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How is a light photon affected by Gravity? 

For the Love of Physics
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How is a light photon affected by Gravity? Without invoking General Theory of Relativity, we can use an alternate method to see how the energy of a light photon is affected by gravitational field. Since light has Energy, by virtue of Mass-Energy Equivalence Principle, therefore light has 'mass' due to its Energy. This mass can experience gravity.
When such a photon is moving upwards, it will loose Energy and thus its frequency will reduce.
When light escapes the gravitational pull of a massive star, its frequency is considerably reduced (for visible radiation, it's shifted towards the red end of the spectrum). This phenomenon is known as Gravitational redshift.
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14 июн 2019

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Комментарии : 298   
@FortheLoveofPhysics
@FortheLoveofPhysics 4 года назад
If you liked this video, here are a few more suggestions :) 1) Why pair production cannot occur in vacuum? ► ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-fngJOOiAj5k.html 2) Can you Prove E=MC² ? ►ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-VZEhmWFlrnM.html 3) What is a Black Hole? ►ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-WuYpI3EoCnM.html
@nikhilbhathi3778
@nikhilbhathi3778 4 года назад
Wonderful job sir👌🏻
@aseemanandmishra4598
@aseemanandmishra4598 4 года назад
Sir please answer as u said everything that has energy that has mass than how photon have energy but no mass how it's possible please tell sir
@MM-ci5mb
@MM-ci5mb 3 года назад
answer mi ,, why there is no neutrons in hydrogen atom...and present in its isotopes.
@soumapriyamondal3808
@soumapriyamondal3808 3 года назад
Sir, Can you also discuss advance topics topics like Maxwell-Boltzmann, Fermi-Dirac and Bose-Einstein statistics..
@souvikmandal6491
@souvikmandal6491 Год назад
@@aseemanandmishra4598 according to Einstein E^2 = (M°C^2)^2 + (PC)^2. here p is the momentum and m° is the rest mass... Now for photon the rest mass is zero but still the photon will have energy as putting m° =0 in the equation we get.. E = PC This things may not have mass but can have momentum like photon.. put it simply like a chemistry teacher it's an exception brooo..😂
@girirajsharma3399
@girirajsharma3399 4 года назад
your lectures are extremely convincing, crystal clear and unmatched. You are indeed doing a wonderful service to the Physics Community and I really thank you for these wonderful lectures on behalf of Physics lovers. I feel that you are a born teacher. Keep it up and uploading more and more lectures. Bye the way I could not see your name anywhere. The physics lovers must be quite curious to know about you. So please let us know or introduce yourself through a video and I firmly believe that it will inspire a lot of budding physicists.
@Ihab.A
@Ihab.A 3 года назад
I can't but echo your comment and thank the professor for this marvelous explanation!
@shibhanlalpandita6975
@shibhanlalpandita6975 3 года назад
This is all wrong. If earth pulls an upgoing mass then it won't go up. In religion we have one God. Here many many supposition r taken as true.
@Jamesdavey358
@Jamesdavey358 2 года назад
Youve inspired me mate
@Jamesdavey358
@Jamesdavey358 2 года назад
@@shibhanlalpandita6975 what are you on about
@TheCosmicDestroyer....
@TheCosmicDestroyer.... 2 года назад
I haven't been able to understand the gravitational redshift mathematically before...but thanks to you ,now i know it in a very simplest manner🙏
@akshatsrivastava9396
@akshatsrivastava9396 5 лет назад
I humbly request you to please discuss about the general theory of relativity
@FortheLoveofPhysics
@FortheLoveofPhysics 5 лет назад
All in good time :)
@Just_mind_______
@Just_mind_______ 3 года назад
@@FortheLoveofPhysics Sir I think you were wrong about the formula E=MC² . It's actually wrong . This formula is actually E= MC²+ PC². Any with rest mass we can measure it energy by E= MC² . But anything with out rest mass we can't measure it's mass but we can only measure it's energy so the formula for finding energy of a photon is E= PC . I hope you understand it.
@Just_mind_______
@Just_mind_______ 3 года назад
@@FortheLoveofPhysics And sir it is scientifically proven that light will lose its when it is travelling in space energy because space itself is expanding .
