How to calculate LTE Data rate Speed ?| Throughput calculation in LTE

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How to calculate LTE Data rate Speed ?| Throughput calculation in LTE
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16 окт 2024

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Комментарии : 90

@sukumarane2302 3 года назад

Explained clearly .Any one can follow easily .nice ! Wonderful ! Expecting more videos from you . Thank you ,sir 👍👍 Expecting similar videos for data rate calculations for 2g,3g and 5 G

@AnandTechnoSolutions 3 года назад

Thanks...5g calculation is uploaded

@israrahmad96 7 лет назад

When I was learning this in my training it was looking very boring and complicated. Your way of teaching is so easy and simple... Thanks a lot sir...

@AnandTechnoSolutions 7 лет назад

Thanks Israr..Thanks for your complement..please comment if i am missing anything and I will try to improve that area...also polease suggest improveplease suggest any new topic

@israrahmad96 7 лет назад

LTE/UMTS/GSM interoperability means selction/reselction and Handover priorities and criterias will be a very useful lecture . Your way of teaching is so simple and easy

@AnandTechnoSolutions 7 лет назад

Sure i will try to cover this section

@jaythakur2137 6 лет назад

400*25% != 300. please correct it. As 25% resources used for signalling. So you should be multiplying with remaining once. means 400*75% = 300. I hope this help.

@AnandTechnoSolutions 6 лет назад

Thanks Jay .. for your suggestioj

@rajendra259 4 года назад

Wonderful Explanation, Really appreciate you. A person with a basic knowledge can also understand easily from your videos. Thank you

@SharpKnife523 Год назад

Great. very easy explanation.

@mayankchandla1502 6 лет назад

Thanks for the video. Which specification provides the no. of RBs available for each bandwidth ?

@gabrieldelacruz7100 6 лет назад

Mayank Chandla TS 36.211

@balkrishnasrivastava9258 4 года назад

Super sir, keep continuing to spread knowledge to us Thanks

@AnandTechnoSolutions 4 года назад

Thanks man

@malakondaiah1512 4 года назад

Magnificent class ji

@PankajSharma-pe2ws 2 года назад

Wow, Very nicely Explained...Thanks buddy

@aquibali772 6 лет назад

Thanks for Video, But I think 100800 bits/1ms !=100.8 Mbps, when we used right convergence of Bits to Mega bits than need to divide by 1024, By using this data rate will be 96.13 Mbps, & for 4x4 Mimo It will be 288.39 effective data rate not 302 Mbps.

@AnandTechnoSolutions 6 лет назад

Yes correct...its only for understanding purpose.....so taken just approx value

@KidsNehaTalks 5 лет назад

@@AnandTechnoSolutions 100800 bits/1ms =100800*1000 bits/s (here suppose to convert 1ms to sec,so 1ms=0.001=10^-3 sec) 100.8 *10^6 bits/sec =100.8Mbps

@Koimith 2 года назад

You explanation was excellent, thank you. 👍

@AnandTechnoSolutions 2 года назад

Thanks

@klinsmannhotspur9792 6 лет назад

Hi Anand, could I ask you a question? In 4G LTE, the baseband signal is actually at low frequency(a few khz?), but how come it is that low? Say for example at DL, the through put is around 300Mbps( for 20MHz , 64QAM and 4x4 MIMO), meaning that 300Mbps will arrive at the mobile receiver end(assume only 1 user is using all the available RB or 1200 sub carriers), and after all the require process, the baseband signal(bits 0 1) is retrieved but at very low frequency. So now for 1 sec, 300Mbps is waiting the mobile to process, but if the baseband signal is slow, it will take a long time to just proceed that 1 sec of information. How could that possible? Could you please briefly answer my question? Many thanks.

@AnandTechnoSolutions 6 лет назад

as per my understanding..The use of "high" frequencies has nothing to do with energy. The main purpose of using a "carrier" is to transmit multiple signals of smaller bandwidth over a channel that has much larger bandwidth. though the fact that higher frequencies have shorter wavelengths and therefore can be transmitted more effectively with short antennas is also important for many applications.In Modulation and antenna propagation, the adsorption of the wave makes you to need more energy to transmit.

@rbm004 6 лет назад

Excellent, simple and to the point!

@AnandTechnoSolutions 6 лет назад

Thanks

@muhudiinyusuf6900 6 лет назад

thanks so much, really you provided a very good information for calculation of PRB.

@debasisbadal1 3 года назад

Hello Sir, Can you come with a video where LTE throughput and debugging is explained involving all layers . ?

@ApricityTS 6 лет назад

This is best and simple explanation of LTE-FS

@AnandTechnoSolutions 6 лет назад

Thanks..

@pranshudwivedi2724 6 лет назад

bahut hi badhiya samjhaya aapne..

@AnandTechnoSolutions 6 лет назад

Thnaks Bro....

