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General method for drawing any regular polygon given the measurement of one side 

Arthur Geometry
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How to draw a any-sided regular polygon given the length of one side.
This RU-vid channel is dedicated to teaching people how to improve their technical drawing skills. It focusses on drawing figures from the geometric plane to descriptive geometry and also different systems of technical drawing representation.
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#Geometry #HowtoDraw
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16 авг 2024

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Комментарии : 48   
@alexbennie
@alexbennie 9 месяцев назад
I've read through all these comment, yapping on about "It's wrong!", but no one seems to be fascinated by the fact that such extremely high accuracy is reached by such an extremely low effort method. For instance: How many division in "n" parts of lines and angles are suddenly possible after the "Origami Axioms" come into play? I've not yet seen Mr Galois or any of his students tackle the -morphisms from Geometry including Origami axioms to their rings and fields and their other headache-inducing, albeit fascinating, contraptions! Anyways, late to the party, but YT Algorithm should've known better and recommended this channel years ago... So, a belated, cheers on an awesome channel! And secondly, if anyone can tell me who the originator of this method is, I'd love to Delve into that Rabbit Hole!
@apunctg
@apunctg 3 года назад
It's an approximation method ... the accuracy is 1.9 degrees ... try to draw it in CAD ...
@cbranalli
@cbranalli 4 года назад
the hexagon drawn here is perfect because the construction establishes an equilateral triangle ABO and replicates it 5 more times around the circle. an equilateral hexagon is indeed comprised of 6 identical equilateral triangles meeting at a common vertex. however - any construction purporting to draw equilateral polygons of successive numbers of sides - based on the notion that the respective circumscribing circles have centers equally spaced along the central vertical line is simply WRONG - as a trigonometric analysis will clearly show. at best - this method will yield good approximations of equilateral polygons whose number of sides is "quite close" to the original number of sides - in this case 6 - thus 7 8 and 9 as well as 5 4 and 3.
@josefwintzentlibot7852
@josefwintzentlibot7852 Год назад
Yes, the heptagon thing is just an approximation because for it to be perfect 7sin(180/7) must be exactly 3. But that is not the case as 7sin(180/7) = 3.037... or 1.24% more than 3.
@devildog4805
@devildog4805 3 года назад
The sector is a vintage drawing instrument. It uses the same method to lay out any regular n-gon.
@muhammadvaseem6926
@muhammadvaseem6926 4 года назад
Sir this is very good useful easy method important lecture thank you
@philippereverdiau1087
@philippereverdiau1087 4 года назад
This 9-sided polygon is not regular, neither the others (probably), except indeed the hexagon !
@roselyngbobor900
@roselyngbobor900 2 года назад
l understanding it thanks for this good work
@supchurch8055
@supchurch8055 5 лет назад
Well done . Applied mathematics for machine trades ... Divideing head math . 👍
@einsteingonzalez4336
@einsteingonzalez4336 4 года назад
If you love this geometry, then you might love this higher geometry: mathworld.wolfram.com/QuadratrixofHippias.html
@ssakelvin1923
@ssakelvin1923 4 года назад
Thank u alot ave really appreciated from Kenya😊
@rajasekaran5333
@rajasekaran5333 5 лет назад
useful for beginners
@oussamaziani1551
@oussamaziani1551 4 года назад
Thanks from algerian 😀
@nankundaarnold6486
@nankundaarnold6486 3 года назад
extremely helpful. Thank you!!
@OnlineToBrain
@OnlineToBrain 8 лет назад
But this is not a exact method. It is approximately method.
@Nameci-wo1ht
@Nameci-wo1ht 7 лет назад
This is an exact method if you already have constructed a line segment with the same length as the side of the regular polygon you want to construct.
