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Full Wave Voltage Doubler Circuit 

The Organic Chemistry Tutor
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This electronics video tutorial explains the workings of the full wave voltage doubler circuit. This circuit converts an AC power source into a DC voltage with an output that is nearly twice the voltage of the input.
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11 фев 2020

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Комментарии : 43   
@PunmasterSTP
@PunmasterSTP 2 года назад
Full wave? More like "hip hip hooray!", for all of this free learning. Thanks again!
@Dumb-Comment
@Dumb-Comment 4 года назад
What category is this channel? *yes*
@MindMathMoney
@MindMathMoney 4 года назад
The *#1 Math Teacher* on RU-vid with some *Electrical Science* video lately...🔌⚡ I still love it! 😍
@ninjawarriors2838
@ninjawarriors2838 2 месяца назад
All engineering in this channel This guy single handedly made Millions of Engineers
@domix711
@domix711 4 года назад
you make things way much easier than they actually look like. God bless you. sir may you add some videos on how to use the steam table ( thermodynamics)
@trebushett2079
@trebushett2079 3 года назад
You've modelled the scenario very nicely but haven't made it clear that you've introduced AC peak voltage, in this case 12V ( 8.4V RMS ), this may lead to confusion.
@awaitingthetrumpetcall4529
@awaitingthetrumpetcall4529 Год назад
Thank you for posting. I was trying to grasp the mosfet bootstrap circuit and the charge pump circuit.
@raulconve6841
@raulconve6841 2 года назад
Thxs for your excellent and clear explanation. Kind regards from Mexico amigo!
@kingcrunch85
@kingcrunch85 2 года назад
Thank you so much! This particular circuit is used in the Kenwood Trio KW33-L tube receiver power supply and i could not figure out how to solve the residual ripple on the output. Now i have a hunch on why it still has so much ripple on the circuit.
@ahasiikuyu8001
@ahasiikuyu8001 4 года назад
This guy is great and awesome we would like to see you
@wesleymatthews137
@wesleymatthews137 Год назад
Nice. Simple. Maybe explain how the amperage of the circuit changes throughout the doubling process?
@nickstanton9885
@nickstanton9885 4 года назад
Would you use electrolytic capacitors? (Polarized to prevent flow through C1 to C3 and R1 during the negative cycle)
@arthurharrison1345
@arthurharrison1345 3 года назад
Nice!
@agari123
@agari123 3 года назад
thanks
@liamhoward2208
@liamhoward2208 4 года назад
@OrganicChemistryTutor , How are functions found ? Say if a scientist was making a mathematical model of a radio signal. How do they figure out the long complicated trig functions?
@rademilijasevic4313
@rademilijasevic4313 2 года назад
What happens when you ground the other end of the AC side? How could I get +/- DC double output voltage using a singe AC winding as the source?
@user-bn7qu5yo4y
@user-bn7qu5yo4y 7 месяцев назад
12V must be RMS right?, not the Peak value ??
@SuperPutzPutz
@SuperPutzPutz 11 месяцев назад
That circuit will save current if you connect two of the same resistors at load wired in series. 11.7 volts will drop over each resistor and the 23.4 volts will push the same current needed for one resistor thru both running two devices for the price on one if the higher voltage doesn't damage the 12 volt device.
@W1RMD
@W1RMD Год назад
How do you know what size capacitors to use based on load current? Thanks.
@thorstenelvers7618
@thorstenelvers7618 2 года назад
i'd say the voltage would be at 2Vsup-Vd, since in every half cycle, the supply voltage is connected in parallel to one of the caps at Vsup-Vd, and in series to the other cap at the same Vsup-Vd, thus adding the voltage up to Vsup+Vsup-Vd = 2Vsup-Vd. voltage should however be more stable at 2Vsup-2Vd, depending on the Power of Vsup, since Vsup drops under load
@sicciopasticio2560
@sicciopasticio2560 10 месяцев назад
Nice! Just a remark the threshold diode in example is 0.3V. About charging C2, the voltage coming from AC source is 12V. The diode is after C2, should not be C2 charging until 12 V in this case?
@mdengentonga1900
@mdengentonga1900 2 года назад
You. Are. AWESOME!
