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Spectral Analysis - Cadence Crash Course #9 

Thomas Booij
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19 сен 2024

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Комментарии : 20   
@omarghanimghazal3712
@omarghanimghazal3712 2 года назад
Please keep the cadence training series updated with new videos and functionalities because you are the best at explaining it.
@kashmirparadise8625
@kashmirparadise8625 Год назад
This channel deserves more than 1M subscribers 😔❣️
@evadeltor7811
@evadeltor7811 Год назад
Thank you for the video!
@strangeff6461
@strangeff6461 7 месяцев назад
Thank you for the video.Very helpful
@mauricio533
@mauricio533 2 года назад
Ontzettend goede uitleg! Bedankt!
@jacobrajesh804
@jacobrajesh804 6 месяцев назад
Thanks for the video, the topics were very well explained. I have one question, shouldn't m=fs/fi cause fs>fi?
@yaohuazhang8422
@yaohuazhang8422 2 года назад
Should we also tick the transient noise box in the transient response set up page?
@ThomasBooij
@ThomasBooij 2 года назад
Great question! You can choose to add transient noise to the signal to which you apply the FFT. That will result in a much higher noise floor, depending on the statistical properties you choose in the setting. Right now, the floor is at around -300 dB, which implies that the noise is only limited by the accuracy of floating-point numbers (i.e. there is no discernable noise). For more info on how to determine such a noise floor's behavior as a function of temperature and system parameters, have a look at this: en.wikipedia.org/wiki/Minimum_detectable_signal.
@JeromeManzano-j7w
@JeromeManzano-j7w Год назад
Hi Thomas, great video. I was just wondering at 13:12 the THD is 0% even though Harmonics are present. Any idea how to get an actual value of THD in this case? Thanks
@ThomasBooij
@ThomasBooij Год назад
Hi Jerome! Really good point, the real THD definitely isn't 0% here! I don't have access to the simulation from here, but I expect that you might have to indicate what the fundamental frequency is somewhere. Otherwise, I'd expect that Cadence can't distinguish between the signal and its harmonics (esp. in the case of intermodulation, where the number of harmonics increases significantly). Hope this may help as a pointer for getting closer to that real THD-value.
@JeromeManzano-j7w
@JeromeManzano-j7w Год назад
@@ThomasBooij I see, very interesting. I think I managed to get a value for Total Harmonic Distortion by using the "THD" function in the Cadence calculator. This function asks for the fundamental frequency and returns a percentage for THD. Thanks Thomas
@Nanoelectronicslab
@Nanoelectronicslab Год назад
@@JeromeManzano-j7w Please increase the value in the harmonics from 1 to 10 (in the spectrum window), and then you will see the proper THD.
@Mohamad-dc1zx
@Mohamad-dc1zx 2 года назад
Hello Thomas Thanks for this tutorial I wonder if you could help me with this. I've designed a 10 bit 1v ref fully differential SAR ADC. what I want to do now is to calculate SNR, ENOB and other factors. Here I can not understand if these values such number of samples and Fs you're talking about is just for FFT function requirements or the exact idea can be applied for ADCs too. I mean should I apply a sine wave and sampling frequency for 1M hertz and then all values will be calculated by software automatically? If the sampling frequency is to be 1 Mega hertz so fin has to be only 1K hertz so that 1024 specific samples will be produced.
@ThomasBooij
@ThomasBooij 2 года назад
Hi Mohamad, the rules laid out in the video are meant for getting a meaningful result from the FFT. The sampling rate of the FFT and that of the ADC are, thus, not the same. I am therefore also not completely certain as to whether the contraint you list is correct, but from intuition I would expect the Fs of the FFT to be highter than that of the ADC. Otherwise, you are taking too few samples in the FFT to get a realistic idea of the signal's spectrum. Hope this helps!
@gouda9995
@gouda9995 2 года назад
mention me if you have video about PVT variation "corner "
@marichamydivya8544
@marichamydivya8544 2 года назад
Hello sir. If I have a 160MHz pll output clock for a 20MHz reference clock. Can I take the sampling freq to be 640MHz?
@fjord2141
@fjord2141 Год назад
Why not M = 77?
@ThomasBooij
@ThomasBooij Год назад
That's because 77 isn't a prime number; it's divisible by 1, 7, 11 and 77. 79 is the nearest prime number.
@vincentf502
@vincentf502 Год назад
@@ThomasBooij Thanks! I think I understand. It’s still “relatively prime” to 1024 I think though right so it should technically still work?
@ThomasBooij
@ThomasBooij Год назад
@@vincentf502 Indeed, after thinking about it, you're absolutely correct. As long as M is relatively prime with 2^N this will work, which is indeed the case for M = 77. When M is a prime number itself, we have the immediate guarantee that there can be no common divisors. In other words, while there are many other values of M for which this will work, choosing a prime number guarantees that there will be no common divisors.
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