How a 555 Timer IC Works 

You made the drawing yourself ? They seem really nice.

555 comments i dont want to ruin it

yea when you already know what he is talking about , then again you don't need much explanation don't you ? That guy is an idiot, he described the chip for 10 minutes without even saying what it is about and or what he is talking about. PURE RUBISH

@@michgingras Where's your amazing content?

@@michgingras something tells me you cut yourself.

@@THE16THPHANTOM I didn't know how it works and now I do. You being slow to understand doesn't mean the guy did a bad video, it just means you're slow.

@@furrane OK, boomer.

Kevin Byrne - congrats are - extremely - premature. Really, pal, why would you say this? He is very difficult to understand now and of you tell him he is “great” talking english, he might STOP trying to improve. In this way you actually HURT his progress. This guy has very good content and the right ideas about teaching, but still need to improve English A LOT.

@@ShelliLoop wow you're stupid af.

S H i agree, the English is shoddy and needs work.

I agree with Kevin. I already knew most of this, but it is an excellent video. The 555 timer is a "killer app" example of an integrated circuit. It's simple, elegant, and versatile! The criticisms of his English are unfounded. His English is very good. His accent is still very strong, but I had no trouble understanding him. Accents only go away with time and exposure to native speakers, which not everyone has access to.

@@jovetj yup, the 555 timer, along with a 566 chip, form the sound of the 2 flying saucers on Atari arcade Asteroids. It really is used in a ton of stuff.

Thank you!

verry much yess

@Rishikesh upload more electronics videos 📹👀

@@cryptocsguy9282 sure!

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Thank you!

Glad it was helpful! :)

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Glad you found it useful. Cheers!

Thanks! I'm glad you found it useful.

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6:48 If anybody who reads this is curious how to derive that t=1.1*C*R result, its simple. capacitor --------| |-------- | | | \ | / resistor | \ | / | | | __ Vcc __| constant Dc dq = i dt i = dq/dt Using Kirchoff's law, q/C + R i - Vcc = 0 R (dq/dt) = (Vcc . C - q) /C dq/ (Vcc - q) = dt/ CR Apply integration on both sides with limits LHS.. from 0 to q, and RHS..from 0 to t. then you will get, - Ln ((Vcc .C - q) / Vcc .C) = t/CR From this we can easily get this result, i.e q= Vcc. C (1- e^(-t/CR)) since q=CV, V = Vcc(1- e^(-t/CR)) Now apply V= 2/3 Vcc in this formula, you will end up with t= ln(3). C. R [ln(3) = 1.0986 = 1.1(approx)] Happy learning!

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