Discrete Math II - 5.1.1 Proof by Mathematical Induction 

You should take the sum of I.H (k^2) and substitute that in for 1 + 3 + 5 + … (2k - 1) since we are assuming they equal each other. So you can now do, k^2 + 2k + 1 = (k + 1)^2.

Thanks for the course, but this should be seen according to the roden of the youtube playlist or according to the number of the videos "5.1.1, 5.1.2......"?

thank you very very much for these videos

you r the best

❤👍

very complex video

Great video. Why did you add 2k+1 to both sides?