@sankalpshandilya6382
@sankalpshandilya6382 2 года назад
@@Just_mind_______ yes u are right , for a proper treatment we should not comsider a photon as massive partice where its relativistic mass comes due to motion. Rather the real reason for red shift is simply the different rate of flow of time as photon moves away from G-field ,since rate of time flow changes so does the frequency. However for a simpler explanation sir has Incorporated the effect into the relativistic energy E = /gamma m c^2 where / gamma takes care of everything and then he has defined mass as /gamma into rest mass. Since rest mass is zero and /gamma is infinity the moving mass may still be finitr and thus the trick works
@debtanupatra3385
@debtanupatra3385 2 года назад
@@sankalpshandilya6382 so you are dealing with 0/0. Photons energy comes from relativistic momentum. Nothing to do with rest mass...and its 0.
@himanshusinha2161
@himanshusinha2161 3 года назад
Wow…. Speechless ! Amazing to see how you have been explaining complex topics in such lucid manner 🙏
@JenFoxBot
@JenFoxBot 4 года назад
Very clear math and excellent commentary along the way. Thank you!!
@salu30000
@salu30000 4 года назад
Thank you bro! Appreciate it 🤟 i was looking for this topic explanation literally everywhere
@biswajitray8420
@biswajitray8420 4 года назад
You perceive physics the way it is projected in your mind. Tx for ur fantastic explaination
@tkzsfen
@tkzsfen Год назад
Straight to the point, excellent video!
@joserobing661
@joserobing661 4 месяца назад
Beautiful presentation. Thanks.
@jamesholbert8127
@jamesholbert8127 4 года назад
Very clear presentation, Thank You.
@promitbiswas4771
@promitbiswas4771 3 года назад
thank you so much sir.you are just making stuffs too much easy and realizable
@donol4828
@donol4828 4 года назад
Excellent! Thank you!
@markgoretsky766
@markgoretsky766 2 года назад
Lucid, accessible presentation! Thanks
@ASEEMKUMARSPHYSICSFORIITJEE
Thanks for such great efforts.
@saftheartist6137
@saftheartist6137 24 дня назад
Thank you for this educational lecture!
@augijyotbali2131
@augijyotbali2131 3 года назад
Wow amazing , world needs more of you sir.
@vibha4397
@vibha4397 4 года назад
this video was sO helpful, im doing a project and this video is frickin beautiful, ty
@praptiupadhayay5305
@praptiupadhayay5305 3 года назад
What is your topic name? I am also looking for quantum mechanics project.
@manjitpalahe4129
@manjitpalahe4129 2 года назад
Superb made much easy to understand a complex topic
@babulsy6460
@babulsy6460 11 месяцев назад
Beautifully explained, 👍
@naginabahadurofficial6923
@naginabahadurofficial6923 3 года назад
It's crazy I came here because I wanted to listen to John Mayer's Gravity and gave this video a go. Not at all regretted clicking this.
@niteeshmishra388
@niteeshmishra388 5 лет назад
very lucid explanation. excellent
@nnfefe9451
@nnfefe9451 Год назад
You are a great teacher.
@johneonas6628
@johneonas6628 3 года назад
Thank you very much.
@mushfiqurrahmanshishir8055
@mushfiqurrahmanshishir8055 3 года назад
This is a man, who know what he does Lots of love 💗
@Johncowk
@Johncowk 2 года назад
Very clear video, thanks. Cheers from France.
@kutbuddinrangwala1039
@kutbuddinrangwala1039 2 года назад
thank u i learn a lot through yur videos
@aravindrpillai
@aravindrpillai Год назад
What a nice explanation.. 👏
@tantaiphan9153
@tantaiphan9153 3 года назад
It helped me a lot. Thank you.
@TheNishantGi
@TheNishantGi 4 года назад
Very nice explanation !!
@maheshnaik561
@maheshnaik561 2 года назад
You explain very well sir. Thank you
@Komal-1401
@Komal-1401 Год назад
Sir your lectures are extremely good. such a nice explanation of the things. Sir keep uploading the videos🤩
@thechemistrysection552
@thechemistrysection552 4 года назад
Perfect crystal clear explanation in a simple and sophisticated way.
@saturnus8187
@saturnus8187 4 года назад
The Chemistry Section you know that simple and sophisticated are opposites yeah?