@lakshanrathnakumara9158 Год назад

Thank you very much

@AnandTechnoSolutions Год назад

Thanks

@Daily_Cric 3 года назад

excellent bro....👍

@gototcm 6 лет назад

Great explanation. Where did you get for example, 20 MHz=100 RBs?

@AnandTechnoSolutions 6 лет назад

It is for your understanding...same way you can calculate for 10 MHz or 15 Mhz

@evensondlovu4982 6 лет назад

1RE corresponds to 15kHz channel and in 1RB there are 12 such channels so 1RB corresponds to 180kHz. In a 20MHz channel, 2MHz is used as guard band leaving 18MHz for transmissions. This therefore means the number of RBs in 20MHz (Effectively 18MHz) = 18MHz/180kHz = 18000000/180000 =100 I hope you got it.

@AnandTechnoSolutions 6 лет назад

Yes..got it

@evensondlovu4982 6 лет назад

I am sure you knew this Anand, your video is great. I was just explaining to Tom M.

@gototcm 6 лет назад

Thanks. Now I understand.

@3100637 6 лет назад

Thanks a lot for your explanantion!!!

@AnandTechnoSolutions 6 лет назад

Thanks Bro

@ssasidhar75 6 лет назад

Excellent explanation

@AnandTechnoSolutions 6 лет назад

Thanks

@veerojumanasa7948 6 лет назад

thnks for clear explanation

@AnandTechnoSolutions 6 лет назад

Thanks manasa

@klinsmannhotspur9792 6 лет назад

Very good explanation

@AnandTechnoSolutions 6 лет назад

Thanks klinsmann

@klinsmannhotspur9792 6 лет назад

Could you do a video on how OFDMA works with MIMO in LTE?

@AnandTechnoSolutions 6 лет назад

@@klinsmannhotspur9792 sure..i will try

@klinsmannhotspur9792 6 лет назад

In particular for DL after IFFT is applied to the subcarrier signals.. thanks

@panditram9046 5 лет назад

Thanks for clearly explained bro...........

@AnandTechnoSolutions 5 лет назад

Thanks so much

@Rakeshkumar-kp2lb 4 года назад

Sir please send the brief throughput calculation of 2G and 3G

@jeff830103 4 года назад

thank you help me a lot!

@varakumarisamudrala9763 6 лет назад

excellent

@rajendrapdsharma1120 6 лет назад

Excellent

@moulanamohammadh6894 6 лет назад

Brother excellent.

@AnandTechnoSolutions 6 лет назад

Thanks Bro

@moulanamohammadh6894 6 лет назад

Excellent explanation bhai

@tanjirahmed6643 6 лет назад

very nice....

@AnandTechnoSolutions 6 лет назад

Thanks

@kamalhassanwarsi3799 6 лет назад

Great

@AnandTechnoSolutions 6 лет назад

thanks

@SheysonSanchezSuarez 5 лет назад

excellent thanks

@AnandTechnoSolutions 5 лет назад

Thanks

@vikramgarg3134 5 лет назад

super explanation

@AnandTechnoSolutions 5 лет назад

Thanks

@swarnban8634 Год назад

Overheads will be added bcoz headers from upper layers will be added, Guard band will be there thats why.

@kumarsunder8750 7 лет назад

super lecture

@AnandTechnoSolutions 7 лет назад

Thanks Kumar

@gaurishkadam3839 4 года назад

Hello, at 8:05 why do you multiply by 2? I understand that there are 2 slots in a subframe. But 20MHz has only 100 RB. 100 RB = 100 * (12 subcarriers X 7 symbols). How can you multiply again by 2 here? 1 RB = 1 slot (12 SC X 7 symbols). Can someone clear my doubt?

@MITHUNTV 4 года назад

Network always allocates UE 1 subframe in DL which is called a TTI. Since there are 2 SFs in a TTI we have to multiply by 2.

@gaurishkadam3839 4 года назад

@@MITHUNTV Right. It makes more sense to me, if further down the video we convert 100 * (12 x 7) per 0.5ms, to 100 * (12 * 7) * 2 per 1ms

@avisek0101 5 лет назад

Overheading is done in PDCP using ROHC

@Lawrencearjun 6 лет назад

THANK U

@rishika.m9784 4 года назад

1frame= 1prb??

@durgeshpal1439 3 года назад

Create calculation for peak data rate..

@Heavygunner1 6 лет назад

Why 32 QAM not used

@sunnyteki 5 лет назад

as the system is binary[ real n imaginary]. in a quadrant of space, only 2 power x bits can only be represented using real & imaginary fields.

@hordevran 7 лет назад

Why you say 0 as gero? :D

@AnandTechnoSolutions 7 лет назад

My engish pronunciation is not clear🤔 I am working on This and i will come with new quality video......Thanks...Please SUBSCRIBE if it is helpful...

@hordevran 7 лет назад

No problem, your english is good and video brilliant, just this one word was funny and at the beginning i thought it has some special secret meaning :D.

@AnandTechnoSolutions 7 лет назад

Thanks BRO 😃