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Geometric Interpretation of Ordinary Least Squares: An Introduction 

Ben Lambert
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This video provides an introduction to the geometric interpretation of Ordinary Least Squares.
Check out oxbridge-tutor.co.uk/graduate-... for course materials, and information regarding updates on each of the courses. Check out ben-lambert.com/econometrics-... for course materials, and information regarding updates on each of the courses. Quite excitingly (for me at least), I am about to publish a whole series of new videos on Bayesian statistics on youtube. See here for information: ben-lambert.com/bayesian/ Accompanying this series, there will be a book: www.amazon.co.uk/gp/product/1...

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20 ноя 2013

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Комментарии : 19   
@vatsalamolly
@vatsalamolly 3 года назад
Sometimes when you're studying advanced stuff, you get confused about the very basics. Thank you for this quick and easy explanation!!
@andresiganciomunozecheverr6071
@andresiganciomunozecheverr6071 3 года назад
Among all the intuitions we can possibly find, this is exactly the one I was looking for, thx a lot Ben!!!
@291291ify
@291291ify 10 лет назад
you are a life saver, thank you so much!!
@murfalious
@murfalious 6 лет назад
Thank you very much. Clarified this subject very well :)
@bertobertoberto3
@bertobertoberto3 9 лет назад
that was excellent
@ranjit1568
@ranjit1568 10 лет назад
Hey thanks for the video. Why at the end do you say u hat equals XBeta hat? I thought it is y hat = XBeta hat.. thanks
@NoName-kg5rv
@NoName-kg5rv 3 года назад
Amazing!!
@Angel1a89
@Angel1a89 2 года назад
Thank you!!!!
@Marteenez_
@Marteenez_ 11 месяцев назад
Is it possible for y to be in the column space of X?
@javierwagner4410
@javierwagner4410 Год назад
Would it be valid to interpret it instead as the row space, given that the row space defines the independent variables and pre-determines in which space the observations can move. Row vectors seem to make more sense as all observation are restricted to the # of independent variables present.
@vinsavi
@vinsavi 7 лет назад
what bounds all x into 1 plane? . if y1 is a step explained by [1 x11 x12] then it means there are 3 steps needed to explain y1 thats all, no one is saying that those all are in one plane. kindly explani
@aleksanderpasato6916
@aleksanderpasato6916 10 лет назад
Hi, thanks for great explanation. I've been looking for something like this for ages ;) I guess I don't get one thing. Isn't it so that span of 3 independent vectors in 3D space cover entire space (as we can get any point by using linear combination) instead of just a plane?
@kottelkannim4919
@kottelkannim4919 3 года назад
2:59 The space described in the video is 4D, albeit drawn on a 2D graphic tablet. So 3 independent vectors in 4 dimensional space do span a "plane".
@tomasnobrega8087
@tomasnobrega8087 3 года назад
@@kottelkannim4919 yeah! Thats a hyperplane (sounds much fancier than it is)
@fk866
@fk866 Год назад
@@kottelkannim4919 n
@samkim6933
@samkim6933 4 года назад
I think u hat, in this case, doesn't indicate the residual, it only means the orthogonal projection of y onto col(X)... is that right?
@kurtvonschleicher
@kurtvonschleicher 4 года назад
no, u hat is the distance between the orthogonal projection of y over the space (in this example represented as mu hat on a plane) spanned (obtained through linear combinations) by the columns or vectors (column space) and the actual y. there is a unique linear combination obtained through the Ols method that minimizes the value of u hat. the parameters of such "optimal" combination are the betas of the regression. u hat can be also interpreted as the portion of y that cannot be expressed through a linear combination of the columns (i.e. the part of y that does not lie on the column space). why is u hat perpendicular to the row space? due to the fact that u hat lies in the so called "left null space", which as stated in the fundamental theorem of linear algebra is orthogonal to the column space.
@m.h.4652
@m.h.4652 2 года назад
The end of the video is not correct. When you write u_hat = XBeta_hat, thats not correct. It should be u_hat = y_hat - X Beta_hat
@zhizhongpu8937
@zhizhongpu8937 Год назад
Agreed; there's also another error: the vector in the column space should be XB (in the graph now it's u) and the difference vector should be y-XB = u (instead of y-u as in the video 4:54)
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