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How does a calculator find sinx? 

The Unqualified Tutor
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Online Python IDE: www.online-python.com/
My code: www.online-python.com/diwYZl2Luj
Credit to @HowToBasic for the clips I used in the video. I figured he wouldn't mind me stealing just a few seconds... hopefully.
Knowledge of the following topics are essential to understand this video:
Basic trigonometry (obviously)
Radians & Degrees
Matrices
Chapters:
0:00 Explaination
5:26 Programming

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8 июн 2024

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Комментарии : 227   
@David_Box
@David_Box 27 дней назад
the most egregious programming tutorial ever
@The_Prince770
@The_Prince770 27 дней назад
horrendous, perchance
@Bolaside
@Bolaside 27 дней назад
@@The_Prince770 you can't just say perchance
@hallrules
@hallrules 27 дней назад
@@The_Prince770 you cant just say perchance
@ianweckhorst3200
@ianweckhorst3200 27 дней назад
It has befouled us
@harley_2305
@harley_2305 27 дней назад
@@The_Prince770you can’t just say perchance
@LethalChicken77
@LethalChicken77 25 дней назад
My favorite part is how it still uses a trig function
@janpaul74
@janpaul74 24 дня назад
indeed, how do we get rid of the atan for f**k sake? ;-)
@Tof0986
@Tof0986 24 дня назад
@@janpaul74 Thought the same first, then concluded that these are arctan of always the same values, then it can be hardcoded, I guess.
@Tovarris
@Tovarris 24 дня назад
@@janpaul74 You can use taylor series to approximate trig functions as a polynomial. For example cosx = 1 - (x^2)/2! + (x^4)/4! - (x^6)/6! + ... Look up taylor series for more info. I believe they are used to approximate trig functions and also other tricky functions like e^x as well. It is also how exact values of these functions were found before calculators.
@dariosucevac7623
@dariosucevac7623 20 дней назад
@@janpaul74 i think they use Taylor series for a close aproximation
@firstduckofwellington6889
@firstduckofwellington6889 15 дней назад
@@dariosucevac7623 Nah, the Taylor series is too inefficient. Check out the CORDIC algorithm en.wikipedia.org/wiki/CORDIC
@communismwizard8198
@communismwizard8198 27 дней назад
Funnily enough, I wasn’t too hurt when you used curly braces instead of a colon. It’s a common mistake, sometimes it gets hard switching between languages very often. I was hurt when you called that symbol a “hashtag”
@Momie_et_Masque
@Momie_et_Masque 27 дней назад
I didn't even notice he used curly braces but I was hurt when he used special characters in variable names instead of spelling them (phi, theta) or even using representative names.
@ianweckhorst3200
@ianweckhorst3200 27 дней назад
Also, he could’ve easily saved the import and just used 1/(2**n), for someone teaching us about math, he sure doesn’t know basic math facts
@ianweckhorst3200
@ianweckhorst3200 27 дней назад
Although he probably did need atan from math, but the question here is uh, how would one calculate that by hand, it’s clearly needed for the formula, and while there is an integral formula, it’s still an integral, and integrals are pretty equal in their difficulty to calculate, plus, even once you’ve gotten past that difficulty, there’s even some square roots that even with a definite formula, the formula is quite difficult and time consuming when you’ve converted your numbers to binary, otherwise, it’s pretty close to impossible, and since the atan is part of an approximation, and you have to stack two approximations which grow harder exponentially the more you stack them, and you’ve got a recipe for a horrible or likely impossible time getting it, if there was some solution he gave to that, let me know
@LichtMarv
@LichtMarv 27 дней назад
he literally said it in the video, you can just use a lookup table for the values of n. since n is just a counter and therefore a natural number, you can just cover all the cases of n in one lookup table, no need to implement an atan function yourself.
@SpringySpring04
@SpringySpring04 27 дней назад
Curly braces are just so much nicer to look at tho. (Yes I hate python)
@aria.z124
@aria.z124 27 дней назад
you are the howtobasic of mathematics. lol
@mrshmister173
@mrshmister173 26 дней назад
Finally, a channel does a better explanation of the Cordic algorithm than just "rotating the vector" to approximate a trig function, When rotations require trig functions. Brilliant video.
