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Electric Power and Joule's Law |Lec#07 |Class10/12 |Current Electricity 

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Electric Power and Joule's Law |Lec#07 |Class10/12 |Current Electricity
In this video, we discuss Electric Power and Joule's Law in detail. We discuss Electrical Energy and its uses in daily life.
The link to the video about Electric Potential and EMF is given below
• Electric Potential and...
• Potential Difference a...
#ephysics
#currentelectricity
#electricpower
#joulelaw
#electricalenergy

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24 сен 2024

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Комментарии : 13   
@MuhammadUllah-b5w
@MuhammadUllah-b5w 8 месяцев назад
Nice lecturs sir ji ❤
@muhammadfayaz7054
@muhammadfayaz7054 6 месяцев назад
❤thank you sir for learning
@KakaKako-b9m
@KakaKako-b9m 12 дней назад
Assalamu Alaikum sir, sir "joules law" k formula ma "current" per square q hai??????
@KakaKako-b9m
@KakaKako-b9m 12 дней назад
Sir plzzzzzzzzzzzzzzzzzz reply karay 😢😢
@ephysics3801
@ephysics3801 11 дней назад
@@KakaKako-b9m Joule's law states that the heat produced (or power dissipated) in a resistor is given by P = I^2 R , where P is the power, I is the current, and R is the resistance. The I^2 term means that the power (or heat) increases with the square of the current. So, if you increase the current, the heat produced grows much faster. For example, if you double the current, the power dissipated will increase by a factor of four, because (2I)^2 = 4I^2. This is why the current is squared in the formula.
@KakaKako-b9m
@KakaKako-b9m 11 дней назад
@@ephysics3801.
@SalwaYousaf
@SalwaYousaf 8 месяцев назад
sir ye juole's law equation ma "J" division ma Kasey aya ye tu constant Hy or constant product ma hota hy
@ephysics3801
@ephysics3801 8 месяцев назад
The constant J in the formula is used for the amount of mechanical work required to produce one calorie of heat energy. it has a value of 4.184 J/calorie It appears in the denominator of the formula to ensure that the equation is consistent with the units being used. Sometimes we are interested in knowing the heat dissipated or wasted in the units of calories instead of joules, for which we use Joule's Mechanical Equivalent in the equation. H = (I^2 * R * t)/ J If the result is desired in joules, the constant J would not be necessary in the formula and the new formula will be H = (I^2 * R * t) and then constant will be equal to 1 only. In short it is just the conversion factor from joules to calories and nothing special.
@SalwaYousaf
@SalwaYousaf 8 месяцев назад
Okay thanks 😊
@AliashrafKhan-ch7ux
@AliashrafKhan-ch7ux 9 месяцев назад
WELDONE explaination sir
@fidakh6980
@fidakh6980 10 месяцев назад
@fidakh6980
@fidakh6980 10 месяцев назад
Sir plz jaldii jaldii lecture uploads krei
@jaseemullah1563
@jaseemullah1563 10 месяцев назад
Sir g please ❤ firstyer physic lecture uplod ❤❤❤❤❤
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