@MustardPipeLibrary
@MustardPipeLibrary 7 лет назад
Nameci2718, you're just flat-out wrong. I would hope the creator didn't intend for this method to be seen as an always-exact method (one doesn't exist for general regular polygons with compass-and-straightedge only). I would assume that either he knows this is an approximation and didn't think that was worth saying, or he was duped as well. Rndm Dud, while what you've said is true, you're missing the point of what Online is saying. What Online is saying is that if you COULD use "perfect" methods perfectly, without any errors, you would get a perfect regular polygon, but if you likewise could use this method perfectly, without any errors, the resulting polygon would unavoidably be NOT regular. True, the error may be small enough for most practical purposes, and may easily be overshadowed by other factors when doing an actual physical construction - but again, that was not the point.
@MustardPipeLibrary
@MustardPipeLibrary 7 лет назад
I'm not entirely sure about that. Your expansion seems to be more along the lines of "No method can be perfect in the physical world" which is completely true. To be fair, I don't know exactly what Online's point was, but I took it to be "Even in a perfect world without physical limitations, the method is flawed." That is, dealing with it in a purely mathematical sense. Assuming that is what he meant, your point about physical limitations, while true in our universe, isn't really relevant for the purely mathematical one. As I'm typing this, I realize we may very well have the same opinions, just different focal points - your focus being on the physical world, mine being on the pure mathematics. I assume you would accept that, say, Euclid's construction of a regular pentagon is "perfect" in the pure mathematical sense, though it's impossible to perfectly replicate it in the physical world?
@MustardPipeLibrary
@MustardPipeLibrary 7 лет назад
Probably, yeah, the only difference is what we emphasize.
@MustardPipeLibrary
@MustardPipeLibrary 7 лет назад
You're welcome; I agree that too often RU-vid comments can be insulting and childish, and while I have a bad habit of sometimes being too blunt, I do try my best to not descend to quite that level. (I just hope I didn't go too far in my comment directed to Nameci...)
@mr.perfect8750
@mr.perfect8750 3 года назад
This guy sounds like the one from Organic chemistry tutor channel. 😅
@dr.facilier4322
@dr.facilier4322 7 лет назад
Nice job dude., Really helpfull
@mnek742
@mnek742 7 лет назад
It was proven *CENTURIES* ago that not all polygons can be constructed with a straightedge and compass. See en.wikipedia.org/wiki/Constructible_polygon . For example, a 7-sided polygon is not constructible. It's very easy to prove that this method isn't correct and only produces approximately correct results in certain cases. Try using the C3 for a 3-sided polygon and it won't even work.
@kingfuff402
@kingfuff402 5 лет назад
A seven-sided polygon (a heptagon) is in fact able to be constructed. ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-cErccoHui9g.html
@doublespoonco
@doublespoonco 5 лет назад
@@kingfuff402 Its close but not 100%
@ffggddss
@ffggddss 5 лет назад
@Murtaza Nek: That's right. In particular, the actual centers for those polygons would *not* be equally spaced. The constructible regular polygons are those whose side count, n, is a product of distinct Fermat ("Fair-mah" - it's French) primes, and any number of factors of 2 (including none). The known Fermat primes are 3, 5, 17, 257, 65537. [To generate these numbers, start with 2, square each term to get the next, then add 1 to all of the terms.] It's unknown whether there are any more (that are prime), but if there are, the next one is larger than an astronomically huge lower bound, and therefore, of absolutely no practical importance. For that matter, neither is 65537. The n-values up to 100 that are and aren't constructible, are: Yes: 3, 4, 5, 6, 8, 10, 12, 15, 16, 17, 20, 24, 30, 32, 34, 40, 48, 51, 60, 64, 68, 80, 85, 96 No: 7, 9, 11, 13, 14, 18, 19, 21, 22, 23, 25, 26, 27, 28, 29, 31, 33, 35, 36, 37, 38, 39, 41, 42, 43, 44, 45, 46, 47, 49, 50, 52, 53, 54, 55, 56, 57, 58, 59, 61, 62, 63, 65, 66, 67, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 81, 82, 83, 84, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 97, 98, 99, 100 But using an accurate ruler and some trig (or a good protractor, for that matter!), you can draw any regular polygon with a given side length. With side length s, the height, h, of the center (h is called the apothem of the regular polygon), is h = s/[2 tan(180º/n)] The method shown in this video is exact only for n=6, which is what it started with, anyway. Fred
@TheRojo387
@TheRojo387 4 года назад
Straightedge yes, impossible, but marked rulers do make all other polygons constructible. And marked rulers render primitive straightedges obsolete.