@hafixion
@hafixion 27 дней назад
Hey there, awesome video, but I did just want to give a pointer. Using a variable called d next to x, y, or phi is generally considered an abuse of notation since it looks closer to an infinitesimal rather than actual variable.
@HenryStrattonFW
@HenryStrattonFW 27 дней назад
This is all well and good. But to any future programmers watching this, please do not use weird Unicode math characters in your code, just use the names of things, like phi, theta, delta, using these symbols will drive anyone that isn’t a heavy math user mad when trying to read your code.
@mad_6519
@mad_6519 12 дней назад
tbh I'd kinda rather learn the meaning of 3 characters and not have big variable names like that. if you need readability, just shove a comment in explaining each symbol
@caiocouto3450
@caiocouto3450 День назад
​@@mad_6519even though, you should avoid it, there are tons of text encoding and this can lead someone to have a pretty ugly and unreadable code if they don't know the right encoding. Use ASCII as long as you can, because it's compatible with most of encodings
@r75shell
@r75shell 27 дней назад
1) I think even if it's what algorithm is really used, there are some fine details about things regarding precision. Because if it shows 6 decimal places, then all of them should be correct. But error in cycle accumulates 2) Your code won't work for angles > 4pi 3) Question in the beginning was how do you calculate those without calculator. But then you pull out from somewhere: some constant which is limit of product (which is also you need to calculate without calculator), and table of 50 arctan, which you also need to calculate. I think more plausible way to calculate sin/cos without calculator to use angle halving formulas, and rotate by pi/2, pi/4, pi/8, pi/16 and so on.
@BryanLu0
@BryanLu0 27 дней назад
The algorithm is called CORDIC, apparently each iteration gives 1 more decimal place of accuracy
@BryanLu0
@BryanLu0 27 дней назад
You can read about it on Wikipedia, under modes of operation, it shows that the part inside the product can be written in the form 1/sqrt(1+2^-n) which is much more manageable to compute.
@BryanLu0
@BryanLu0 27 дней назад
Of course because of the symmetry of sine, you only need to calculate a domain of (0, π/2)
@r75shell
@r75shell 26 дней назад
@@BryanLu0 it won't give you correct 6 decimal places if each term of summation will be calculated up to 6th decimal places.
@user-yb4dz7pl2h
@user-yb4dz7pl2h 12 дней назад
well you can always take the angle mod 4pi
@kamilrichert8446
@kamilrichert8446 27 дней назад
If someone doesn't want to use pow function, the powers of 2 can be achieved by taking 1 and shifting it a few bits (remembering that 2^(-n) is the same as 1/2^(n))
@kakuserankua
@kakuserankua 27 дней назад
That works when multiplying by two because the result is an integer, but dividing one by two results in a floating point number which don't quite lend themselves to the same bitwise shift operation. You can, however, keep 2^n in an integer variable (starting as 1) and for every iteration shift to the left once (which multiplies it by 2), then divide 1 by the result. Also, Python does have an exponentiation operator (double asterisks) and a built-in pow() function not part of the math library. Both would eliminate the need to use the math library (we still need it for arctan however).
@IRedBerryI
@IRedBerryI 27 дней назад
@@kakuserankua was gonna say, why not use 2**n?
@declanmoore
@declanmoore 27 дней назад
@@kakuserankuaif you really want you can subtract n from the exponent to divide by 2^n for floats :)
@luigidabro
@luigidabro 26 дней назад
You try do that on a float.
@kamilrichert8446
@kamilrichert8446 26 дней назад
@@luigidabro that's why I said "remembering that 2(-n) is the same as 1/2^(n)". You can get a float by dividing by an integer
@kingbeauregard
@kingbeauregard 27 дней назад
Didn't understand this, will have to watch again later. But when it comes to approximating sin and cos, I find that this is a good plan: 1) Add or subtract multiples of 2*pi until you're in the range -pi to pi. 2) Map the angle to the first quadrant and remember what that will do to the sign of the final result. 3) If you're dong the sin or cos of an angle greater than pi/4, do the cos or sin of the complementary angle. With those three steps, we've guaranteed that our angle is no more than 0.785 radians. We can Taylor series it and get a good approximation within just a few terms. But we can take it even further: 4) Pre-calculate some sines and cosines of angles like pi/4, pi/8, etc. Save them as constants to whatever arbitrary degree of precision you like. 5) Remember your trig identities, like sin(a+b) = sina*cosb + coa*sinb, and cos(a+b) = cosa*cosb - sina*sinb. With those in mind, suppose you want to calculate sin(3*pi/16). Well, that's sin(pi/8 + pi/16), and if you've precalculated sin(pi/8), then you just have to calculate sin(pi/16) and cos(pi/16) and do the trig identities. And since pi/16 is a little under 0.2, the calculations for sin(pi/16) and cos(pi/16) will converge very quickly.
