Divisibility Rules 2 || Number Systems || Quantitative Aptitude || CAT Preparation 2024

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Number System by Ravi Prakash | Quantitative Aptitude for CAT 2024
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27 фев 2018

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Комментарии : 148

@ashokkumar-it2wz 4 года назад

What a powerful concept. Hearing this concept for the first time in my 23 years of life. Wondering why this hasn't been taught in high schools.

@SHIVERS445 2 месяца назад

Same😅

@bhargavsathuvalli2480 3 года назад

simply superb-I totally agree with you sir-Many books skips the divisibility rules of 7,13 etc difficult numbers......

@amyepicduel1320 5 лет назад

YOU ARE LEGEND IN MATHS..NO TEACHERSHAVE EXPLAINED THIS WAY.. NO ONE

@Rodha 5 лет назад

Thanks

@Rodha 5 лет назад

Thanks

@mindfullmallu7511 3 года назад

Did u score well?

@shubhneet.x Год назад

@@mindfullmallu7511 did u score well ?

@ThatGirlDiarieS45 8 месяцев назад

What a Conceptual clearity this man has😮...Thank you Priya Mam and satyam sir fr introducing us to this legend

@swamisharma4666 5 месяцев назад

An UPSC aspirants

@indranujhazarika2369 2 года назад

Explained a difficult concept so flawlessly. Everything makes sense now!

@VenkateshKariappa 3 года назад

I've been going through multiple places to find the divisibility rule for 7 from a long time now. Your concept explained here seems to be pretty simple and easy to do. Excellent teaching, Thank you Sir.

@sonty6589 3 года назад

While watching this video i felt like what is the need to learn so much or rules i will just mug the divisibility of each important numbers.....but after completing the divisibility series i came here again to learn this ultimate hack to develop the divisibility rule for any number

@muskanmalhotra9035 6 дней назад

i am watching this video in 2024.. and this is just so useful...thank you sir.. you have made a difference in our lives

@suryavoroy3527 Год назад

Very unique concept ,tweaked congruence modulo property of 7 for 1000 ,exploited minus 1 remainder property and groups of three with signs affixed to them was truly unique . Loved it!

@shivanshimathur9146 Год назад

Never heard of this concept before, thankyou so much Sir

@mantreekumar8923 Год назад

I can't express in words, how much I am thankful to you sir🙏...

@arjunmalhotra2662 3 года назад

Beautiful +Wonderful×Amazing=Superb

@anmolsharma9397 3 года назад

U r simply the best sir....after a very long time somebody has impressed me in this subject

@gokulkrishna3242 3 года назад

The best teaching class ever in online

@faraznadeem7918 3 года назад

Brother could you explain me in the second question why didnt we write (1+2+3+4+5) As according to formula it was (1*10^5+2*10^4 and so on).

@faraznadeem7918 3 года назад

@SARTHAK BORA thanks for your concern to help me. Bdw i understood what i wanted to ask

@kalvinvrijbhan4761 Год назад

Great concept sir I don't have words how to appreciate you sir

@sam16419 10 месяцев назад

How easily you summed up such a difficult concept Thank you Ravi sir!

@rishitachakraborty6140 2 года назад

Thank u for clearing my concepts....

@gungunjain2623 2 месяца назад

Best teacher ever ❤

@supriyathakur2968 3 года назад

What amazing concepts sir

@Eth_com 2 года назад

Amazing explanations 😍

@jaspreetpannu4264 Год назад

GREAT CONCEPT!!

@prashantthakur23 Год назад

what a cocept grt way to teach thanks

@Ok12376 3 года назад

When sor says for any number it is 10^x/N, it's just for odd numbers.

@user-yk9ic2td4l 8 месяцев назад

grateful to your series, sir!

@shaleenjain4220 2 года назад

Sir mujhe cmat ki preparation karni h but uski videos available nhi h utube pe to m yeh vedios se kr lu to jaega kya ya nhi Or yeh complete course h na

@user-qx3wp3qz9w 7 месяцев назад

thank you so much sir. God bless you.

@ManuSrivastava_ 2 года назад

Thank you so much sir.❤❤

@sakshimishra7333 3 года назад

Amazing sir ..m. Watching your vedios for tcs NQT ...bahut hard work kiya h aapne sir

@Rodha 3 года назад

Thankyou :)

@truptinarkhede4850 3 года назад

What is tcs NQT!?

