here in sucrose there will be alpha-1,beeta-2 glycocidic linkage , not alpha -1,2glycocidic linkage. i was searching for my IIT jee ques but on youtube there is no any clear concept .
There's a mistake on the Haworth-projection of Fructofuranose. As seen in Fischer's projection, by completing the mechanism building the furanose ring, the C2 atom should have the C1-H20H, the intremolecular etherbridge (the O between C2 and C5), the bond with C3 and instead of, as shown, a bond to H, it has to be a hydroxy group.
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thank you for the helpful video. I have a question: so In disaccharides if any of the monosaccharides has an aldehyde or a ketone group we say the the disaccharide is a reducing sugar right?i mean not necessarily both should have it...
What matters is, that there is a reducing group free at any end of the molecule. Mattter of fact, I think (at least with conventional sugars) it is not possible to form a glycosidic bond and keep the reducing properties of both monomers, since one of them is needed to form the bond. Thus, it only is important wether the end of a disaccharide has reducing properties.
No, fructose (D-fructofuranose) in sucrose is shown correctly in the video. The furanose ring is simply shown flipped along the y-axis so that all the substituents pointing up are now pointing down, and all the substituents pointing down are now pointing up. By the way, the alpha and beta designations have nothing to do with whether OH (on C2) is pointing up or down. Rather, alpha denotes the OH (on C2 in the case of fructose) is trans from the CH2OH on C5, and beta denotes the OH is cis. For example, alpha-D-fructofuranose means OH on C2 is pointing down since CH2OH on C5 is pointing up in the D- enantiomer, thus making the OH and CH2OH trans. Beta-D-fructofuranose means OH on C2 is pointing up so that it is cis relative to the CH2OH on C5. However, if we are dealing with alpha-L-fructofuranose, CH2OH on C5 is pointing down, so OH on C2 must point up in order to be trans. And likewise, in beta-L-fructofuranose, OH on C2 points down in order to be cis.
While in a ring configuration (Haworth-projection), the C-1-Atom is chiral. It has four different substitutes around itself, so no matter how you turn it, the order will always be the same. Alpha and Beta are different orders of the substitutes, thus they cannot look the same simply by turning. In order to differ these two orders, there's the alpha-beta-nomenclatur.
Nah, you're right it shouldn't. the video's missing an O... C2 should have the intramolecular ether bridge, the bond with C1 / C3 and an additional hydroxy group instead of an H. Took me a while, too
