You Sir are my friend atleast in my head haha...am an engineering student and I have learnt so much from you. Watching your videos is always a highlight for me
Hi Michel first of all thank you for these amazing lectures, also i would like to ask if you were to cover these lectures till 35 what topics would you have covered. Hoping for a quick reply. And once again thank you so much for all the content.💖💖💖💖💖💖💖💖
Work smart, not hard... 😀. Recognize that triangle wave is the integral of a square wave which has a trivial Fourier series. It’s also trivial to integrate those terms. Nothing at all wrong with the approach shown here - but this is a good trick to remember.
When you find a(n) ==> where period is (2/T) from Fourier formula, and your integrating between (T/2 and 0) for function f(t), using (y=mx+c) I have found that f(t) is (2A/T)*t ==> Now a(n) becomes (2/T)*(2*A/T)= (4A/T^2)*integral(t)cos(wnt) dt==> where did you get the (8A/T^2) from (for a(n) ?
In this example the period is T/2 (we are only integrating the first part of the sawtooth, since the second part requires a different equation. Thus 2/(T/2) = 4/T
That is derived from the linear equation y = mx + b Where m is the slope and b is the y intercept. In this case the slope = rise / run = A / (T/2) and the y intercept is zero.
learning about dc power supplies in electronics class where the almost-dc output of them is approximated by a triangular wave. And my professor just said "look up the fourier series of a triangle wave". And here I am. Without you sir I would be lost with such incompetent people teaching me in real life
Yes, when I was a student I felt lost often. I always thought to myself, if I already knew how to do that, I wouldn't be in this class. Glad we were able to help.
Extend each ramp outward in both direction and the extended line will cross over the vertical axis. Then you can fine the equation for the line in the form: y = mx + b