@IsYitzach
@IsYitzach 26 дней назад
I would have done something similar myself. I don't know if I would have invoked the trig identities, but I would have considered it.
@MelonLord8
@MelonLord8 29 дней назад
Excellent video mate! However, wouldnt a taylor series be easier for a calculator to deal with?
@9remi
@9remi 29 дней назад
yes..
@TheUnqualifiedTutor
@TheUnqualifiedTutor 28 дней назад
A Taylor series is easier for a human because the equation is shorter. However computers/calculators work in a binary number system (base 2). So the multiplication by powers of 2 is very easy for a computer because it just requires all the digits to be shifted (like how multiplication by powers of 10 is done by shifting the digits in our natural base 10 system.) This is why we used the 2^-n in the equations as this is easy to calculate for computers, maybe I should have included this in the video. Thanks
@sepdronseptadron
@sepdronseptadron 27 дней назад
​@@TheUnqualifiedTutor Slight correction/addition, Since we're dealing with floats, we don't shift the digits (as in bit shifting) floats are represented in the form of sign*mantissa*2^exp (a bit simplified, look up IEEE 754 for the whole thing) so when we calculate 2^-n, we just subtract n from the exp part shifting the bits only works for integers
@angeldude101
@angeldude101 27 дней назад
​@@sepdronseptadron As far as I'm concerned, adding and subtracting from the exponent field is basically the same operation as shifting. The only real difference is that for floats it doesn't have the modular behavior that integers have. If you're writing a typical decimal number, you can multiply by 10 by writing a zero, or if you're using scientific notation you can do the same by adding 1 to the exponent. There's a C function called "ldexp" which is basically a shift for floating point numbers, taking an integer and adding it to the float's exponent field. If there was any flat operation to overload the shift operators to, it would be ldexp.
@user-hy8ju1yn5g
@user-hy8ju1yn5g 26 дней назад
​@@angeldude101shifting bits is multiplying/dividing by powers of 2, to add/subtract you can't shift bits in a general case scenario
@trwn87
@trwn87 27 дней назад
Instant subscription. Perfect intro into math amd coding combined for oeople unfamiliar with it. Keep it up!
@cheezey3295
@cheezey3295 28 дней назад
this guys gonna be huge in the future
@simonwillover4175
@simonwillover4175 27 дней назад
8:08 the ** operator also works. i.e: 2**(-n)
@JohnDlugosz
@JohnDlugosz 24 дня назад
From the thumbnail, I thought it would be how modern calculators give symbolic answers for special cases when it recognizes them. IAC, what you described is called the CORDIC algorithm. It needs one iteration per bit of the answer, so 55 iterations seems right as that matches the mantissa of a double precision floating point value. CORDIC _can_ be implemented using only addition, subtraction, bit shifts, and table lookups -- no multiplication or division. Your code doesn't exploit this, and in fact uses division gratuitously. (division being horribly slow even on modern CPUs). This makes it the preferred algorithm for low-end calculators that use 8-bit microcontrollers. For a more capable CPU, the Taylor series takes fewer iterations and will need fewer as the angle is smaller.
@gachanimestudios8348
@gachanimestudios8348 3 дня назад
For me, I would do either of the following: 1) Draw a right angle triangle with an angle of 1. 2) Use the Taylor Series.
@auztenz
@auztenz 28 дней назад
Wow this vedio is very underrated. Excellent subscribed
@LemonCake101
@LemonCake101 27 дней назад
Amazing video, I wish you the best your future efforts, and I can only hope you keep this quality up!
