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0/0 is not undefined. It is indeterminate. We need calculus (or a graph) to see if x = 0 is a solution. The limit of (7^x -11^x)/√(77^x-121^x) as x approaches 0 is equal to 0, so x=0 is not a solution, because 0 ≠ 1.
In this case, solved in a much simpler way. But the exercise was what it was. By observation, if x >0, the answer is complex. If x=0, we get undefined So for all real solutions x
Зачем умножать обе части на (ab-b^2) до вынесения общего мнржителя b в знаменателе? В итоге (a-b)^2/b(a-b). Квадрат убирается и домножить на b вроде проще
There are certain cases where 0/0 can be equal to something finite. Remember, a non-zero number divided by zero is undefined, but 0/0 is indeterminate. For example, (2x)/(x) is obviously equal to 2, but in the case where x=0, we can use calculus (or a graph) to determine that as x approaches 0, (2x)/(x) still approaches 2.
@@markmurto No, function approaches 0, as x approaches 0. If you don't believe me, graph the function or put it in Wolfram Alpha and ask it to take the limit as x approaches 0. Also, 0/0 is not undefined. It's indeterminate. Only non-zeo numbers divided by 0 are undefined.