@successthruknowledge
@successthruknowledge 2 месяца назад
So, if D2 is AFTER C2 then how does it reduce the voltage on C2? Is that due to C2's internal resistance? Anyway still a great video though I'm curious how the circuits were devised. Is this one way of many? It must be.
@klarakhaing3017
@klarakhaing3017 4 года назад
Can you post some videos about physical chemistry? gas law and more. Btw is your name Jake. G ?
@techmelts7860
@techmelts7860 Год назад
The BIL on my transformer can handle the voltage from the voltage doubler. But can you please let me know what about the extra current from the charged capacitors? Will a higher amperage flowing back into my secondary damage the transformer? I have a 10 kva 14.4 Kv 120/240 volt transformer 60 hz. If I used 500 uf capacitors that hold a lot of joules. That’s a lot of extra current flow about to be discharged right into my secondary coil. If the ampacity of my secondary wires are thick enough to handle the extra current will my system be able to run it as long as I would like? Online it doesn’t explain how much current I can run back into my secondary in a DC system very well. Please help friend.
@techmelts7860
@techmelts7860 Год назад
I’m actually wanting to do a full wave voltage tripler. Same exact issue though. On falstad it looks like more voltage and more current would be flowing back into my system.
@petersage5157
@petersage5157 4 года назад
Surely you mean that the 12VAC will charge C1 and C2 to 16.6V each? Unless you specify Vp-p when you say VAC, most of us enginerds will assume Vrms, no?
@PunmasterSTP
@PunmasterSTP 2 года назад
Yes, I agree!
@stephendixon8575
@stephendixon8575 3 месяца назад
Yes, that’s what I was thinking - though I’m assuming maybe the explanation of “12v AC” was being ‘simplified’ as it’s peak voltage for the purpose of this explanation, as towards the end it refers to 2 x “peak voltage” less the diode drops. For anyone reading this and not following - Normal convention is that AC voltages are expressed as RMS (Root Mean Squared) values - so the ‘average’ voltage of 12V AC is at 12V but the peak value (as per the formula) works out at about 1.414x higher (square root of 2), therefore 16.9V peak. So C1 and C2 each charge to about 16.6V each, giving a total combined output voltage of 33.2v (now 23.4v).
@psy7669
@psy7669 4 года назад
What are the capacitance of C1, C2 and C3?
@PunmasterSTP
@PunmasterSTP 2 года назад
I think his explanation was focused more on the concepts than on specific values. If I'm not mistaken, C3 just has to be "relatively large" compared to C1 and C2.
@prasadkarlekar7856
@prasadkarlekar7856 Год назад
I have done this experiment and used 8v... But I got out put 65-66v.. I didn't use c3.
@psy7669
@psy7669 4 года назад
What is the use of C3? If C3 is omitted, the voltage across RL is 23.4V, isn't it?
@bixenbaer
@bixenbaer 3 года назад
It s used as a filter cap to really provide the energy for the load and smooth out the ripple
@qw-hq5xr
@qw-hq5xr 3 года назад
How are the capacitors getting charged if they are reversed??
@bixenbaer
@bixenbaer 3 года назад
C1 and c2 get charged depending on the half cycle. They don’t lose their charge during the opposite half wave. C3 will kind of add up the voltages of C1 and 2
@aselim20.
@aselim20. Год назад
I watched it.
@johnwrightoverlandingrobotics
C3 is not really needed. Also, Caps charge to the Vp of the AC signal input (VAC). Vp = VAC * 1.414 - .3V (.3V is used to represent the Ge Diode nominal voltage drop).
@awaitingthetrumpetcall4529
@awaitingthetrumpetcall4529 Год назад
Quote: _"C3 is not really needed."_ C3 is a bypass cap. A large enough current draw will create ripple.
@hakuwapuyad9891
@hakuwapuyad9891 4 года назад
Face reveal pls, if not though, just continue what you do. You save a lot of people through your videos. Thank you very much.
@nicotean8376
@nicotean8376 4 года назад
Please do a Face Reveal at 1.5 subs 🙏🙏
@sahal1544
@sahal1544 4 года назад
Yo
@messifan2379
@messifan2379 4 года назад
Do a face reveal
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