@lilsavage6807
@lilsavage6807 Год назад
Nice one , easy to learn
@siddharthaghosh2150
@siddharthaghosh2150 3 года назад
Thanks verry good example
@tapashnandy3594
@tapashnandy3594 Год назад
Excellent 👍
@pg7703
@pg7703 6 месяцев назад
Thank-you so much
@OnlySuperHitMoviesShorts
@OnlySuperHitMoviesShorts 2 года назад
mind blowing👌🏻♥️
@sudhakarankarunakaran6932
@sudhakarankarunakaran6932 2 года назад
Wonderful.. Summarised this at the end stating the difference between Doppler red shift with gravitational red shift. 👍☘️☘️👍
@pg7703
@pg7703 6 месяцев назад
Thank-you so much...
@pingu8394
@pingu8394 2 года назад
Sir...your lecture are phenomenal and in addition to that, your handwriting is incredibly neat 🌸
@srikanthtupurani6316
@srikanthtupurani6316 3 года назад
Nice explanation. Very important calculation every astrophysicist has to do. Light we detect from faraway galaxies helps in predicting things like Blackholes etc.
@sashwatsethuraman6300
@sashwatsethuraman6300 3 года назад
Thank you so much sir!!
@peterfred445
@peterfred445 3 года назад
love where you're coming from man
@jameslawrence6068
@jameslawrence6068 5 лет назад
Love your videos! Love from South Africa
@FortheLoveofPhysics
@FortheLoveofPhysics 5 лет назад
Thank you :)
@nagadurgarajuadaka
@nagadurgarajuadaka 3 года назад
I love your voice and your teaching........
@guukumar8851
@guukumar8851 3 года назад
Best explanation
@Ecstatic_photon
@Ecstatic_photon 4 года назад
Very clear explanation .thanks sir
@life42theuniverse
@life42theuniverse 4 года назад
thank you
@sweet_girl269
@sweet_girl269 2 года назад
sir, Your explanation of this topic is awesome 👏,
@ishaankulkarni49
@ishaankulkarni49 3 года назад
great lecture.
@surendrakverma555
@surendrakverma555 4 года назад
Excellent lecture 👌👌👏👌👌👏👌👍😀😊😊👍👍👍👍👍👍👍👍
@omarmohamad5499
@omarmohamad5499 4 года назад
It's Really amazing
@siddharthaghosh2150
@siddharthaghosh2150 3 года назад
Too Good
@mohammadraiz4495
@mohammadraiz4495 4 года назад
Amazing Teacher👏👏👏👏👏👏👏👏👏👏👏👏
@swarnendupachal2579
@swarnendupachal2579 3 года назад
Wowwwwwwww , thank you very much sir...
@60pluscrazy
@60pluscrazy 3 года назад
Excellent explanation 👌
@sidds2004
@sidds2004 2 года назад
Too good
@interstellarconveyance4865
@interstellarconveyance4865 3 года назад
That was AMAZING! Your second interpretation of red shift was wonderful. Can we interpret the final dispersion of red shift by removing Plank's constant and substitute Plank's with another formula? Perhaps Mass to energy, -E+Kv=0/P -G+em? What distance does the last photon particle travel and what is the final principle of dispersion? Are angular and rotational kinematics of photaic mass considered in the gravitational model? Can we measure the final dispersion pattern from an absorption plate and reverse calculate the primary Mass of the 0 point? Thank you! 🙏💖🌱🌍🌱
@amirulislam9595
@amirulislam9595 4 года назад
Thanks sir
@user-rg5qr6zn9m
@user-rg5qr6zn9m 4 года назад
Thanks for you
@mrfinesse
@mrfinesse 4 года назад
Thanks very much for another great video. What happens to the energy that the photon loses? Where does it go? The star is not a BH. Who gains the energy the photon loses?
@itscrawford
@itscrawford 4 года назад
Im relatively new to this concept but its crystal clear to me! Great video!...but it raises a new question - what happens to photons as they ENTER a planets gravitational feild and if the photon has no mass is the gravitational redshift just an example of time's effect on the photon?
