Тёмный

Entropy ideal gas 

Jos Thijssen
Подписаться 2,7 тыс.
Просмотров 2,9 тыс.
50% 1

Опубликовано:

 

8 окт 2024

Поделиться:

Ссылка:

Скачать:

Готовим ссылку...

Добавить в:

Мой плейлист
Посмотреть позже
Комментарии : 4   
@Galileosays
@Galileosays 8 месяцев назад
I wonder, why in the end we don't write S~h.
@josthijssen6782
@josthijssen6782 8 месяцев назад
We simply want to have an unambiguous number. An additive constant would not matter for analysing processes, whereas a multiplicative constant does. We want to make contact with thermodynamics: E = TS-PV+μN, so there's not too much freedom.
@Galileosays
@Galileosays 8 месяцев назад
Thanks. Another explanation came to my mind. At thermal equilibrium the entropy is at the maximum value and therefore it stays at Heisenbergs lowest possible value; DpDx=h. @@josthijssen6782
@Galileosays
@Galileosays 8 месяцев назад
@@josthijssen6782 Thank you for the explanation. I see, a constant wouldn't matter. Especially not in differences between states. It came also to my mind that at thermal equilibrium the entropy is at a maximum. This brings Heisenberg's relation to its minimum possible value Dx.Dp=h.
Далее
The cluster expansion
49:40
Просмотров 9 тыс.
Counting quantum states in 1D
20:43
Просмотров 2 тыс.
Thermodynamic potentials
16:55
Просмотров 2,7 тыс.
Particle Physics is Founded on This Principle!
37:39
Просмотров 175 тыс.
How Quantum Entanglement Creates Entropy
19:36
Просмотров 1,1 млн
Langevin and Fokker Planck equations
36:27
Просмотров 24 тыс.
What is entropy?
13:32
Просмотров 3,1 тыс.
Polymers: Free and Gaussian chains
51:25
Просмотров 16 тыс.
How Quantum Mechanics Predicts All The Elements
14:44
Просмотров 323 тыс.
thermodynamics part 1
1:18:49
Просмотров 1,8 тыс.