Hardy cross method 

Acha G. Tek hh. Likn Kuch khas nai is lectures main. Banda khod pansa huwa hh. Apko kia samjaya ga

@Shoukat ullah battani from UET Peshawar Bannu Campus

That's modified darcy equation.

flv^2/2gD mai f hotha hai friction factor. Aur f=4f' (f' = coefficient of friction). therefore it is modified to be 4f'lv^2/2gD. (people usually denote with f and it doesnt matter until you substitute a value for it.)

Bro delta Q can't be zero The value of detla Q tends to zero means very less Let value of delta Q is 0.2 Then square of delta Q is 0.04 This value if very less compare to Q that's we have neglect that portion

4f is Darcy friction factor where f is coefficient of friction. if (flv²)/2dg is used it means they used friction factor ie, 4 times the coefficient of friction If (4flv²)/2gd is used it means they are using coefficient of friction In short Friction factor = 4 times Coefficienr of friction

More then my teacher .... rispect sir👌👌

Actually ∆Q is not zero it is very negligible as compared to Q( assumed discharge) hence ∆Q^2 was neglected..

Do u guys also study day before exams?? 😂

😂😂

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