@jansatamme6521
@jansatamme6521 24 дня назад
Helo Lemon man
@LemonCake101
@LemonCake101 24 дня назад
@@jansatamme6521 o/
@sometwo7429
@sometwo7429 27 дней назад
Damn, i didnt know howtobasic was a mathematician 💀
@il_panda1979
@il_panda1979 16 дней назад
thanks a lot. this has been a question at the back of my mind for a lot of time
@jackkalver4644
@jackkalver4644 27 дней назад
In degrees, use angle bisection as approximation. In radians, use the power series.
@yogoc3432
@yogoc3432 28 дней назад
Pretty cool! Though if we don’t have functions for sine and cosine, shouldn’t we also not have functions for arctangent? Or is this actually the way computers calculate it?
@cody8743
@cody8743 28 дней назад
i have no experience, but they are all the same so you can probably just precalculate and store them
@adw1z
@adw1z 27 дней назад
There are many different ways to approximate functions usually, some less computationally costly than others. For example, arctan(x) is the integral from 0 to x of 1/1+u^2 du, and there are so many ways to approximate integrals such as this. The way in which the function is computed depends on the type of computer/calculator you are using
@communismwizard8198
@communismwizard8198 27 дней назад
You’re only taking the arctan of a small set of numbers (negative powers of two), so yes recalculating and storing will work. Whereas for the final trig functions themselves, any number could be the input
@danix30001
@danix30001 27 дней назад
You could have a table of atan(2^-n) that is fixed for every calculation of the sin, cos and tan
@itz_mario.
@itz_mario. 26 дней назад
or simply use binomial expansion of trig functions, define the function, replace the x with the variable name in the function parameter, keep writing as many terms as you can then you will get almost identical results to real values
@Faroshkas
@Faroshkas 27 дней назад
Hello, what app do you use for that blackboard? I thought it looked very cool.
@markthompson2874
@markthompson2874 27 дней назад
I remember in the 70's my dad brought home a TI calculator that had trig functions. Being about 8, I had no idea what they mean but I thought it was interesting that the calculator would take a couple of seconds to handle these functions. I made it my goal in life to be able to use all the functions on a calculator (it also had log as well.) But always wondered why it took so long to calculate sin, now I know.
@arduous222
@arduous222 17 дней назад
Something worth noting here is, you still need to calculate arctan(2^-n) somehow, which is also a trig function. However, given this is very close to 2^-n, you can simply remove arctan for larger order terms, and perhaps hard-code first few terms to further decrease error.
@gky93
@gky93 19 дней назад
You can just use tailor series, it works well with small numbers
@TannerJ07
@TannerJ07 20 дней назад
I love the part where you used wolfram alpha to make you own trigonometric equation
@joshuao4928
@joshuao4928 26 дней назад
Cool video! If you want to make those print statements a little easier to write and more readable, you can put an 'f' before the quotes and use curly brackets to avoid needing the str() functions. As in print(f"sin({θ}) = {y}")
@LaMirah
@LaMirah 25 дней назад
7:54 Python uses the same double-asterisk operator as FORTRAN for exponentiation, so 2ⁿ would be written as `2 ** n`. Math.pow() always returns floating point numbers as a result, whereas the double-star operator will return integer values when appropriate.
@berkberilbayraktar8301
@berkberilbayraktar8301 26 дней назад
this channel is a gem how i just saw this
@zhixinhuang4084
@zhixinhuang4084 22 дня назад
What will you do? A B C or D? A: You can always go to the park B: You can always get to work on time C: You can always make a PERFECT triangle D: You go to Paris every year E: you ALWAYS get what you want
@oxidine2968
@oxidine2968 22 дня назад
E
@wetwillyis_1881
@wetwillyis_1881 26 дней назад
Imagine if a business major sees this. I think they’ll explode. Math majors may be sad, depressed, lonely, and overworked, but at least we can understand shit like this!
@MarIsRandom
@MarIsRandom 4 дня назад
literallly just use taylor’s stratagey which is: sin(x) = x-(x³/3!)+(x⁵/5!)-(x⁷/7!)+(x⁹/9!), etc
@Sudipto911
@Sudipto911 28 дней назад
Great video bruv! Just remember me when you have millions of subscribers😃
@jacksc9855
@jacksc9855 27 дней назад
Acktually the sin is calculated using multiple techniques. Firstly, you only need to calculate the first quarent of the sin. Since other quarent can be calculate using trig. Secondly, look up table is used for common value like π/12, π/6, π/4, π/3, π/2 and more. Thirdly, values are close to 0 are return without calculation. Depend on how accurate the approximation need to be, cordic and Chebyshev polynomials can be use.
