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Harmonic Balance Analysis of Nonlinear RF Circuits 

Michael Steer
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19 сен 2024

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Комментарии : 12   
@tensorbundle
@tensorbundle 7 лет назад
Hi professor thanks for the webinar. I am currently working on a cmos freq doubler and running cadence's HB. Your lecture helped me a lot to understand the underlying principle. Your book is also excellent, easy to follow and enriched with insightful explanation. Thanks
@Scuba_Bro
@Scuba_Bro 3 года назад
great webinar! your textbook has really taught me a lot even after using it during grad school.
@karamany9870
@karamany9870 2 года назад
what do you do? Analog?
@amalelghailani3258
@amalelghailani3258 4 года назад
Great explanation, thank you so much Sir. Can i have the matlab code with which you did the calculations?
@holydoragon
@holydoragon 10 лет назад
Hi, at 23:20, how did you solve for I_0, I_1, and I_2 for the nonlinear subcircuit? Could you give an example calculation for I_0? I used trigonometric substitution to evaluate the [v(t)]^2 term, and I get a 4th harmonic from that and you drop that term as you say in your next slide, but I think that's the only part that we could agree on.
@michaelsteer343
@michaelsteer343 10 лет назад
I used MATLAB. If you want to follow this along you need to look at the section referred to in the book. Lot's more explanation there.
@colin_hart
@colin_hart 6 лет назад
I'm looking at p. 923 in the second edition of the book and I am also struggling to follow along. The only explanation in the book is "The linear subcircuit and the nonlinear subcircuit described by the quadratic model result in the following equations." I calculate by substituting v(t) into i(t) = v(t) + [v(t)]^2, expanding the expression and grouping phasors in terms of DC, cos(wt), cos(2wt), etc. as explained: I0 = V0 + V0^2 + 1/2*V1^2 + 1/2*V2^2 I1 = V1 + 2*V0*V1 + V1*V2 I2 = V2 * 2*V0*V2 + 1/2*V2^2 I3 = V1*V2 (neglected) I4 = 1/2*V2^2 (neglected) However the book (19.5) and this video (23:30) give: I0 = V0^2 + 1/2*V1^2 I1 = 2*V0*V1 + V1*V2 I2 = 1/2*V2^2 These terms appear in what I calculated but there must be some justification for discarding the remaining portion. The system of differential equations at (32:10) is satisfied by the equations I found so I believe that the remaining portion is necessary. Further inspection shows the equations with all terms present in (19.14). I'm not sure if there is a subtlety I am missing or if the equations in (19.5) are just incomplete.
@FigoMaluco
@FigoMaluco 6 лет назад
Hello everyone, I also solved with trigonometric substitution and there is a lot of variables that are not assigned for some reason that i did not find out. Could you please tell me what I'm missing? My trigonometric resolution is on the link below: drive.google.com/file/d/1w8xdCCbi8cejjh0CrIIg4XYrGI5DpPv6/view?usp=sharing
@FigoMaluco
@FigoMaluco 6 лет назад
Hi Colin Hart, Did you find anything ?
@colin_hart
@colin_hart 6 лет назад
My work was still on my whiteboard, so here's a photo: imgur.com/csF6ZCs
@RahulSharma-qz2vj
@RahulSharma-qz2vj 4 года назад
@Michal Steer , what is wrong if I directly solve for V0, V1 and V2 on slide 2 (Around 25) and got solutions i.e. V0 = -00390V, V1 = -0.125 V and v2 = 0.5 v.
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