MATH VIDEO. How to calculate how much of a substance remains after a certain amount of time. ALSO: How to figure out how LONG it takes to decay to a certain amount (use logarithms!) Check me out: www.chemistnate...
I need to find out the radioactivity of a certain isotope using the half-life and the mass. How in the heck do I do this? Nothing on the internet is helping me, and neither is this video.
IT WAS SERIOUSLY THAT EASY!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! I SPENT HALF AN HOUR TO GET IT OUT AND ALL YOU HAD TO DO WAS TOO JUST PRESS IT :( Thank you so much!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! : )
dude! great video but in second question u made a mistake by taking 1gm as undecayed substance... it would have been 499 gm as in formula, "A" is amount of radioactive substance undecayed or left! :)
As working out the half life is in the syllabus for my gcses, for the second part of the video for working out the time, is this the same principle for figuring out the actual amount of half life's if instead the time is given to you or is there a different solution to it?
When i enter 1440 divided by 58 i get the answer 24.82758621. When you do it you don't seem to get he decimal point after 24. Also the later calculation you get the correct amount of zeros before the numbers start whilst on my CASIO fx-85GT calculator i get 3.358550105x10-8. I know what 10-8 means i just wondered if you could tell me how i get my calculator to give the answers in the same form as you get?
Isn't it easier to use the 0.693/k = (half-life), solve for K and then use the first-order rate law ln(At/Ao)= --kt ? Substituting k in Ao = initial amount and At = amount remaining. I used these for each problem and got the same answers. Maybe it's just me, but this way seems much faster and easier to solve. Anyone else prefer this method?
+TheOomen2012 I understand and hope I didn't offend. I was just taught a different way and wanted to offer it up in case anyone else was struggling like me. I find that seeing alternatives sometimes helps me learn better. Thank you
Got a question saying " The activity of a sample falls to 0.60 of its original value after 100s. Find the decay constant." What formula should i use? How would you answer that?
If youre playing the stock market today it is 780,000 to one odds. 🤔 Id call that to Bill Burr n say I feel like I get it but do my comments matter or my thoughts. N Im worth 2$ ask any basketball player who knows the Ballsteadts... ❤ TuTu' its Fffing Rude
Hi ChemistNATE and everyone, Could you please help me with this following question Radioactive materials are considered to be relatively safe when their activity has fallen below 0.1% of their initial value. (a) How much half-lives does this take? (Answer = 10 half-lives) (b) Plutonium-239 is a by product of nuclear reactors. Its half-life is 24 000 years. How long does the plutonium-239 have to be stored as nuclear waste before it is considered safe to handle? (Answer - 240 000 years)
6.1K people like this video... Man o man I hope I can be this smart one day .. i wonder what language this guy speaks it sounds foreign.... Maybe its latin for 🐐 s wait... I know it's expensive language ... F me running. I almost detected the tongue dialect...
Instead of just giving me this formula, the IGCSE Physics book just says you have to count the half-lives and half the times until you get your answer. Really dumb.
for some reason my 2 calculators wont get anything but 3.37 but then i put it in on googles sci calculator and it finally worked. this is tricky if your calculator isn't like his.
you could just use the solve function in the calculator to find the t in the second problem. I assume your 10 canadian bucks calculator will have solve function as where i live in, almost every calculator do have the solve function if you know where to find it
Yeah... and the million dollar question (regarding Carbon14) How much was there at the time of death. There is no way of telling (unless the scientists have the ability to time travel)
I don't even care tht he was a bit cocky anymore I understood here out of all the other 10+ videos I watched thanks nate! *oh and yea exam in an hour!!!