@rahulsinghrana3378 6 месяцев назад

Sir we can apply divisiblity of 11 also bcz. 11 is the factor of 33, so 123456 adding alternate dig it and substract like (2+4+6)-(1+3+5) =12-9 =3 remainder very simple Sir let me know it is right or wrong???

@faraznadeem7918 3 года назад

In question one why did we write 10^2k and what is k here ??

@romi896 Год назад

Anyone can tell me that how we will get to know that remainder will come + or - in last question

@sparsh.... 2 года назад

Thank you sir ❤️

@dishasingh7482 2 года назад

Thanks sir

@cumulusmusic100 9 месяцев назад

Thank you Sir🙏

@tanmaydey3008 Год назад

Thank you so much sir

@sanjeetchandra Год назад

Can someone please please explain how did he get the remainder of 10×10×10/7 as +6(-1), i know he used basic remainder theorem, but when you use basic remainder it should have been 3×3×3, which is basically 27/7 again, that gives out remainder 2 using basic reminders theorem.

@thatsme61 Год назад

How are you getting rem as 2? When it's 27/7, 7x3=21 providing the rem of 6, and again 7x4=28 providing the rem of -1. Hope you got it.

@vishnusharmaek6754 2 года назад

Sir,what will be the remainder for the number 5675354 when divided by 7? Because as per your concept (354+005-675)/7 where i am getting a negative number.

@hardikthakur569 2 года назад

I think you need to just divide it as -675+354 would be -316 and then further dividing -316 by 7 would give you remainder -1 and just change it to positive by subtracting 1 from 7 which would be 8 and this would be further divided to give you 1 as your remainder. Correct me if this is the right way

@justvibin6601 Год назад

@@hardikthakur569 7-1=6

@karthikmadhusoodanan7274 3 года назад

divisibility of complex nos like 33 & 7.

@shubhammaheshwari1191 4 года назад

Please answer this, Given 7^3 leaves a remainder of -1, we can then find the remainder for any greater number by making groups of 3, but we also know that 7^6 will leave a remainder of 1. So why can't we make groups of 6? we won't even have to worry about signs? Edit: Leave, I tried it, both works. That's just lengthy.

@monikarathore1550 3 года назад

Do you know, Where are the questions on LCM and HCF models?

@siddharthjain7766 2 года назад

you can even find at 15:20 of the Divisibility Rules 4 video, the method you're referring here

@siddharthjain7766 2 года назад

@@monikarathore1550 ru-vid.com/show-UCHXQiDwicRon0tRuWj6r9HAplaylists/playlists

@akashsahu6306 3 года назад

When we divide 10^x by 24 remainder +1 or -1 will never come. So, how to proceed in case of 24.

@sakshamgupta3276 3 года назад

24 = 6*4 so if the no. is divisible by 6 and 4 it will be divisible by 24 also..

@rohitnrao4894 3 года назад

Divisibility of 13?

@36_parthshrimali84 3 года назад

At 23:50 ,how can you add and subtract fast ...well done

@prozac8430 Год назад

789-456= 333 333+123=456

@vishusingh3097 3 года назад

Sir in the divisibility rule of 33 in your example , abcdef divided by 33, you convert it into the form of 10 ^ 2K divided by 33 , so you're taking common 10 to the power 4 and hence the remaining is 10a + b and you write only ab how can we write 10 a + b is equal to a b and 10 C + d is equal to CD, sorry I don't understand I am confused please help me sir or anyone please help me.

@arindamtaak6843 3 года назад

A 2 digit no ab can be written as 10a+b

@vishusingh3097 3 года назад

Ohk thanku for rply 😊

@adi_dgaf 2 года назад

@@vishusingh3097 brother when you write a 2 digit number it can be written in the form 10a + b which can be simplified as ab For ex let us take 24 ..we can write 24 in the form of 10 x 2 + 4 where a = 2 and b = 4 Similarly 3 digit can be written in the form abc

@swethamadavan5859 Год назад

how come 10^3 / 7 reminder is -1? don't understand it 15:38

@adityathakur005 Год назад

Same doubt

@spkbusinessD-- 2 года назад

shivam kamat (11) 6-8-2021 thank you sir🙏

@saikiran-pe9yz 4 года назад

Want to know how the reminder is +1 =10power 2/33

@snehatsamuel30 4 года назад

33 x 3 = 99 . therefore 100-99=1

@janvisoni2619 4 года назад

Multiple of 10^2 wont work here u should have said every power of 10^2 gives remainder +1 when divided by 33 . As multiple of 10^2 is 200 also which do not give remainder 1 when its divided by 33. Correct me if m wrong :) and ya I really appreciate your videos,you make all concepts so easy for us.THANKS.