@xbia1
@xbia1 26 дней назад
Iteration isn't the fastest method and there's a chance that change never reaches zero because of finite precision. It's better to use a polynomial or rational function. See Computer Approximations by J.F. Hart et al.
@MCPicoli
@MCPicoli 25 дней назад
How do you get rid of the atan() function in the code? We're not supposed to use trig functions here, unless there is a video explaining how to approximate atan() without other trig functions!
@borbzaby
@borbzaby 27 дней назад
Nice video. I didn’t understand everything but it was pretty interesting 👍
@MrBeiragua
@MrBeiragua 13 дней назад
This means that the calculator needs to have a arctan(x) table in the memory or defined somehow for it to calculate sin(x)?
@pranaypallavtripathi2460
@pranaypallavtripathi2460 13 дней назад
why can't we use infinite series expansion of sin, taking the first n terms such that it gives answer within accepted error limit?
@drstrangelove09
@drstrangelove09 27 дней назад
I coded up CORDIC many years ago and was going to implement it in a FPGA but got bogged down with the floating point conversions.
@steamnotstem9047
@steamnotstem9047 19 дней назад
being an actual python programmer, seeing the beginner tactics (like concatenation instead of functional strings or using Unicode characters as variables, or printing instead of returning) made me remind myself that beginners don't need to follow python conventions when their methods work. This was before I noticed you used curly brackets. (no hard feelings, great video)
@kavinbala8885
@kavinbala8885 27 дней назад
i thought it used a parabolic approximation for 0-pi/2. then reflected and rotated that as necessary
@GeorgiMomchilov
@GeorgiMomchilov 26 дней назад
The most underrated chanell on the platform
@guush890
@guush890 22 дня назад
instead of math.pow, you can do 2**-n, no idea if it has the same time complexity tho
@mrtnsnp
@mrtnsnp 26 дней назад
I do get some weird values. π/4 stops after 2 iterations, but ends up at the really wrong value (0.6072529350088812 instead of 0.7071067811865475). And cos(0) is really wrong, after 1 iteration. For π/2 the sin and cos are fine, but understandably the tan value is a bit wonky.
@yigitrefikguzelses291
@yigitrefikguzelses291 27 дней назад
This was really a tutoriel that I watched with curiosity until the end. I liked both the math and computer part very much. My only question is, cos(arctan(1)).cos(arctan(2)).cos(arctan(3))... I think it is not appropriate to calculate it on the computer. Because we used trig again? Also i _think_ you can use Taylor Series of sinx , cosx, or tanx for example: sinx ~ x -x^3/3! + x^5/5! -x^7/7!
@gamingdiamond352
@gamingdiamond352 27 дней назад
cool approximation of sin cos and tan, impressively interesting approach to programming it tho
@BryanLu0
@BryanLu0 27 дней назад
4:51 I understand how the arctan values can be precomputed, but how do you calculate the cosine?
@BryanLu0
@BryanLu0 27 дней назад
Ok, based on the Wikipedia article, the part inside the product can be written as, 1/sqrt(1+2^-n) which is much more manageable to calculate
@caiocouto3450
@caiocouto3450 День назад
the math was pretty awesome, but I'm pretty sure using unicode characters, as theta is not a good programming practice. you should stick as long as you can to ASCII to name variables and functions
@theredstonehive
@theredstonehive 12 дней назад
If you're gonna use a trig function anyway (atan), why not just def trig(theta): return math.sin(theta)
@mathematicalmachinery7934
@mathematicalmachinery7934 26 дней назад
8:03 that's not "to the power of", that's "xor". XOR is a weird binary thingy, if you want "to the power of", use ** instead of ^
@Anife69
@Anife69 23 дня назад
peak cinema of math
@beaverbuoy3011
@beaverbuoy3011 28 дней назад
Very nice!