@PBS-nm1uu
@PBS-nm1uu 3 года назад
what is the angle of the T line??
@scratchthecatqwerty9420
@scratchthecatqwerty9420 Год назад
Any.
@dddreslu3072
@dddreslu3072 8 лет назад
nice
@trevorallen3212
@trevorallen3212 2 года назад
So I can in theory I can construct my own protractor 360 degree polygon? Sounds like a fun challenge.
@dudeyouhavenoidea
@dudeyouhavenoidea 3 года назад
Neat
@official-obama
@official-obama Год назад
Beware that this is only a really good approximation, if you want to draw 1-gons, you might run into some problems.
@official-obama
@official-obama Год назад
And, the limit step is 1/pi, so by doing an inversion over a unit circle, pi can be obtained, which is impossible, so it also is an approximation going out to infinity, and will slowly become less and less accurate.
@official-obama
@official-obama Год назад
A 7-gon cannot be constructed using a compass and straightedge. If it could only be created from a side, it could be "transported" to a circle using parallelograms.
@madhusudanlolge5068
@madhusudanlolge5068 6 лет назад
this method is not give accuracy which have
@ArthurGeometry
@ArthurGeometry 6 лет назад
Thank you for your contribution. This is an approximation method for drawing by hand, not for an accurate mathematical solution.
@VijayaKumar-el2yn
@VijayaKumar-el2yn 6 лет назад
Which method have you got ? Please share it.
@gottfriedschuss5999
@gottfriedschuss5999 4 года назад
@@ArthurGeometry You are correct, sir, this is an approximation. Actually, it's plenty good enough for many "pencil" drawings. As an example, using your method to inscribe a tridecagon (13 sided polygon) with sides 2 units in length, gives a relative error of about 0.2% larger than the "true" circle should be. This is just fine for dividers that use pencil lead. However, with carefully sharpened machinist's dividers, working on metal, this error will be obvious. Similarly, the error will be quite obvious if using a CAD package with precision set smaller than 0.01 units. I'm sure you know this, but for the benefit of other readers, if machinist's/CAD accuracy is required, then a tiny bit of trigonometry will give a precisely accurate solution. As an example, take the above tridecagon with side 2 units long. The radius of the inscribing circle is 1/sin(180/13) = 8.373136 units. In general, the radius is (s/2)/sin(180/n), where s is the length of each side and n is the number of sides. Best regards, Gottfried
@elizacollate8967
@elizacollate8967 6 лет назад
This method is not accurate enough .All sides are not equal .Please rectify that
@okorarewhor7016
@okorarewhor7016 6 лет назад
construct yours and post for us to watch.
@ffggddss
@ffggddss 5 лет назад
There is no method with the classical tools - straightedge and compass - that will work for most numbers of sides, n; but with a ruler and some trig calculation (or a protractor), it can be done. As accurately as can be measured with those tools, anyway. With straightedge and compass, the scorecard reads as follows... Constructible: n = 3, 4, 5, 6, 8, 10, 12, 15, 16, 17, 20, 24, ... Not constructible: n = 7, 9, 11, 13, 14, 18, 19, 21, 22, 23, 25, ... Fred
@mathografixartdesignartdes5452
that is not what I am looking for
@wizrom3046
@wizrom3046 6 месяцев назад
So there is not need at all to draw the silly hexagon and the smaller circle? Total waste of time all you need are the points A B and O which is just 2 arcs. And to divide A B by 2 so you can get T (that division is a weak point of this system).
@cringequeen9376
@cringequeen9376 4 года назад
I don't like this one
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