@anandbhatt1795
@anandbhatt1795 3 года назад
You used the term “effective mass” for a photon based on its frequency. I think that is an excellent way to represent a massless entity. Is there a theoretical minima and maxima frequency for a photon ? Thanks. Your videos are clear and therefore riveting. Anand
@sushreesatapathy6173
@sushreesatapathy6173 4 года назад
Thnk u
@ImUpsetThatYouStoleMyUsername
@ImUpsetThatYouStoleMyUsername 4 года назад
Can you actually solve for average redshift ? I'm curious to see how many nm shift occurs as a photon leaves earth and/or the sun
@FoamyDave
@FoamyDave Год назад
Thank you for the very practical explanation. This has been a question I've had for a while and you answered it in a way that I can grasp.
@manzoorhussain6523
@manzoorhussain6523 4 года назад
Thx
@MrCorniere1
@MrCorniere1 7 месяцев назад
Excellent demonstration. It has been said that e=mc2 formula does not apply to the photon due to the presence of mass m but to everything else.
@irwinvillalobos2837
@irwinvillalobos2837 3 года назад
I read that gH/c^2 is an approximation for the relative change of the frequency of the photon in Earth's surface, where H is the difference in altitude and g is Earth's surface acceleration. Do you know how can I prove that this is a good approximation? I ask that because I get very different results if I proceed as you explain in this video.
@martin.monfils
@martin.monfils 2 года назад
Thank you for your interesting & clear lecture! I just wondered, so all incoming light observed at the surface of the earth is slightly blue shifted?
@TheCosmicDestroyer....
@TheCosmicDestroyer.... 2 года назад
Sir,if there is a shift in frequency then what happens to the energy lost by a photon during its escape...is energy conservation law doesn't hold up here....?
@ROHANDATAR1
@ROHANDATAR1 3 года назад
Light bend around sources with high mass due to gravity. This is not because the mass pulls on the photons directly, but instead because the mass warps the space.
@prabhakerpandey5905
@prabhakerpandey5905 3 года назад
big fan of your work sir.............. but I think i have one more explanation that photons have the influence of gravity on it .... for this first consider the equation relativistic energy from special relativity i.e E^2=(M'C^2)^2 + p^2c^2 ... where m' is the rest mass of the particle (0 in the case of a photon). Hence this reduces to E=pc. Einstein also introduced the concept of relativistic mass (and the related mass-energy equivalence) in the same paper; we can write it as: mc^2=pc m=relativistic mass, hence: m=p/c in simpler word a photon does have relativistic mass proportional to is momemtum. (II) = De Broglie's relation, an early result of quantum theory (specifically wave-particle duality), states that : λ=h/p ; h = planks constant = 6.62607*10^-34 m^2 kg/s we can write is as: p=h/λ hence combining this with equation of relativistic energy; we get: E/c^2=m=p/c=h/λc; m= relativistic mass. so form this we can conclude that , photons have 'mass' inversely proportional to their wavelength! Then simply by Newton's theory of gravity, they have gravitational influence. I hope that you would consider it sir thank you......
@kushagrakinra4505
@kushagrakinra4505 9 дней назад
Sir if frequency changes constantly as we go up due energy conservation, then mass of photon should also change, then how can we calculate it directly by energy conservation
@priyamshukla3741
@priyamshukla3741 3 года назад
hard..👌💝
@siddharthaghosh2150
@siddharthaghosh2150 3 года назад
We need more in general theory of relativity by simple example
@onderozenc4470
@onderozenc4470 3 года назад
Bravo, the first part of the formula was tested in MIT by the gamma ray photons experiencing red shift through a vertical duct. The second part refers to the black holes' thermal radiation.
@minimalisttraveler9337
@minimalisttraveler9337 4 года назад
How do you know if you're observing gravitational redshift or redshift caused by motion?