@jasonnong3305
@jasonnong3305 15 дней назад
Fortunate that people were able to use wolfram alpha back in the day, despite not having a calculator
@georgephilippe4028
@georgephilippe4028 24 дня назад
The whole point of the original CORDIC (published by Jack Volder in 1957ish) was to replace computationally heavy/expensive multiplication and division in old memory-poor computers with additions/subtractions and some table lookups. Logs were also possible. Though based on some obscure 17th Century mathematics it was still a damn impressive algorithm. The code here would not have worked efficiently on early computers and calculators. In fact, it would have defeated the whole point of the original CORDIC. Interesting, though.
@NStripleseven
@NStripleseven 27 дней назад
Why does the algorithm for finding trig functions need you calculate arctan? How does it do that?
@sowndolphin5386
@sowndolphin5386 27 дней назад
dont you use a knife to open another knife's box, or use the seed that an already-grown tree gives, to make another tree, dont question
@hallrules
@hallrules 27 дней назад
either a lookup table (precalculated arctan values by hand probably) or "i used the arctan to find the arctan"
@mariobabic9326
@mariobabic9326 24 дня назад
calculators actually have tables with all the sin values with the maximum precision they need. they dont directly calculate sin() because of perfomance
@simonyi912
@simonyi912 12 дней назад
Confirmed, Wolfram Alpha existed before calculators did.
@billr3053
@billr3053 26 дней назад
Better to pronounce the sign() function as SIGNUM. Not “sine” - because that would confuse it with sin().
@charlieborchardt2066
@charlieborchardt2066 24 дня назад
"But wait, that requires cos and sin." "Aaaarerggghg!!!!!!!!!" Got me dying. 💀 Eggs in a blender.
@user-lu9fg7pc9q
@user-lu9fg7pc9q 25 дней назад
11:00 this jump scared me slightly
@its_aidan
@its_aidan 27 дней назад
this is amazing
@rieder990
@rieder990 26 дней назад
Good video!
@shang_psycho7414
@shang_psycho7414 27 дней назад
I’ve wanted to know this for a while
@user-zc5jz6bh2r
@user-zc5jz6bh2r 27 дней назад
sin(x) = (4x(180 - x)) / (40500 - x (180 - x)) error margin: 0.0016 maximum relative error is less than 1.8% Bhaskara I's sine approximation
@victorien3704
@victorien3704 27 дней назад
Video: How to make a trig function 8:45 : Ok first you have to use a trig function
@jangelbrich7056
@jangelbrich7056 24 дня назад
And I thought for half a century that mathematicians and programmers have zero emotions ...
@prateekjain506
@prateekjain506 День назад
I always thought it used the Taylor series expansion
@notohkae
@notohkae 13 дней назад
i love this
@randospawn7495
@randospawn7495 27 дней назад
I noticed the brackets immediately and was very confused by it, I was like: Why didn't we just do this in c or somethin and why did he do that?
@TheUnqualifiedTutor
@TheUnqualifiedTutor 27 дней назад
You are eagle-eyed. I used python because its easier for beginners imo.
@loulounya
@loulounya 27 дней назад
How does the calculator display it in a form like √2 /2 or 3π/2?
@loulounya
@loulounya 27 дней назад
or even something like (1+√2)/2
@BryanLu0
@BryanLu0 27 дней назад
It's precalculated for some known values
@valcubeto
@valcubeto 23 дня назад
When I saw the brackets I died
@CesarGrossmann
@CesarGrossmann 27 дней назад
Legend says the CORDIC isn't used anymore.
@mr.dragon.purple9209
@mr.dragon.purple9209 23 дня назад
0:15 A
@AbdallahAhmed-qz6uu
@AbdallahAhmed-qz6uu 21 день назад
can't you just use maclaurin's expansion for the first couple terms
@joaocordeiro6539
@joaocordeiro6539 12 дней назад
Imagine being in 1956 without a calculator and having a Python interpreter...xD
@dragoni_penguin
@dragoni_penguin 26 дней назад
now make an infinite precision pi calculator
@ze5os427
@ze5os427 27 дней назад
8:15 or you can use the ** operator
@j7ndominica051
@j7ndominica051 24 дня назад
I had to stop watching a few minutes in because I couldn't focus afraid of a scene with wasted eggs and phone books sudddenly appearing.
