Clement Zhou since n is a natural number, the absolute value was not necessary as I moved beyond that point, since I knew the expression would be positive.
Hi! Thank you for the video; question... at around 3:40, we claim $n > 19/9e$. Thus is it necessary to "choose N > 19/9e" or can we just set $N = 19/9e$ since $n > N$ by implication.
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For the final step when you plugged in your N and simplified to epsilon, what do you do if your N doesn't simplify down to just epsilon? I have a constant term in my N that I can't get rid of.
OreoMan, can you put ignore the constant? Remember, these are inequalities, so you can choose N to be larger to ensure you are less than epsilon. If the constant cannot be ignored, can you bound it somehow? This is what I typically try to do.
OreoMan I see, so your issue was that you are getting (essentially) 1/epsilon needs to be zero right? That is a bit strange, what was the limit you were trying to establish?
very similar to the question you used as an example. I needed to show that (5n^2 +4)/(3n^2 + n +1) is convergent to 5/3. The thing I posted just before is my N
OreoMan , I am getting a different possible N for yours, if you want. No fancy bounding needed. Try N=\sqrt((7\epsilon-3)/9) if I am not mistaken. See if you can find how I got that (assuming I did not make an error!!!)