@HighEnergyScientist
@HighEnergyScientist 3 года назад
Bro E=mc^2 is applicable for stationary objects , how you can applied for photons . For photons E = √(m^2C^4+p^2c^2) . Please reply
@shrikant8446
@shrikant8446 3 года назад
Exactly and instead of taking E=mc^2 we should take E=pc as mass of proton is zero
@asce4999
@asce4999 2 года назад
*photon And photon’s rest mass is zero i.e m^2c^4 term in E^2 is zero leaving E= pc
@enricobelvisi3880
@enricobelvisi3880 2 года назад
@@asce4999 momentum of a photon should be p=mc, so in the end you still have E =mc^2, where m is not the rest mass as he said in the video, but the one which cames from his energy content
@waqasahmad5887
@waqasahmad5887 3 года назад
good.. change in frequency has effect on energy (hf`=E`) SO further change will effect mass and speed of light (E`=m`c^2) so mass has to change itself to keep speed of light constant..then tell me is mass infinitly large enough to cause the light not to escape from the blackhole..what will be the speed of light against blackholes surface .is it constant or zero? rediculs
@sohamkulkarni5922
@sohamkulkarni5922 4 года назад
Hello sir... But the ball is initially at rest. So v equals to zero and so does kinetic energy. So how kinetic energy of ball at below is half of mc squared?
@firozKhan-wo8dg
@firozKhan-wo8dg 3 года назад
Can u advice me best book for GR... Like zettli and Griffith for QM.... And Leonard suskind is better for special theory or some one best than this
@AwaisKhan-uw9en
@AwaisKhan-uw9en 4 года назад
zbardast...
@hitenderkumar7922
@hitenderkumar7922 Год назад
there are two problems. first is can you apply mass energy equivalence on photon? and second is the quanta energy which we are taking hv here can be compared with classical potential energy? This could rather be explained using lorentz transformation on energy.
@borntolive2097
@borntolive2097 3 года назад
Can the last derived equation be used for black holes?
@hizbullahshah1776
@hizbullahshah1776 2 года назад
Sir discuss general theory of relativity
@LesCish
@LesCish 11 месяцев назад
Great explainer. Now I understand how a light photon is affected by gravity. But what about a heavy photon?
@mohsinali-dh4ln
@mohsinali-dh4ln 3 года назад
I find an another teacher❤
@sushobhitjakhmolaAdmin
@sushobhitjakhmolaAdmin 3 года назад
Okay, so if we apply this to a light photon, trying to escape black hole's gravity, what would be the case? ? As u said,speed won't change but freq would decrease. So if freq decreases, wavelength must increase. Concluding that momentum of individual photon would decrease? ( P=H/lambda) where p=mc So basically mass of each photon decreases so maybe the mass of photon tends to zero and wavelength tends to infinity. So maybe light escapes but it's mass is so small and it loses the characteristics of light
@vishalmishra4081
@vishalmishra4081 12 дней назад
sir if frequency decreases ,but red has higher frequency and hence high energy.Then why red shift
@69532
@69532 3 года назад
Sir please kindly let me know as mass of photon is given by m=hv/c^2 ...h & c are constants, since we have range of frequencies that is we have electrospectrum different wavelengths and frequencies does it mean different photons associated with different frequencies have different MASS PLEASE ANSWER.
@michaeldodd3563
@michaeldodd3563 Год назад
Can you explain more about why it is you think light can completely escape the gravity of a star? You seem to suggest that there is asymptotically flat space, which I’m not convinced there is. Arguendo, assuming light could escape the gravity of the emitting star, would that light not then be affected by the gravitational mass of everything it encounters between us and the star, thus, shifting it even further red?
@MM-ci5mb
@MM-ci5mb 3 года назад
answer mi ..why there is no neutrons in hydrogen atom , and present in its isotope ????
@rijuwanahaque8054
@rijuwanahaque8054 2 года назад
Wow
@nadeemsaleem
@nadeemsaleem Год назад
Hlo Dear Sir How are you I hope you will be fine dear Your every topic is well explained Please Sir make videos on LASER subject
@masoomladkaaproudvegan2876
@masoomladkaaproudvegan2876 2 года назад
can you pls teach general theory of relativity
@Write_with_me_gknotes
@Write_with_me_gknotes 4 года назад
What actually bends...mass or energy??
@dianabenobo
@dianabenobo 3 года назад
What if everything is made out of light? Would gravity be generated by light displacing/interfering with/energising light at the speed of light squared?
@paulmanusu6052
@paulmanusu6052 4 года назад
Im not sure if anyone else got confused by this. But he is comparing point A) half mv squared vs point B) mgh. The kinetic at the beginning vs the potential at its highest point. What I don't understand is from rest the velocity would be 0 therefore making the kinetic energy 0. This equation only works if the object is already in motion right?
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