VivekKhare-z1m Месяц назад

Q1. test_tuple = ([5,6],[6,7,8,9],[3]) test2 = () for lst in test_tuple: for inner_lst in lst: test2 += (inner_lst,) print(test2) Q2. tup1 = (10,2,3,5) tup2 = (3,6,4,3) new_tup = () for element in range(len(tup1)): result = (tup1[element]**tup2[element],) new_tup += result print(new_tup)

@anuragdasgupta6203 3 месяца назад

1. input = ([5, 6], [6,7,8,9], [3]) output = () for i in input: output = output + tuple(i) print (output) 2. tuple1 = (10, 2, 3, 5) tuple2 = (3, 6, 4, 3) result = [] # print(type(s)) for i in range(len(tuple1)): n = tuple1[i] ** tuple2[i] result.append(n) print(tuple(result))

@vinu11sharma 4 месяца назад

tuple1 = (10, 2, 3, 5) tuple2 = (3, 6, 4, 3) final=() for i in range(len(tuple1)): rslt=tuple1[i] ** tuple2[i] print(type(rslt)) rslt1=(rslt,) print(type(rslt1)) final=final+rslt1 print(final)

@bolisettisaisatwik2198 4 месяца назад

How is everyone's second answer the same and none's is failing? When both the tuples are being iterated by i, then the second tuple has one less argument to pass and so the execution will fail. I think the correct way to handle that error would be this way. tuple1 = (10,2,3,5,6) tuple2 = (3,6,4,3) result = () for i in range(len(tuple1)): if i in range(len(tuple2)): result = result + (tuple1[i] ** tuple2[i],) else: break print(result) Note: Considering the input taken is same as the inputs provided by Manish. I might be wrong. Please educate, if i am wrong.

@AbhinavShukla-ki5jd Месяц назад

Q1: tt=([5,6],[6,7,8,9],[3,9,0]) l=[] for i in tt: for x in i: l.append(x) t=tuple(l) print(t) Q2: tt=(10,2,3,5,6) tt2=(3,6,4,3) rt=[] for i in range(len(tt2)): tw=pow(tt[i],tt2[i]) rt.append(tw) newrt=tuple(rt) print(newrt)

@AnuragRaut-ry2oq 2 месяца назад

Problem 1 test_tuple = ([5,6],[6,7,8,9],[3]) result = () for lst in test_tuple: new_variable = tuple(lst) result = result + new_variable logger.info(f"The output tuple is {result}") Problem 2 tuple1 = (10,2,3,5) tuple2 = (3,6,4,3) final_tuple = () for i in range(len(tuple1)): result = (tuple1[i] ** tuple2[i],) final_tuple = final_tuple + result logger.info(f"The output tuple is {final_tuple}")

@user-sf7xi7zw6f 3 месяца назад

test_tuple = ([5,6], [6,7,8,9], [3]) # output: (5, 6, 6, 7, 8, 9, 3) lst = [] for i in test_tuple: if len(i) == 0: lst.append(i) else: for j in i: lst.append(j) print(tuple(lst))

@nupoornawathey100 4 месяца назад

Q1: lst=[] for tup in test_tuple: for t in tup: lst.append(t) print(tuple(lst)) # (5, 6, 6, 7, 8, 9, 3) Q2: tup=() for num in range(len(tuple1)): tup = tup + (tuple1[num] ** tuple2[num],) print(tup)

@ankitdhurbey7093 4 месяца назад

Q2 : tuple1 = (10,2,3,5) tuple2 = (3,6,4,3) final_result = () for i in range(len(tuple1)): exp = tuple1[i]**tuple2[i] final_result = final_result + (exp,) print(final_result)

@hariharanraman4181 4 месяца назад

Q1: from loguru import logger tuple_1=([5,6],[6,7,8,9], [3]) result=() result1=[] result1_tuple=() for lst in tuple_1: variable_name=tuple(lst) result=result+variable_name logger.info(result) for lst_1 in tuple_1: result1.extend(lst_1) result1_tuple=tuple(result1) logger.info(result1_tuple) Q2: from loguru import logger tuple1 = (10, 2, 3, 5) tuple2 = (3, 6, 4, 3) result=[] iterator=0 for t1 in tuple1: result.append(t1**tuple2[iterator]) iterator=iterator+1 logger.info(tuple(result))

@bolisettisaisatwik2198 4 месяца назад

I am getting this error when trying to convert the list into a tuple Error= TypeError: 'tuple' object is not callable My approach to the code. Tryed multiple other things, still seeing the same issue. print(list_to_tuple(result)) tuple_test = ([4, 5], [9, 7, 3], [81, 5]) result = [] def list_to_tuple(*args): return tuple(args) for lst in tuple_test: new_tuple = lst result.extend(new_tuple) print(list_to_tuple(result))

@vinu11sharma 4 месяца назад

test_tuple=([5, 6], [6, 7, 8, 9],[3]) print(test_tuple) result=() for n in test_tuple: break_tuble = tuple(n) result=result+break_tuble print(break_tuble) print(result) print(result) result1=[] for n1 in test_tuple: break_tuble1=n1 result1=result1+break_tuble1 print(break_tuble1) print(result1) print(result1)

@raushansingh7530 Месяц назад

# 2nd Question tuple1 = (10,2,3,5) tuple2 = (3,6,4,3) final_tuple=() for i in range(len(tuple1)): result = tuple1[i]**tuple2[i] # logger.info(result) final_tuple = final_tuple + (result,) logger.info(final_tuple)

@Cherry29-no9pb 4 месяца назад

Question1:: example1_tuple=([5,6],[6,7,8,9],[3]) example1_new_tuple=[] for i in example1_tuple: example1_new_tuple=example1_new_tuple+i example1_new_tuple=tuple(example1_new_tuple) logger.info(example1_new_tuple) Question2:: tuple1 = (10,2,3,5) tuple2 = (3,6,4,3) final_tuple=() for i in range(len(tuple1)): final_tuple=final_tuple+(tuple1[i]**tuple2[i],) logger.info(final_tuple)