@Jainankur789 4 года назад

10^2 is 100, that gives you a remainder of 1. 10^ 2 is nothing but 10*10.

@janvisoni2619 4 года назад

@@Jainankur789 thanks for telling me what 10^2 means 😊 u didnt get me read it again... every multiple of 10^2 doesn't give remainder 1 like 200,300,400.. We are talking about numbers like 10^2,10^4,10^6...(every power of 10^2)

@tanyashankar9685 3 года назад

Yeah I was confused with his phrases too.

@sjsthomasnick3002 3 года назад

@@janvisoni2619 yah u r right. Its not multiples of 10^2. It is powers of 10 which are multiples of 2.

@riyashrivastava1460 9 месяцев назад

How is 10 to the power 1ef/33 is leaving remainder as 1? I am not getting this

@SHIVAMKUMAR-hi9hb 7 месяцев назад

watch again from 5:35 , and see 10^0/33 is nothing but 1/33 and its remainder is 1. And (10^1.e +10^0. f) can be written as 10^0(ef) this is what he has done

@user-bd5py9nh4k 7 месяцев назад

Is their anyone having problems sheet topic wise. Then please help me

@vardhmanjain9887 11 месяцев назад

Why it got so hard ..like you have to multiply the last number with 2 and then subtract that with the remaining numbers .. that one is so easy the this mess

@sanaparweenansari2333 4 года назад

Whats the method of divisibility of 6..anyone?

@snehatsamuel30 4 года назад

Check if the number is even - divisibility test for 2 and then check if sum of digits is divisible by 3 . because 2 and 3 are factors of 6

@anujpatil343 2 года назад

Sir Jipmat and Ipmat ki registration date aah gayi hai kya

@sujalkumar8634 Год назад

have you cleared it !!!??????

@morningstar2728 4 года назад

Here you gave questions like which follows order in group of 3,, so what about if such numbers ask like suppose e.g: 1234 / 7. How should we solve it easily?

@vikasnarasapur3251 4 года назад

1234/7= Make a group of 3 means (001,234)/7two groups So now sign 234 have +be sign and 001 have negative sign( u know this how sign comes from above concept) so now -001+234/7=233/7=2 So the remainder for ur question is 2! I hope u got the answer

@muslim1713 3 года назад

How to take common? Im nt able to undrstnd

@sakshamgupta3276 3 года назад

You should take Commen in the form of 10^x and 10^x remainder should be 1 or -1

@shashankdewangan9176 4 года назад

thanks sir u are awesome. sir is this much videos is enough for cat level preparation?

@ashitadoshi3047 4 года назад

How did 10 to the power zero divided by 33 become one?

@drigo8192 4 года назад

To make a no. in point form we have to first multiply by zero. As 1/33 so 0.030 So in the first step when u multiply 33 with 0 you get the remainder 1 . As we are dividing 1 by 33.

@Justsomeguyyoutubing 3 года назад

10^0 = 1 1/33 = remainder 1 (calculate)

@aryamansrivastava7218 3 года назад

@@Justsomeguyyoutubing rem should be 0 na? 1/33 1*33=33 Quotient 33, remainder 0???

@sanjeetchandra Год назад

Can someone please please explain how did he get the remainder of 10×10×10/7 as +6(-1), i know he used basic remainder theorem, but when you use basic remainder it should have been 3×3×3, which is basically 9/7 again, that gives out remainder 2 using basic reminders theorem.

@akshaysonavane8629 3 года назад

39×55×73×90×97×54 is divided by 50 then what is remainder i can't solve this type sir

@sjsthomasnick3002 3 года назад

Ans is 0.