@dragoni_penguin
@dragoni_penguin 26 дней назад
imagine not waiting until deltamath was invented
@GeomeTeamCraft
@GeomeTeamCraft 27 дней назад
Why are you so fucking funny lmao
@xniyana9956
@xniyana9956 20 дней назад
Interesting video but I don't like the fact that this algorithm uses a trig function to define other trig functions. I think it's sexier to derive trig functions from lower level math abstractions.
@alguem24
@alguem24 26 дней назад
I really liked the video but the python part made we want to bang my head
@o_s-24
@o_s-24 24 дня назад
Why not use Taylor series approximations?
@stormswindy3013
@stormswindy3013 19 дней назад
the frustrated AUURRGHHH 🥚
@excelmaster2496
@excelmaster2496 28 дней назад
How does a calculate find atan(2^-n)?
@kebien6020
@kebien6020 28 дней назад
Since it only ever uses atan(1/2), atan(1/4), atan(1/8) up to atan(1/2^maxIterations), you can pre-calculate those and stick them into a lookup table
@hallrules
@hallrules 27 дней назад
@@kebien6020 wait how do u precalculate it
@spaghettiking653
@spaghettiking653 27 дней назад
Maybe Maclaurin expansion, then print all the values and write them into a big list
@BryanLu0
@BryanLu0 27 дней назад
​@@hallrulesarctan = integral 1/(x² + 1) dx The question is how do you then take the cosine?
@aaab6054
@aaab6054 27 дней назад
Why use this approach over a Taylor / Maclaurin series?
@Tomyb15
@Tomyb15 27 дней назад
Faster convergence and probably more numerically stable.
@aaab6054
@aaab6054 27 дней назад
I've looked into it now and Taylor / Maclaurin series definitely converge faster(as I suspected), but the CORDIC algorithm he is using is faster for the CPU.
@diogoduarte4097
@diogoduarte4097 27 дней назад
I have subscribed
@rifatbhuiyan2543
@rifatbhuiyan2543 26 дней назад
I thought calculators use Taylor's series. What's wrong with that?
@kelvenlim9283
@kelvenlim9283 26 дней назад
How to find sin of whatever? Use tan. But how do I find the tan of whatever?
@user-vt7kt6ny3o
@user-vt7kt6ny3o 27 дней назад
ok but how to calculate the atan then?
@carultch
@carultch 25 дней назад
You can calculate arctan as an integral of 1/(x^2 + 1) dx. Use Simpson's rule to evaluate this integral, and it can find arctangent.
@noway2831
@noway2831 13 дней назад
Okay, umm, how do you calculate arctan? You've kinda kicked the can down the road by relying on another function. Obviously you could do numerical integration but that would be slow as balls
@Snurklll
@Snurklll 27 дней назад
I actually asked myself 2 days or so ago
@highlightermarca-texto3281
@highlightermarca-texto3281 13 дней назад
But you had to use Wolfram Alpha to kind k...
@lox7182
@lox7182 27 дней назад
why do we need k? can't we just do y/sqrt(x^2+y^2) in the end?
@TheUnqualifiedTutor
@TheUnqualifiedTutor 27 дней назад
Yes, you probably could do. However, a computer/calculator should be as efficient as possible when trying to solve. I believe using a pre-calculated version of K at the start is more efficient.
@honsthebronze
@honsthebronze 24 дня назад
ERORR: division by zero line 7 and 13
@raiden.b6163
@raiden.b6163 28 дней назад
Also me, who knows what sin 60 degrees is and also knows that 60 degree = 1.047 radian. so i just approx sin of 1 radian as sin of 60 degrees which gives me 0.86. I call that good enough and move on. ᕙ(⇀‸↼‶)ᕗ + 1 sub
@TheUnqualifiedTutor
@TheUnqualifiedTutor 27 дней назад
Alpha male moment.
@alex.g7317
@alex.g7317 9 дней назад
Good vid. Have no clue what’s going on.
@krishnachoubey8648
@krishnachoubey8648 27 дней назад
8:13 Could've just used the ** (double-star) operator. if you're worried about any performance issues.... IDGAF HE'S PROGRAMMING IN PYTHON FOR FUCK'S SAKE
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