@akshaysonavane8629 3 года назад

@@sjsthomasnick3002 explain plz

@sjsthomasnick3002 3 года назад

@@akshaysonavane8629 39×55×73×90×97×54/50 We can divide individually (39/50)R = -11 (55/50)R = 5 (73/50)R = 23 (90/50)R = -10 (97/50)R = -3 (54/50)R = 4 (-11 × 5 × 23 × -10 × -3 × 4)/50 -(55 ×230 × 12)/50 Again divide individually (55/50)R = 5 (230/50)R = -20 (12/50)R = 12 -(5× -20 × 12)/50 (100×12)/50 Again divide individually (100/50)R = 0 (12/50)R =12 (0×12)/50 =0. Ans = 0. Hope it's clear.

@sjsthomasnick3002 3 года назад

@@akshaysonavane8629 are u preparing for CAT'21?

@Meena-ud2ry Год назад

Can anyone explain at 8:55 how 1/33 =1?

@sujalkumar8634 Год назад

its not 1/33=1 ...its actually reminder when 1 is divided by 33 which goes like 1=33*0+1 where 0 is devisor and 1 is reminder

@shrutikmanwatkar8019 3 года назад

And Exactly "7" dislikes...

@Abhishek-vn1nq 28 дней назад

mujhe smj nhi aya koi ye smja skta hai -1 remainder kesa find krte hai is video mai 15:30 pe 1000/7 ka remainder -1 kessa find kiya

@legendaryquotes964 18 дней назад

Bhai jab divide krega to last mein 20 aayega which is -1 to the multiple of 7 (21) . Jaise 22 is +1 of 21 ....I hope you got it

@sakshamgupta3276 3 года назад

I tried this method for 17 and 19 but unable to solve bcs there are no 10^n which gives rem of +1 or -1

@HadesBTC 3 года назад

For 17 do 10^8 = -1 Rem

@HadesBTC 3 года назад

For 19 do 10^72 = +1 Rem

@HadesBTC 3 года назад

If You Still unable to understand then leave your insta id will send you step by step and help u to understand

@aryamansrivastava7218 3 года назад

10^0 ÷ 33 ka rem 1 kaise?

@HadesBTC 3 года назад

@@aryamansrivastava7218 Question sahi sa batao

@vinitpatil8755 Год назад

24:10 456/7 remainder should be 2.correct me if I am wrong.

@growwithbro01 Год назад

456÷7= 65 and remaindr 1

@vinitpatil8755 Год назад

@@growwithbro01 65/7=9 further dividing 9 gives remainder 2.

@growwithbro01 Год назад

@@vinitpatil8755 bhai tu *quotient* ko kyu divide kar rha hai

@kaushikibhatt1874 3 месяца назад

(123+789)-456 how it became 456/7 can you tell me

@vyankateshpandey8228 5 месяцев назад

Sir the method is not working in the 6 7 digits

@vyankateshpandey8228 5 месяцев назад

Kindly guide sir

@ashokmacho1932 3 месяца назад

Question batao Bhai

@lokeshsanklecha3789 3 года назад

Sir some questions are there

@Rodha 3 года назад

what?

@Ukkmeee Год назад

How does 101 0 leave rem 1?

@Ukkmeee Год назад

imeant 10 to power O

@legendaryquotes964 18 дней назад

Divided 0 times , so got 1 remainder

@Gautam_OG 2 года назад

13:00 24:00

@BharatSingh-mi9xo 4 года назад

Taaliyan bajti rehni chahiye

@anishdubey6721 4 года назад

Bilkul

@kshitijbalonie4361 4 года назад

thankyou

@StardomMovies01 3 года назад

How 1/7 remainder is 1? 😞

@truptinarkhede4850 3 года назад

Coz 1 is not wholly divisible by 7 and also we don't want a remainder in fractions as remainders are always in integers.

@truptinarkhede4850 3 года назад

So 1 is the positive remainder. And -6 is the negative remainder. Every remainder is in +1and -1 form. Ok!

@syedshoaib8720 5 месяцев назад

How is the remainder of 56 one?

@ShifaArabi 23 дня назад

I also have the same doubt

@legendaryquotes964 18 дней назад

Bhai yaha particularly 56 ki baat nhi ho rhi , uska Jo common liya hua multiple 10° hai , uska 33 k respect mein remainder 1 hai ....same concept also applied with 12 .,....I hope you got it